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**STARTERS**Find the equations of the following graphs: y = (x+4)(x-2) y = x2 + 2**Note 7: Cubics - Basic**y = x3 This “central point” is called a “point of inflexion”**Any functions of the basic cubic are treated the same as the**shifts in the parabola. Examples: Graph y = x3 + 4 y = x3 + 4 y-intercept is 4**Examples: Graph y = (x – 5)3 + 2**Vertex (5, 2) y = (x - 5)3 + 2**Graph the following cubics**y = x3 + 1 y = (x – 2)3 y = -x3y = (x + 1)3 – 2 y = x3– 3 y = (x – 3)3