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Module 5 Higher Tier Paper 2 Calculator Specimen Paper (non-coursework) 2009 Mock exam 2009 I hr 15mins

Module 5 Higher Tier Paper 2 Calculator Specimen Paper (non-coursework) 2009 Mock exam 2009 I hr 15mins. 1. The diagram shows a solid made from centimetre cubes. On the grid below, draw the elevation of this solid, from the direction shown by the arrow. 2 Marks.

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Module 5 Higher Tier Paper 2 Calculator Specimen Paper (non-coursework) 2009 Mock exam 2009 I hr 15mins

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  1. Module 5 Higher Tier Paper 2 Calculator Specimen Paper (non-coursework) 2009 Mock exam 2009 I hr 15mins

  2. 1. The diagram shows a solid made from centimetre cubes. On the grid below, draw the elevation of this solid, from the direction shown by the arrow. 2 Marks

  3. 2. The graph shows a coach journey. (a) For which part of the journey is the coach travelling at the fastest speed? Answer: C to D 1 Mark (b) What is the speed of the coach from C to D? Give your answer in kilometres per hour Travels 40km in 30 min Answer: 80km/hr 2 Marks

  4. 3. The diagram shows a shape made from rectangles. A C B Find the area of the shape. State the units of your answer. Area of A: 6.2 x 3.5 = 21.7 Area of B: 6.2 x 3.5 = 21.7 Area of C: (6.2 – 2.4) x 3 = 11.4 Total area: 21.7 + 21.7 + 11.4 = 54.8 cm3 4 Marks

  5. 4. Solve these equations. (a) 2 ( y + 3 ) = 22 (b) 6z + 9 = 1 - 2z Add 2z to both sides 2y + 6 = 22 8z + 9 = 1 2y = 16 Subtract 9 from both sides y = 8 8z = -8 z = -1 3 Marks 3 Marks

  6. 5. The diagram shows a quadrilateral . Find the value of p p + 20 + 2p + p + p + 30 = 360 5p + 50 = 360 5p = 310 4 marks p = 62º

  7. 6. Calculate the size of the exterior angle of a regular pentagon. The sum of the exterior angles of a regular polygon add up to 360º 360 ÷ 5 = 72º 2 Marks (b) Explain why you cannot have a regular polygon with an exterior angle of 50º 360 ÷ 50 does not give a whole number answer 2 Marks

  8. 7. The diagram shows a walled garden ABCD. Using ruler and compass only, construct the perpendicular bisector of AB 2 Marks S (b) A statue stands in the garden. The statue is equidistant from A and B. It is also equidistant from the walls AD and CD. Using a ruler and compass only, mark the position of the statue. Label it S. 2 Marks

  9. 8. A solution of the equation x3 - 5x = 60 lies between x = 4 and x = 5. Use trial and improvement to find this solution. Give your answer to one decimal place. 4.3 58 too small too big 4.4 63.18 4.35 60.56 too big 4.33 59 .53 too small Answer: x = 4.3 (1dp) 3 Marks

  10. The diagram shows a metal ring. The inner diameter of the ring is 8.4cm and the outer diameter is 15.6cm. Area of a circle is π x r x r Calculate the area of the ring. Give your answer to an appropriate degree of accuracy. Area of inner circle: π x 4.22 = 55.4 Area to outer circle: π x 7.82 = 191.1 Area of ring: 191.1 - 55.4 = 135.7 cm2 =136cm2 (3sf) 5 Marks

  11. 10. Each of these graphs represents a different equation. Match each graph to its equation y = x3 - 2 is graph (b) x + y = 3 is graph (c) y = 5 - x2 is graph (d) y = 2x + 4 is graph B D C A 4 Marks

  12. 11. Solve the following equation Multiply both sides by 10 3x - 4 + 2x - 6 = 35 5x - 10 = 35 5x = 45 x = 9 4 marks

  13. w, x, y and z represent lengths. Match each expression, with an arrow, to the type of formula it represents. 3 Marks

  14. 13. (a) In the diagram, O is the centre of the circle. Work out the value of x Answer: 104º 1 Mark (b) Write down the value of y Answer: 47º 1 Mark

  15. 13(c) work out the value of z. Give a reason for your answer. Answer: - 111º Reason: Opposite angles in a cyclic quadrilateral add up to 180º 2 Marks

  16. 14. Make x the subject of the formula: Multiply both sides by x + 3 y ( x + 3) = 2x - 4 xy + 3y = 2x - 4 3y + 4 = 2x - xy Factorise RHS 3y + 4 = x (2 - y ) 4Marks

  17. 15. A ship leaves port and sails on a bearing of 130º for 3 km. The ship then changes course and sails on a bearing of 240º for 7km. 70º Calculate the distance of the ship from the port (marked “a” on the diagram) Using the cosine rule: a2 = 32 + 72 – 2x3x7xCos70º a2 = 43.64 5 Marks a = 6.6km

  18. A plant pot is in the shape of a frustum of a cone. The plant pot has a base diameter of 10cm and a top diameter of 18cm. The height of the plant pot is 15cm. Sandra has a 2 litre bag of compost. Will she have enough compost to fill the plant pot? You MUST show all your working. Volume of a cone:- x π x r x r x h 1 litre = 1000cm3 1/3 x π x 92 x 27 = 2290.22 1/3 x π x 52 x 12 = 314.16 2290.22 – 314.16 = 1976cm3 = 1.976 litres 4 Marks Yes she will have enough compost

  19. 17. Find the x-coordinates of the points of intersection of the line y =2x -1 and the circle x2 + y2 = 27 7 Marks

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