1 / 45

Chemistry Chapter 7 – Chemical Quantities

Chemistry Chapter 7 – Chemical Quantities. Section 7.1 The Mole: A Measurement of Matter. Objectives: Describe how Avogadro’s number is related to a mole of any substance Calculate the mass of a mole of any substance. Representative Particles. Types of representative particles:

rlake
Download Presentation

Chemistry Chapter 7 – Chemical Quantities

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. ChemistryChapter 7 – Chemical Quantities

  2. Section 7.1 The Mole: A Measurement of Matter • Objectives: • Describe how Avogadro’s number is related to a mole of any substance • Calculate the mass of a mole of any substance

  3. Representative Particles • Types of representative particles: • Atoms (Single element) • Molecules (Covalent/Molecular Compound) • Formula Units (Ionic Compound) • Ions (+/- charge)

  4. Ex. Label each representative particle. • KF formula unit • CO2 molecule • He atom • SO42- ion • Ba(OH)2 formula unit • F2 molecule • H2O molecule • H3O+ ion

  5. What Is a Mole? • Mole(mol) – a quantity which represents 6.02 x 1023 representative particles of any given substance. • Avogadro’s Number – 6.02 x 1023 or 1 mole • The term “mol” is similar to: dozen, ream, bushel • Representative particle – the species present in a substance: atoms, molecules, formula units, ions.

  6. How large is a mol? • A mol of golf balls: • lined up would go to the sun and back ~1 billion times (dist to sun is ~92,000,000 miles) • A mol of animal moles: • spread over the Earth would make a layer 8 million animal moles thick

  7. Conversion Factors • 1 mole = 6.02 x 1023 atoms • 1 mole = 6.02 x 1023 molecules • 1 mole = 6.02 x 1023 formula units • 1 mole = 6.02 x 1023 ions

  8. Ex: How many atoms are there in 1.14 mol Ag? 1.14 mole Ag x 6.02 x 1023 atoms = 6.8628 x 1023 atoms Ag 1 mole Ag 6.86 x 1023 atoms Ag

  9. Ex: How many moles of magnesium is 1.25 x 1023 atoms of magnesium? 1.25 x 1023 atom Mg x 1 mole Mg = 0.207641196 mol Mg 6.02 x 1023 atoms Mg 0.208 moles Mg

  10. Ex: How many molecules is 0.360 mol of water? 0.360 mole H2O x 6.02 x 1023 molecules = 2.1672 x 1023 molecules H2O 1 mole H2O 2.17 x 1023 molecules H2O

  11. Ex: How many moles of NO2 are there in 4.65 x 1024 molecules of NO2? 4.65 x 1024 molecules NO2 x 1 mole NO2= 7.724 mol NO2 6.02 x 1023 molecules NO2 7.72 moles NO2

  12. Caution! • Be careful when being asked to convert moles of a compound into atoms! • We will need to multiply the final answer by the number of atoms in the compound. MOLE CROSSING

  13. Ex: How many atoms are there in 1.14 mol SO3? 1.14 mol x 6.02 x 1023 molecules x 4 atoms = 2.74512 x 1024 atoms 1 mole 1 molecule 2.75 x 1024 atoms

  14. Ex: How many atoms are in 2.12 mol of propane (C3H8)? 2.12 mol x 6.02 x 1023 molecules x 11 atoms = 1.403864 x 1025 atoms 1 mole 1 molecule 1.40 x 1025 atoms

  15. The Mass of a Mole of an Element • The gram atomic mass (gam) is the atomic mass of an element expressed in grams. We will use the periodic table to determine this. • Gram atomic mass of Carbon = 12.01 g • Gram atomic mass of Nitrogen = 14.01g • Gram atomic mass of Sulfur = 32.06 g • The gram atomic mass is equivalent to one mole of the atom. Use the Periodic Table

  16. The Mass of a Mole of a Compound • The gram molecular mass (gmm) of any molecular compound is the mass of 1 mole of that compound. We will again use the periodic table to determine this. • Find the gram molecular mass of the following: • H2O2 • N2O5 • Ca(OH)2

  17. The Mass of a Mole of a Compound • The mass of one mole of an ionic compound is the gram formula mass (gfm). A gram formula mass is calculated the same way as a gram molecular mass. • Find the gram formula mass of the following: • CaI2 • (NH4)2CO3

  18. Section 7.1 The Mole: A Measurement of Matter • Did We Meet Our Objectives? • Describe how Avogadro’s number is related to a mole of any substance • Calculate the mass of a mole of any substance Charlotte would be proud!

  19. Section 7.2 Mole-Mass and Mole-Volume Relationships • Objectives: • Use the molar mass to convert between mass and moles of a substance • Use the mole to convert among measurements of mass, volume, and number of particles

  20. The Mass of a Mole of an Element • Molar mass – mass of 1 mol of any substance.Can be used in calculations involving elements, molecular compounds, and ionic compounds • 1.0 mol of C has a mass of 12.01 g 12.01 g/mol • 1.0 mol of H2 has a mass of 2.02 g 2.02 g/mol • 1.0 mol H2O has a mass of 18.02 g 18.02 g/mol

  21. Ex: Find the mass, in grams, of 2.5 molsof Na. 2.5 mol Na x22.99 g Na= 57.475 g Na 1 mole Na 57 g Na

  22. Ex: Find the number of mols in 75.0 g of dinitrogen trioxide (N2O3). 75.0 g N2O3x1 mol N2O3= 0.98658 mol N2O3 76.02 g N2O3 0.987 mol N2O3

  23. Ex: Find the mass, in grams, of 3.0 mols of molecular oxygen, O2. 3.0 mol O2x32.00 g O2= 96 g O2 1 mol O2 96 g O2

  24. Ex: Find the number of moles in 236.5 g of CuSO4. 236.5 g CuSO4x1 mol CuSO4= 1.4817 mol CuSO4 159.61 g CuSO4 1.482 mol CuSO4

  25. Volume of a Mole of Gas • Standard temperature and pressure (STP) – conditions in which gas volumes are generally measured • Standard Temperature: 0 oC, 273 K, or 32 oF • Standard Pressure: 101.3 kPa, 1 atm, 760 mm Hg • Molar volume – 1 mol of any gas at STP takes up 22.4L of space.

  26. Ex: What is the volume of 0.960 mol of CH4 at STP? 0.960 mol CH4x22.4 L CH4= 21.504 L CH4 1 mol CH4 21.5 L CH4

  27. Ex: What is the volume of 1.5 mol of N2 at STP? 1.5 mol N2x22.4 L N2= 33.6 L N2 1 mol N2 34 L N2

  28. Ex: How many mols are in 2.50 L of CO2 at STP? 2.50 L CO2x1 mol CO2= 0.111607 mol CO2 22.4 L CO2 0.112 mol CO2

  29. Ex: What is the molar mass of a gas with a density of 1.964 g/L at STP? 1.964 gx22.4 L= 43.9936 g/mol L 1 mol 43.99 g/mol

  30. The Mole Road Map

  31. Ex: Calculate the number of molecules in 60.0 g NO2 60.0 g NO2 x 1 mol NO2 x 6.02 x 1023 molecules NO2 46.01 g NO2 1 mol NO2 7.85046729 x 1023 molecules 7.85 x 1023 molecules

  32. Ex: Calculate the volume, in liters, of 3.24 x 1022 molecules Cl2 at STP. 3.24 x 1022 molecules Cl2 x 1 mol x 22.4 L 6.02 x 1023 molecules 1 mol 1.21 L Cl2 at STP

  33. Section 7.2 Mole-Mass and Mole-Volume Relationships • Did We Meet Our Objectives? • Use the molar mass to convert between mass and moles of a substance • Use the mole to convert among measurements of mass, volume, and number of particles

  34. Section 7.3 Percent Composition and Chemical Formulas • Objectives: • Calculate the percent composition of a substance from its chemical formula or experimental data • Derive the empirical formula and molecular formula of a compound from experimental data

  35. Calculating the Percent Composition of a Compound • Percent composition – the relative amounts of each element in a compound • Percent by Mass

  36. Ex: An 8.20 g piece of magnesium combines completely with 5.40 g of oxygen to form a compound. What is the percent composition of this compound?

  37. Calculating the Percent Composition of a Compound • Percent composition – the relative amounts of each element in a compound • Percent by Composition

  38. Ex: Find the percent composition of propane (C3H8).

  39. Using Percent as a Conversion Factor • To do this, you multiply the mass of the compound by a conversion factor that is based on the percent composition. • Ex: Calculate the mass of carbon in 82.0 g of propane (C3H8). (Remember, carbon is 81.8%)

  40. Calculating Empirical Formulas • Empirical formula – gives the lowest whole number ratio of atoms of the elements in a compound • Empirical formula can sometimes be the molecular formula • CO2 • C6H12O6 CH2O

  41. Calculating Empirical Formulas The polymer used for the nonstick surface of cooking utensils is 24.0% C and 76.0% F by mass. • What is the empirical formula of this polymer?

  42. Calculating Molecular Formulas The polymer used for the nonstick surface of cooking utensils is 24.0% C and 76.0% F by mass. • What is the empirical formula of this polymer? • If the molecular mass is 100.02 g, what is the molecular formula?

  43. Section 7.3 Percent Composition and Chemical Formulas • Did We Meet Our Objectives? • Calculate the percent composition of a substance from its chemical formula or experimental data • Derive the empirical formula and molecular formula of a compound from experimental data

More Related