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OXIDATION-REDUCTION REACTIONS

OXIDATION-REDUCTION REACTIONS. Settle in, this is going to take a while…. What is redox?. Reaction where there is a transfer of electrons between reactants O xidation i nvolves the l oss of electrons (OIL) Oxidation number/state of the element increases

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OXIDATION-REDUCTION REACTIONS

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  1. OXIDATION-REDUCTION REACTIONS Settle in, this is going to take a while…

  2. What is redox? • Reaction where there is a transfer of electrons between reactants • Oxidation involves the loss of electrons (OIL) • Oxidation number/state of the element increases • Oxidized element is the reducing agent • Reduction involves the gain of electrons (RIG) • Oxidation number/state of the element decreases • Reduced element is the oxidizing agent

  3. Example Complete Reaction: Mg + Zn(NO3)2 Mg(NO3)2 + Zn Net-ionic Reaction: Mg + Zn2+ Mg2+ + Zn The magnesium metal was oxidized by the zinc and the zinc was reduced by the magnesium.

  4. Do what?!?! • The oxidation state of the magnesium changed from 0 to +2 • Oxidation state increased = oxidation • Because magnesium gave its electrons away, it is the reducing agent • The oxidation state of zinc changed from +2 to 0 • Oxidation state decreased = reduction • Because zinc took the electrons, it is the oxidizing agent

  5. How do you know oxidation states? • The oxidation number for any pure element is zero. • Group 1 metals form +1 ions, group 2 metals form +2 ions, group 13 metals form +3 ions. • Transition metals can be all kinds of oxidation numbers (ranging from +1 to +7) • Transition metal oxidation states can be determined based on the nonmetal(s) it’s bonded to…

  6. Nonmetal oxidation states • Fluoride is ALWAYS -1, the other halides are usually -1. • Oxide is usually -2, except when it’s in the peroxide ion (-1) or bonded to fluorine (+2) • Hydrogen is +1, unless it is the hydride ion (-1)

  7. Putting it all together • The total charge on a compound is zero, so all oxidation numbers must cancel out. • The total charge of elements in a polyatomic ion must add to the charge on the ion

  8. Practice What is the oxidation number of each element in the following compounds? • Zn(NO3)2 • H2SO4 • KMnO4 • N2O4 • PCl3

  9. What’s the point? • When an element gains electrons, another element must accept those electrons (Newton’s 3rd law). • If you separate the reaction into half-reactions, you can exploit this electron transfer to generate electricity. • The study of this is electrochemistry, but more on that later…

  10. Half-Reactions? • You can separate a redox reaction into the reduction reaction and the oxidation reaction. • First you have to identify which element is oxidized and which is reduced. • So let’s practice identification first:

  11. Practice Determine the oxidation states of all elements in the following reactions and then identify which element is oxidized and which is reduced. N2 + 3H2 2NH3 2MnO2 + Zn + 2H2O  2MnO(OH) + Zn(OH)2 AgNO3 + Cu  Cu(NO3)2 + Ag

  12. N2 + 3H2 2NH3

  13. 2MnO2 + Zn + 2H2O  2MnO(OH) + Zn(OH)2

  14. AgNO3 + Cu  Cu(NO3)2 + Ag

  15. Separating reactions • Once the oxidized and reduced elements have been identified, separate the reactions. • Use net ionic reactions instead of complete reactions 2AgNO3 + Cu  Cu(NO3)2 + 2Ag 2Ag+1 + Cu  Cu2+ + 2Ag

  16. 2Ag+1 + Cu  Cu2+ + 2Ag • The silver is reduced, so that is the reduction reaction: 2Ag+1 2Ag • The masses are balanced, but the charges are not, so add the electrons being transferred: 2Ag+1 + 2e- 2Ag • Notice that the reduction half reaction has electrons as reactants

  17. 2Ag+1 + Cu  Cu2+ + 2Ag • The copper is oxidized, so that is the oxidation reaction: Cu  Cu2+ • The masses are balanced, but the charges are not, so add the electrons being transferred: Cu  Cu2+ + 2e- • Notice that the oxidation half reaction has electrons as products

  18. 2Ag+1 + Cu  Cu2+ + 2Ag • When you put the 2 half-reactions together they equal the complete reaction: 2Ag+1 + 2e- 2Ag Cu  Cu2+ + 2e- • the electrons cancel out to make the net ionic reaction

  19. More about balancing • Sometimes you need more than electrons to balance a half reaction. • Oxygens and hydrogens can be balanced by the addition of H+, OH-, and H2O depending on if the solution is acidic or basic.

  20. Balancing Acidic Redox • Balance all elements that are not oxygen or hydrogen • Balance O by adding H2O where needed • Balance H by adding H+ where needed • Balance charges by adding e- to the more positive side

  21. Balancing Basic Redox • Follow the steps for acidic balancing first, then… • Count the H+ used to balance the reaction and add the same number of OH- to both sides. • Combine OH- and H+ to make water. • Combine/cancel water molecules as needed.

  22. A LOT of practice Balance the following equation in both an acidic and a basic solution: HOCl + NO(g)  Cl2(g) + NO3-

  23. More practice Balance this reaction in an alkaline environment: MnO2(s) + Zn(s) + H2O  2MnO(OH)(s) + Zn(OH)2(s)

  24. Homework Problems Pick a few homework problems to work through together 

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