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Learn about methods like Present Worth, Internal Rate of Return, Savings/Investment Ratio, and more to determine the economic feasibility of projects. Explore cash flow breakdown examples and calculations for Present Worth and Annual Worth. Discover when an alternative is economically feasible based on key indicators.
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CTC 475 Review • Is a certain cash flow economically feasible?
CTC 475 Methods for Determining if an Alternative is Economically Feasible
Objectives • Know the various methods for determining if an alternative is economically feasible • Be able to use any method for economic feasibility studies
Methods for Economic Feasibility Studies • Present Worth (PW) • Annual Worth (AW) • Future Worth (FW) • Internal Rate of Return (IRR) • External Rate of Return (ERR) • Savings/Investment Ratio (SIR) or • Benefit/Cost Ratio (B/C) • Payback Period Method (PBP) • Capitalized Worth Method (CW)
Equivalent Methods • PW • AW • FW • IRR • ERR • SIR or B/C
Nonequivalent Methods • PBP • CW
When is an alternative feasible? • PW > 0 • AW > 0 • FW > 0 • IRR > MARR • ERR > MARR • SIR or B/C > 1
Net Cash Flows • It’s a good idea to use net cash flows (one cash flow at each period). • It doesn’t matter with respect to whether a project is feasible or not; however, absolute numbers (ERR and SIR) may differ
Cash flow breakdown • Years 1-4: Uniform ($5K) + Gradient ($3K) • n=4 • P will occur at t=0 • F will occur at t=4 • Years 5-8: Uniform ($14K) - Gradient ($3K) • n=4 • P will occur at t=4 • F will occur at t=8
Present Worth • PW= -40K+5K(P/A10,4)+3K(P/G10,4) +[14K(P/A10,4)- 3K(P/G10,4)](P/F10,4) • PW= -40K+5K(3.1699)+3K(4.3781) +[14K(3.1699)-3K(4.3781)]*0.6830 • PW= +$10,324 • PW>0 ; therefore, cash flow is economically feasible
Annual Worth • Find A given P • AW=PW(A/P10,8) • AW=$10,324(.1874) • AW=$1,935 • AW>0; therefore, cash flow is economically feasible
Future Worth • FW=PW(F/P10,8) or PW(1.1)8 • FW=$10,324(2.1436) • FW=$22,130 OR • FW= AW(F/A10,8) • FW=$1,935(11.4359) • FW=$22,128 • FW>0; therefore, cash flow is economically feasible
Future Worth-Alternate Method • FW= -40K(F/P10,8)+[5K+3K(A/G10,4)](F/A10,4)(F/P10,4) +[14K-3K(A/G10,4)](F/A10,4) • FW=-$85,744+($9,144)(6.7949)+($9,856)(4.6410) • FW=+$22,129
IRR-Find i that gives a PW=0 • PW= -40K+5K(P/Ai,4)+3K(P/Gi,4) +[14K(P/Ai,4)- 3K(P/Gi,4)](P/Fi,4) Interpolate to get an IRR = 16.5% IRR>MARR
ERR: Set FW of + using MARR = FW of – using ERR; solve for ERR • FW(+) = 5K+3K(A/G10,4)](F/A10,4)(F/P10,4) +[14K-3K(A/G10,4)](F/A10,4) = $107,873 • FW(-) = 40K(1+ERR)8 • 40K(1+ERR)8 = $107,873 • (1+ERR)8 = 2.6968 • ERR=13.2% • ERR>MARR • Check: MARR=10%; ERR=13.2%; IRR=16.5%
SIR or B/C • SIR=PW(+)/PW(-) • PW(+)=5K(P/A10,4)+3K(P/G10,4) +[14K(P/A10,4)- 3K(P/G10,4)](P/F10,4)=$50,324 • SIR=$50,324/$40,000=1.26 • SIR>1
PBP-Payback Period • If MARR=0 how many periods does it take to get your investment back? • At 1 year; $5K<$40K • At 2 years: $13K<$40K • At 3 years: $24K<$40K • At 4 years: $38K<$40K • At 5 years: $52K>$40K • PBP is 5 years
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