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ACC. AAF Practice Test #3 - Key

ACC. AAF Practice Test #3 - Key

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ACC. AAF Practice Test #3 - Key

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  1. ACCUPLACER® AAF Practice Test #3 - Key ACCUPLACER® Practice Test AAF #3 - Key © 2017 The College Board

  2. ACCUPLACER® AAF Practice Test #3 - Key 1 2 1 2     2 2 1. C: The correct solution is 10.8 because 45 (3.14) A r r 45 1.57  centimeters.      2 2 . The diameter is twice the radius, or about 10.8 28.66 5.4 r r r 1 2 1 2 1 2      48 1.57  2 2 2 2. A: The correct solution is 17.3. 48 (3.14) A r r r 1 2          centimeters. 2 (2 ) (2)(3.14)(5.5) 17.3 30.57 5.5 C r C r r centimeters. 3. B: The correct solution is 254.4 because millimeters. 4. D: The correct solution is line segment because the cities represent the endpoints and the segment is the distance between the two points. 5. C: The correct solution is six lines of symmetry. There are three lines of symmetry through opposite vertices and three lines through the midpoints of opposite segments. 6. D: The correct solution is D. The translation for the points is (x - 4, y + 4). The points of the original square, (-1, 5), (-1, -1), (5, -1) and (5, 5) become (-5, 9), (-5, 3), (1, 3), and (1, 9). 7. C: The correct solution is a reflection across the line of y = x because the points (x, y) become (y, x). 8. D: If the positive number is 1, then one of its multiples is 3 - a prime number. Answer A is therefore false, as is answer C. If the positive number is 0, all of its multiples are 0. Therefore, it has no prime multiples, eliminating answer B. 9. A: Any product of a number and an integer is a multiple of that number. Since, (123)(-1) is -123, one multiple of 123 is -123.     2 2 square 3.14(9) 254.34 A r © 2017 The College Board

  3. ACCUPLACER® AAF Practice Test #3 - Key 10. B: A prime number only has 1 and itself as factors; therefore a composite number must have at least one other factor. If that factor is composite, the number has more factors. If that factor is prime, then it is the only prime factor of the number. For example, 9 has 3 as a prime factor; its only other factors are 1 and 9. But 1 is not a prime number. Neither is 9, which is composite. A composite number therefore has at least one unique prime factor. 11 A: The correct solution is 45 3. Substitute the values into the formula and 1 3 1 1 ( 3 2 1 1 ( (9)(3 3))10 3 2     simplify using the order of operations, . ) 45 3 V bh bh h 12. A: The correct solution is 8. Substitute the values into the formula, 2 80 10 , h    and apply the exponent, 800 equation by 100?, and h = 8 centimeters. 13. B: The correct solution is 184.21 cubic centimeters. The radius is 4 centimeters. Substitute the values into the formula and simplify using the order of 1 1 1 (3.14)(4 )(11) (3.13)(16)(11) 184.21 3 3 3 14. D: The correct solution is (115, 30) because 100 can be added to the x- coordinate, 15 + 100 = 115. 15. B: The first point is in the second quadrant, the second point is in the third quadrant, the third point is in the fourth quadrant, and the last point is in the first quadrant. 16. C: The correct solution is 3,375. Substitute the values into the formula and simplify using the order of operations, V  17. C: The correct solution is 7. Substitute the values into the formula, 105 = 15h and divide both sides by 15, h = 7 inches.   100 . h  Then, divide both sides of the      2 2 operations, cubic centimeters. V r h   3 3 cubic millimeters. 15 3,375 s © 2017 The College Board

  4. ACCUPLACER® AAF Practice Test #3 - Key  18. D: The correct solutions are 1 2 2 37 x x   38. Add 37 to both sides. 2 2    1 37 1    2 2 2 Complete the square, ( ) 1 1. 2 x x  1 38   2 Add 1 to both sides of the equation. 2 x ( x  1 x   19. D: The correct solution is 8. x x  2 Factor the left side of the equation. 1) 38 Apply the square root to both sides. 1 38 Add 1 to both sides. 38 The equation can be solved by factoring. 3 (3 (3 (3    Factor the equation. 8)(3 8) 0 x x     Set each factor equal to 0. 8) 0;(3 8) 0 x x x  Set one factor = 0 because both are the same. 8) 0 8 3 x  Add 8 to both sides and divide both sides by 3. © 2017 The College Board

  5. ACCUPLACER® AAF Practice Test #3 - Key  and 7. 5 3 20. B: The correct solutions are 2    Factor the equation. (3 (3 (3 5)(2 7) 0 x x     Set each factor equal to 0. 5) 0.. ..(2 or 7) 0 x x x  Subtract 5 from both sides and divide both sides by 3 to solve. 5) 0 5 3 x   x  Add 7 to both sides and divide both sides by 2 to solve. 2 7 0 7 2 x  © 2017 The College Board

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