Khoirul S olehah Nur Athirah K hadijah. Who is he?.
Sir Isaac Newton was born on 4 January 1643 . Sir Isaac Newton (4 January 1643 – 31 March 1727 [OS: 25 December 1642 – 20 March 1727]) was an Englishphysicist, mathematician, astronomer, natural philosopher, alchemist, and theologian who is perceived and considered by a substantial number of scholars and the general public as one of the most influential men in history.
Question 1: The gravitational force of earth acting on a body of mass 1 kg is _______.
Question 2: The momentum of a toy bus of 0.01 kg moving with a velocity of 5 m/s is
a) 0.005 kg m/sb) 0.05 kg m/sc) 0.005 N sd) 0.5 kg m/s
Answer : b
Question 3: When an object undergoes acceleration
a) its speed always increasesb) its velocity always increasesc) it always falls towards the Earthd) a force always acts on it
Answer : d
Question 4 :A force of 625 N acts on a body of mass 25 kg. Find the acceleration of the body.
Force (F) = 625 N Mass (m) = 25 kg
Acceleration (a) = ?F = ma a= F/m
Acceleration = 25 m/s2
Question 5 :Calculate the change in momentum of a body weighing 10 kg when its velocity decreases from 20 m/s to 0.2 m/s.
Mass of the body (m) = 10 kg
Initial velocity (u) = 20 m/s Final velocity (v)= 0.2 m/s
Change in momentum = m (v-u) = 10 (0.2 - 20)
= 10 (-19.8) Change in momentum = -198 N s
WHAT WOULD HAPPEN? weighing 10 kg when its velocity decreases from 20 m/s to 0.2 m/s.
Newton's 3rd law stated: weighing 10 kg when its velocity decreases from 20 m/s to 0.2 m/s."Forces always occur in pairs. If object A exerts a force F on object B, then object B exerts an equal and opposite force –F on object A" or in slogan style:
"Every action has an equal and opposite reaction"
OPEN THE BOTTLE weighing 10 kg when its velocity decreases from 20 m/s to 0.2 m/s.
LAUNCHING OF A ROCKET
THAT’S ALL weighing 10 kg when its velocity decreases from 20 m/s to 0.2 m/s.