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GRAVITY For two particles that have masses m 1 and m 2 and are separated by a distance r , the force has a magnitude given by. 12.0 Kg. 25.0 Kg. 1.20 m. What is the Initial Force between m 1 and m 2 ?. academicearth.org Lecture 69 introduction-to- newtons -law-of-gravitation.

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slide1

GRAVITY

For two particles that have masses m1 and m2and are

separated by a distance r, the force has a magnitude given by

slide2

12.0 Kg

25.0 Kg

1.20 m

What is the Initial Force between m1 and m2?

academicearth org lecture 69 introduction to newtons law of gravitation
academicearth.org Lecture 69 introduction-to-newtons-law-of-gravitation
  • F gravity = (G * M 1 * M 2)/ (d2)
      • G is 6.67 X10 -11 Nm2 / kg2
  • F gravity = (m * “g”) = (mass times gravitational acceleration) =Weight
  • DO NOW: What is the Force of attraction between “P” and “A” if “P” has a mass of 50.0 Kg and “A” has a mass of 65.0 Kg and they are separated by 1.00 meter? __________N
  • If “Purple” is held stationary and “Austin” is allowed to move n a totally frictionless surface (NO other forces!) from rest AND if the INITIAL Acceleration remains constant…HOW LONG will it take “A” to “contact” “P”? _________Sec
slide4

m1 = 50.0 Kg

m2 = 65.0 Kg

r = 1.00 m

F = [6.67X10-11 (50.0 *65.0)] /1m2

ANSWEWR Part ONE F = 2.17 X10-7 N

m2 a = F = 2.167 X10-7 N

a = F/m2 =2.167 X10-7 N /65.0 = 3.335 X10-9 m/s2

D = Vi(t) + ½ a t2

1.00 m = 0 + [½] {3.335 X10-9 m/s2} t2

5.997 X108 s2 =t2

2.448877 X10 4 sec = 2.45 X10 4 sec

408 minutes = 6.8 hrs

gravity homework glencoe pages 191 192 43 45 46 49 58 59 62 71 72
Gravity Homework: Glencoe Pages 191-192 43,45,46, 49, 58,59,62,71,72
  • discovery.com stephen-hawkings-universe-cosmic-gravity-dance.html
definition of weight
Definition of Weight

The weight of an object on or above the earth is the gravitational force that the earth exerts on the object.

Weight is written as m * g

F grav= Weight = Mobj*g

F grav= {G MobjMEarth }/ (Radius)2

Mobj*g = {G MobjMEarth }/ (Radius)2

g = {G MEarth }/ (Radius)2

g = {6.67X10-11 5.9624 X 1024 }/ (6.37814 X 10 6)2

g = 9.77595 m/s2

what is keeping the moon from falling into the earth
What is keeping the moon from “falling” into the Earth?

Mass of the Earth : 5.9624 X 1024 Kg

Mass of the Moon:7.2997 X 1022 Kg

Orbital distance from the Moon to Earth :0.3844 X106 Km

orbits centripetal force
Orbits Centripetal Force

Homework: Glencoe Pgs 191-192: #’s 43,45,46, 49, 58,59,62,71,72

Pgs : 195 ‘s 1 – 6 ALL

Homework: Serway Pgs 451#’s 9, 12,14, 18, 19

  • F centripetal = M obj{V2/ R }
  • (R and d are sometimes used interchangeably when talking about orbits)
  • Gravity = (G * M obj * M planet)/ (d2)
  • Orbits are in “Balance”
    • M obj V2 / R = (G * M obj * M planet)/ (d2)
    • V2 / d = (G * M planet)/ (d2)
    • V2 = (G * M planet)/ (d)
    • V =√[ (G * M planet)/ (d)]
next class kepler s third law
Next Class Kepler’s Third Law

(T “A” / T “B”)2 = (R “A” / R “B”)3

(Period of Orbiting Object “A” / Period of Orbiting Object “B”)2

=

(Radius of Orbit for Object “A” / Radius of Orbit for Object “B”)3

“B”

“A”

{TA/TB}2 = {RA / RB}3