1 / 13

INCLINED BENDING

INCLINED BENDING. z. z. z. . y. y. y. . If bending moment does not coincide with any of principal central axis of cross-section inertia we have to deal with inclined bending. Direction of bending moment vector. Plane of load acting. +. z. z. z. z. z. . y. y. y. y. y.

Download Presentation

INCLINED BENDING

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. INCLINED BENDING

  2. z z z  y y y  If bending moment does not coincide with any of principal central axis of cross-section inertia we have to deal with inclined bending. Direction of bending moment vector Plane of load acting +

  3. z z z z z  y y y y y We use superposition principle Jy>Jz For neutral axis: Jy<Jz Neutral axis

  4. z  y is represented by the equation of the plane Stress distribution: This plane cuts thorough cross-section plane at the neutral axis Tension zone Compression zone Neutral axis

  5. Animation of neutral axis movement dependent on bending moment direction

  6. z Angle 80o 70o 60o 50o 40o y 30o 20 10o h/b=1,41 00o Loading plane Jy/Jz =2 Neutral axis Bending moment vector

  7. z 80o 70o 60o 50o 40o y 30o 20 10o h/b=1,41 00o Jy/Jz =2 Loading plane Neutral axis Bending moment vector

  8. z 80o 70o 60o 50o 40o y 30o 20 10o b/h=1,41 00o Jy/Jz =1/2 Loading plane Neutral axis Bending moment vector

  9. z z z y y y Zmax =a/2=0,5a Zmax =a/2½=0,7a h=b=a Ideal shape: independent of plane of loading angle maximum stress is the same! Jy/Jz =1 Płaszczyzna obciążenia Oś obojętna Wektor momentu

  10. stop

  11. z Angle 80o 70o 60o 50o 40o y 30o 20 10o h/b=1,41 00o Loading plane Jy/Jz =2 Neutral axis Bending moment vector

  12. z Angle 80o 70o 60o 50o 40o y 30o 20 10o h/b=1,41 00o Loading plane Jy/Jz =2 Neutral axis Bending moment vector

  13. z z y y α=45° Zmax =a/2=0,5a Zmax =a/2½=0,7a h=b=a Ideal shape: independent of plane of loading angle maximum stress is the same! Jy/Jz =1 Płaszczyzna obciążenia Oś obojętna Wektor momentu

More Related