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ELECTROCHEMISTRY Chap 20

ELECTROCHEMISTRY Chap 20. Nernst Equation for a Complete Reaction. E cell = E + − E − = E cathode − E anode. Only valid when both ½-rxns written as reductions. Given: Cd ( s ) │ Cd(NO 3 ) 2 ( aq ); M A ║ FeCl 2 (aq); M C │ Fe ( s)

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ELECTROCHEMISTRY Chap 20

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  1. ELECTROCHEMISTRY Chap 20

  2. Nernst Equation for a Complete Reaction Ecell = E+ − E− = Ecathode − Eanode • Only valid when both ½-rxns written as reductions • Given: • Cd (s) │ Cd(NO3)2 (aq); MA ║ FeCl2 (aq); MC │ Fe (s) • [Cd2+] = 0.50 M; [Fe2+] = 0.10 M Ans = −0.058 V • (b) [Cd2+] = 0.010 M; [Fe2+] = 1.0 M; Ans = +0.021 V

  3. In Class Exercise: Calculate the cell potential for: Cu │ CuCl2 (0.0200 M) ║ AgNO3 (0.0200 M) │ Ag Ans = +0.410 V Calculate the cell potential for: Pt │ UO22+ (0.0150 M); U4+ (0.200 M); H+ (0.0300 M ║ Fe2+ (0.0100 M); Fe3+ (0.0250 M) │ Pt Ans = +0.638 V UO22+ + 4H+ + 2e−→ U4+ + 2H2O;Eo= +0.334 V

  4. Applications of Oxidation-Reduction Reactions • Batteries and Fuel Cells • Corrosion • Electrolysis

  5. Batteries Fig 20.19 A 12 V automobile lead-acid battery Fig 20.19 Combining cells

  6. Fig 20.21 Cutaway view of a miniature alkaline cell

  7. Fig 20.24 Corrosion of iron in contact with water

  8. Fig 20.25 Cathodic protection of iron in contact with zinc

  9. Fig 20.26 Cathodic protection of an iron water pipe

  10. Fig 20.27 Electrolysis of molten sodium chloride

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