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Hashing

Hashing. Reference: Chapters: 11,12. Motivation. The primary goal is to locate the desired record in a single access of disk. Sequential search: O(N) B+ trees: O(log k N) Hashing: O(1) In hashing, the key of a record is transformed into an address and the record is stored at that address.

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Hashing

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  1. Hashing Reference: Chapters: 11,12 CENG 351

  2. Motivation • The primary goal is to locate the desired record in a single access of disk. • Sequential search: O(N) • B+ trees: O(logk N) • Hashing: O(1) • In hashing, the key of a record is transformed into an address and the record is stored at that address. • Hash-based indexes are best for equality selections. Cannot support range searches. • Static and dynamic hashing techniques exist. CENG 351

  3. Hash-based Index • Data entries are kept in buckets (an abstract term) • Each bucket is a collection of one primary page and zero or more overflow pages. • Given a search key value, k, we can find the bucket where the data entry k* is stored as follows: • Use a hash function, denoted by h • The value of h(k) is the address for the desired bucket. h(k) should distribute the search key values uniformly over the collection of buckets CENG 351

  4. Design Factors • Bucket size: the number of records that can be held at the same address. • Loading factor: the ratio of the number of records put in the file to the total capacity of the buckets. • Hash function: should evenly distribute the keys among the addresses. • Overflow resolution technique. CENG 351

  5. Hash Functions • Key mod N: • N is the size of the table, better if it is prime. • Folding: • e.g. 123|456|789: add them and take mod. • Truncation: • e.g. 123456789 map to a table of 1000 addresses by picking 3 digits of the key. • Squaring: • Square the key and then truncate • Radix conversion: • e.g. 1 2 3 4 treat it to be base 11, truncate if necessary. CENG 351

  6. Static Hashing • Primary Area: # primary pages fixed, allocated sequentially, never de-allocated; (say M buckets). • A simple hash function: h(k) = f(k) mod M • Overflow area: disjoint from the primary area. It keeps buckets which hold records whose key maps to a full bucket. • Adding the address of an overflow bucket to a primary area bucket is called chaining. • Collisiondoes not cause a problem as long as there is still room in the mapped bucket. Overflow occurs during insertion when a record is hashed to the bucket that is already full. CENG 351

  7. Example • Assume f(k) = k. Let M = 5. So, h(k) = k mod 5 • Bucket factor = 3 records. 17 Primary area overflow CENG 351

  8. # of records in the file # of spaces in primary area Load Factor (Packing density) • To limit the amount of overflow we allocate more space to the primary area than we need (i.e. the primary area will be, say, 70% full) • Load Factor = => Lf = n M * Bkfr CENG 351

  9. Effects of Lf and Bkfr • Performance can be enhanced by the choice of bucket size and load factor. • In general, a smaller load factor means • less overflow and a faster fetch time; • but more wasted space. • A larger Bkfr means • less overflow in general, • but slower fetch. CENG 351

  10. Insertion and Deletion • Insertion: New records are inserted at the end of the chain. • Deletion: Two ways are possible: • Mark the record to be deleted • Consolidate sparse buckets when deleting records. • In the 2nd approach: • When a record is deleted, fill its place with the last record in the chain of the current bucket. • Deallocate the last bucket when it becomes empty. CENG 351

  11. Problem of Static Hashing • The main problem with static hashing: the number of buckets is fixed: • Long overflow chains can develop and degrade performance. • On the other hand, if a file shrinks greatly, a lot of bucket space will be wasted. • There are some other hashing techniques that allow dynamically growing and shrinking hash index. These include: • linear hashing • extendible hashing CENG 351

  12. Linear Hashing • It maintains a constant load factor. • Thus avoids reorganization. • It does so, by incrementally adding new buckets to the primary area. • In linear hashing the last bits in the hash number are used for placing the records. CENG 351

  13. Example Last 3 bits e.g. 34: 100010 28: 011100 13: 001101 21: 010101 Lf = 15/24 = 63% Insert: 13, 21, 37 CENG 351

  14. Insertion of records • To expand the table: split an existing bucket denoted by k digits into two buckets using the last k+1 digits. • e.g. 0000 000 1000 CENG 351

  15. Expanding the table Boundary value 37 CENG 351

  16. k = 3 Hash # 1000: uses last 4 digits Hash # 1101: uses last 3 digits Boundary value 37 CENG 351

  17. Fetching a record • Calculate the hash function. • Look at the last k digits. • If it’s less than the boundary value, the location is in the bucket labeled with the last k+1 digits. • Otherwise it is in the bucket labeled with the last k digits. • Follow overflow chains as with static hashing. CENG 351

  18. Insertion • Search for the correct bucket into which to place the new record. • If the bucket is full, allocate a new overflow bucket. • If there are now Lf*Bkfr records more than needed for the given Lf, • Add one more bucket to the primary area. • Distribute the records from the bucket chain at the boundary value between the original area and the new primary area buckets • Add 1 to the boundary value. CENG 351

  19. Deletion • Read in a chain of records. • Replace the deleted record with the last record in the chain. • If the last overflow bucket becomes empty, deallocate it. • When the number of records is Lf * Bkfr less than the number needed for Lf, contract the primary area by one bucket. Compressing the table is exact opposite of expanding it: • Keep the total # of records in the file and buckets in primary area. • When we have Lf * Bkfr fewer records than needed, consolidate the last bucket with the bucket which shares the same last k digits. CENG 351

  20. Hash prefix Length of common hash prefix i i1 bucket1 Data bucket i2 bucket2 Bucket address table i3 bucket3 Extendible Hashing Extendable Hashing • Hash function returns b bits • Only the prefix i bits are used to hash the item • There are 2i entries in the bucket address table • Let ij be the length of the common hash prefix for data bucket j, there is 2(i-ij) entries in bucket address table points to j CENG 351

  21. 2 2 00 01 10 11 2 1 3 3 3 000 001 010 011 100 101 110 111 2 1 Splitting a bucket: Case 1 Extendable Hashing • Splitting (Case 1: ij=i) • Only one entry in bucket address table points to data bucket j • i++; split data bucket j to j, z; ij=iz=i; rehash all items previously in j; CENG 351

  22. 2 3 2 3 000 001 010 011 100 101 110 111 000 001 010 011 100 101 110 111 2 2 2 1 2 Splitting: Case 2 Extendable Hashing • Splitting (Case 2: ij< i) • More than one entry in bucket address table point to data bucket j • split data bucket j to j, z; ij = iz = ij +1; Adjust the pointers previously point to j to j and z; rehash all items previously in j; CENG 351

  23. 1 4 5 7 8 2 20 001 100 101 111 000 010 100 2 00 01 1 10 0 11 1 0 0 1 2 2 1 1 1 4 4 5 1 7 1 8 4 5 Example Extendable Hashing • Suppose the hash function is h(x) = x mod 8 and each bucket can hold at most two records. Show the extendable hash structure after inserting 1, 4, 5, 7, 8, 2, 20. CENG 351

  24. 1 4 5 7 8 2 20 001 100 101 111 000 010 100 2 3 1 8 000 2 001 2 00 010 2 01 011 3 10 100 4 20 11 101 110 111 2 2 2 2 2 7 4 5 1 8 2 3 7 5 Example Extendable Hashing inserting 1, 4, 5, 7, 8, 2, 20 CENG 351

  25. Comments on Extendible Hashing • If directory fits in memory, equality search answered with one disk access. • A typical example: a100MB file with 100 bytes/entry and a page size of 4K contains 1,000,000 records (as data entries) but only about 25,000 directory elements  chances are high that directory will fit in memory. • If the distribution of hash values is skewed (e.g., a large number of search key values all are hashed to the same bucket ), directory can grow large. • But this kind of skew can be avoided with a well-tuned hashing function CENG 351

  26. Comments on Extendible Hashing • Delete: If removal of data entry makes bucket empty, can be merged with a “buddy” bucket. If each directory element points to same bucket as its split image, can halve directory. CENG 351

  27. Summary • Hash-based indexes: best for equality searches, cannot support range searches. • Static Hashing can lead to long overflow chains. • Extendible Hashing avoids overflow pages by splitting a full bucket when a new data entry is to be added to it. • Directory to keep track of buckets, doubles periodically. • Can get large with skewed data; additional I/O if this does not fit in main memory. CENG 351

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