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Mole Fraction

Mole Fraction. Mole Fraction ( X ). is the number of moles of that component divided by the total number of moles of solute and solvent . X = Moles of component Total moles of solution. Mole Fraction ( X ). X Solute = Moles of solute

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Mole Fraction

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  1. Mole Fraction

  2. Mole Fraction (X) is the number of moles of that component divided by the total number of moles of solute and solvent. X = Moles of component Total moles of solution

  3. Mole Fraction (X) XSolute = Moles of solute Total moles of solution XSolvent= Moles of solvent Total moles of solution Where: Xsolute + XSolvent = 1

  4. 1. An industrial gas contains 64.0g of SO2 in every 750.0g of CO2. What is the mole fraction of SO2? Given: Mass of Solute – 64.0 g Mass of Solvent – 750.0 g Formula: X = Moles of component Total moles of solution Answer: Molessolute = Mass of Solute Molar Mass of Solute = 64.0 g 32+ (16)2g/mole = 1 mole Answer: Molessolvent = Mass of Solvent Molar Mass of Solvent = 750.0 g 12+ (16)2g/mole = 17.05 mole

  5. Given: Moles of Solute – 1 mole Moles of Solvent – 17.05 moles Formula: Mole Fraction = Moles of component Total moles of solution Answer: XSO2 = Moles of SO2 Total moles of Solution = 1 mole 1 + 17.05 mole = 0.05540

  6. 2. 0.100 mole of NaCl is dissolved into 100.0 grams of pure H2O. What is the mole fraction of NaCl? Given: Mole of Solute – 0.100 mole Mass of Solvent – 100.0 g Formula: X= Moles of component Total moles of solution Answer: XNaCl= Moles of NaCl Total moles of Solution = 0.100 mole 5.56 + 0.100 mole = 0.018 Answer: Molessolvent = Mass of Solvent Molar Mass of Solvent = 100.0 g 2 + 16 g/mole = 5.56 mole

  7. 1. A 12.60 g isopropyl alcohol (C3H7OH) is dissolved in a 80 g of water. Calculate mole fraction of isopropyl alcohol in the solution. SEATWORK

  8. Given: Mass of Solute – 12.60 g Mass of Solvent – 80.0 g Formula: X= Moles of component Total moles of solution Answer: Molessolute = Mass of Solute Molar Mass of Solute = 12.60 g (12)3 + (1)8 + 16 g/mole = 0.21 mole Answer: Molessolvent = Mass of Solvent Molar Mass of Solvent = 80.0 g 2 + 16 g/mole = 4.44 mole

  9. Given: Moles of Solute – 0.21 mole Moles of Solvent – 4.44 moles Formula: X= Moles of component Total moles of solution Answer: XSolute = Moles ofC3H7OH Total moles of Solution = 0.21 mole 0.21 + 4.44 mole = 0.045

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