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# Moles of Sodium

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1. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas.

2. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = Molar Mass = Grams of Cl = Empirical Formula= Grams of O = Molecular Formula =

3. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = Grams of Cl = Empirical Formula= Grams of O = Molecular Formula =

4. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = Grams of Cl = 29.0 Empirical Formula= Grams of O = Molecular Formula =

5. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = Grams of Cl = 29.0 Empirical Formula= Grams of O = 52.2 Molecular Formula =

6. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = 122.44 Grams of Cl = 29.0 Empirical Formula= Grams of O = 52.2 Molecular Formula = Moles of Na = Moles of Cl = Moles of O =

7. Moles of Sodium

8. Moles of Sodium

9. Moles of Sodium

10. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = 122.44 Grams of Cl = 29.0 Empirical Formula= Grams of O = 52.2 Molecular Formula = Moles of Na = .8177 Moles of Cl = Moles of O =

11. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = 122.44 Grams of Cl = 29.0 Empirical Formula= Grams of O = 52.2 Molecular Formula = Moles of Na = .8177 Moles of Cl = .8181 Moles of O =

12. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = 122.44 Grams of Cl = 29.0 Empirical Formula= NaClO4 Grams of O = 52.2 Molecular Formula = NaClO4 Moles of Na = .8177 Moles of Cl = .8181 Moles of O = 3.263

13. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = 122.44 Grams of Cl = 29.0 Empirical Formula= NaClO4 Grams of O = 52.2 Molecular Formula = NaClO4 Moles of Na = .8177 Moles of Cl = .8181 Moles of O = 3.263

14. Molar mass P2O3 P: 30.97(2) = 61.94 O: 15.999(3) = 47.997 ------------------------------------ 109.937 g

15. Percent Composition SO3 S: 32.06 = 32.06 O: 15.999 (3) = 47.997 ---------------------------------- 80.057 47.997 * 100= 59.95% 80.057

16. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = 122.44 Grams of Cl = 29.0 Empirical Formula= Grams of O = 52.2 Molecular Formula =

17. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = 122.44 Grams of Cl = 29.0 Empirical Formula= NaClO4 Grams of O = 52.2 Molecular Formula = NaClO4

18. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = 122.44 Grams of Cl = 29.0 Empirical Formula= Grams of O = 52.2 Molecular Formula =

19. A compound contains 18.8% sodium, 29.0% chlorine, and 52.2% oxygen. If the molar mass of the compound is 122.44 g/mol, determine the empirical and molecular formulas. Grams of Na = 18.8 Molar Mass = 122.44 Grams of Cl = 29.0 Empirical Formula= Grams of O = 52.2 Molecular Formula =

20. Ascorbic acid is another name for Vitamin C. It is composed of 40.92% carbon, 4.58% hydrogen, and 54.50% oxygen, by mass. Determine the empirical formula for ascorbic acid.

21. Ascorbic acid is another name for Vitamin C. It is composed of 40.92% carbon, 4.58% hydrogen, and 54.50% oxygen, by mass. Determine the empirical formula for ascorbic acid. • Grams of C = Moles of Carbon = • Grams of H = Moles of Hydrogen = • Grams of O = Moles of Oxygen = • Molar Mass = Molecular Formula = • Empirical Formula =