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Online Coding Course for Beginners

Join our interactive online coding course for beginners to learn programming languages. Develop your skills with practical exercises and quizzes to master coding basics. Start your coding journey today!

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Online Coding Course for Beginners

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  1. nLikirn&> kd

  2. kd a[Tl[ S&>? • (#ipr)miN)y aikirn) vAt&n&> kd a[Tl[ k[ t[n) a>dr rh[l) j³yi. • t[n) kdn) mipN) ni[ a[km 'Gn" kh[viy C[.{u.di.s[m)3}

  3. ai S&> C[? • t[ni b>ºn[ aiFir a[ksrKi C[ an[ vt&<L aikirni C[. • a[ nLikir C[.

  4. nLikirn&> kd:- • aipN[ nLikirn&> kd k[v) r)t[ Si[F)S&>?

  5. udihrN • V = Ah

  6. pi[li[ nLikir • n)c[ dSi<v[l piepn[ bnivvi miT[ k[Tli[ s)m[ºT vpriS[? • s)m[ºTn&> kd = mi[Ti nLikirn&> kd - nini nLikirn&> kd {Kil) j³yi}

  7. dSi<v[l aikZ(tmi> kyi[ #i)pr)miN)k aikir d[Kiy C[?

  8. Grkim / ksi[T) • aip[l nLikirn&> kd Si[Fi[.

  9. nLikirn&> kd • nLikirn&> kd aipN[ k[v) r)t[ Si[F)S&>? • V = Ah • =

  10. a[km pr)vt<n • 1s[m) = 10m).m) • 1m)Tr = 100s[.m) • 1(km) = 1000m)Tr

  11. a[km pr)vt<n 1 s[m)2 = 10 m).m) ×10 m).m) =100 m).m)2 1 m)Tr2 = 100 s.[m).×100 s[.m) = 10000 s[.m)2 1 m)Tr2 = 1000 m).m). ×1000 m)..m) = 1000000 m).m)2 1 h[kTr = 100 m)Tr ×100 m)Tr = 10 000 m)Tr2 1 k).m)2 = 100 h[kTr

  12. Gn a[kmi[ • 1 s[m)3 = 1s[.m) ×1s.[m) × 1s[.m) • = 10 m).m) × 10 m).m) × 10 m).m) • = 1000 m).m)3 • 1 m)3 = 1m) × 1m) × 1m) • = 100 s[.m) × 100 s[.m) ×100 s[.m) • = 1000000 s[m)3

  13. xmti • kd – (#ipr)miN)y aikirn&> kd a[Tl[ t[n) a>dr rh[l) j³yi. • t[ni mipnni[ a[km '' Gn"" C[.{di.t s[.m)3} • kd an[ xmti b>ºn[ pirApr)k C[. • xmti a[Tl[ pi#imi> smie Skti ÚÄyn&> mip{mi[T[ Big[ p\vih)} • xmti h>m[Si m)l)l)Tr, l)Tr an[ k)li[l)Trni a[kmmi> mipvimi> aiv[ C[.

  14. xmtini udihrN q>Di p)Nin&> T)n 375 m).l).n) xmti Friv[ C[. klrni[ D¾bi[ 4 l)Trn) xmti Friv[ C[.

  15. kd an[ xmti prApr k[v) r)t[ j[iDiyli C[? • 1000 m).l) = 1 l)Tr • 1000 l)Tr = 1 k)li[l)Tr • 1 s[m)3 = 1 m).l) • 1000s[m)3 = 1000m).l) = 1l)Tr • 1 m)3 = 1000 l)Tr = 1 k)li[l)Tr

  16. udihrN • 1800 m).l) n[ l)Trmi> pr)vt)<t kri[ • 1800m).l) = 1800/1000 = 1.8l)Tr • 2.3 m)3 n[ l)Tr mi> pr)vt)<t kri[ 1m)3 = 1000l) {1k).l)} • 2.3m)3 = 2.3 k)li[ l)Tr = 2300 l)Tr

  17. l>biE = 5.53s[.m) xmti • aip[l Gnn) xmti Si[Fi[. • l>bie = 5.53 s[.m) • V = Ah • = (5.53 x 5.53) x 5.53 • = 169.11s[m)3 (1s[m)3 = 1m)l)} • xmti = 169.11m).l)

  18. udihrN fy&al T[ºkr upr rh[l) Ti>k) 6 m)Tr li>b) an[ 2m)Tr Äyis Friv[ C[. {a}.Ti>k)n&> m)3 mi> kd Si[Fi[ {b} ai Ti>k)mi> k[Tl&> p\vih)smiv) Skiy t[ Si[Fi[.

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