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High Current RF-testing ing . R.O. de Meijer AR Benelux BV. Customer’s target. Testing of RF-current breakdown levels for currents > 50A rms Improvement of quality and reliability of the product. Not all the customer’s suppliers specify these breakdowns.

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High Current RF-testing ing . R.O. de Meijer AR Benelux BV


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customer s target
Customer’s target
  • Testing of RF-current breakdown levels for currents > 50A rms
  • Improvement of quality and reliability of the product.
  • Not all the customer’s suppliers specify these breakdowns.
  • Perform the testing in-house, as part of the design cycle and QA program

HF Technology, Eindhoven, April 2012

customer s target cntd
Customer’s target (cntd)
  • Various components:
    • Connects
    • Capacitors
    • PIN diode switches
  • Preferably making use of the customer’s amplifiers
    • Pulse with 30 kW peak power @ 3% duty
    • 63 and 127 MHz

HF Technology, Eindhoven, April 2012

problem definition
Problem definition
  • RF amplifiers have 50Ω output impedance
  • Because 50Ω is not low, the maximum deliverable current will not be high
  • In case of Pout = 30 kWatt into 50 Ohm

HF Technology, Eindhoven, April 2012

enlarging the current
Enlarging the current
  • With a constant power level the only option is lowring the impedance in the test cicrcuit.
  • Transformation from 50Ωto 5Ω
  • The implication for the current now flowing through 5Ω is
  • This complies to the customer’s spcification

HF Technology, Eindhoven, April 2012

impedance transformation
Impedance transformation
  • With 30kW pulse and 3% duty cycle  Pavg ~ 1kW
  • Low-loss transformation is a must.
  • Loss less transformation with a ¼λ coaxial transformer
  • Two operational frequencies
    • 63 MHz λ = 4m75
    • 127 MHz λ = 2m36

Ztr

50Ω

30kW

LOAD

  • L= λ/4

HF Technology, Eindhoven, April 2012

coaxial transformer
¼ λ coaxial transformer
  • Coaxial cables with this characteristic impedance is not easily available
  • The impedance of a coaxial line
  • D = diameter outer conducter
  • d = diameter inner conducter
  • εr = rel. dielectrical constant

HF Technology, Eindhoven, April 2012

creation of the coaxial transformer
Creation of the ¼λ coaxial transformer
  • Brass pipes with 17 and 13 mm diameter
  • Make up a Z0 of 16Ω
  • Two models, 63 MHz and 127 MHz

127 MHz

63 MHz

HF Technology, Eindhoven, April 2012

the transformed impedance on the smith chart
The transformed impedance on the Smith-Chart

50Ω

HF Technology, Eindhoven, April 2012

test set up
Test set-up

L

15.8Ω

50Ω

EUT BOX

1 kW

HF Technology, Eindhoven, April 2012

1 kwatt 5 load
1 kWatt 5Ω load

The 5Ωpoint

20 x 100Ω parallel

HF Technology, Eindhoven, April 2012

unwanted effetcs in the set up
Unwanted effetcs in the set-up
  • Electrical lengths inside the EUT box
  • Zload = R + jωL
  • The ¼ λtransformator will not supply 50Ω to the amplifier.

HF Technology, Eindhoven, April 2012

solution theoretical
Solution (theoretical)

HF Technology, Eindhoven, April 2012

the solution practical
The solution (practical)

Stub-tuner detail

2 x 50Ω stub-tuner

HF Technology, Eindhoven, April 2012

conclusion
Conclusion
  • All transmission lines have air-dielectricum, with de εr = 1
  • No dielectrical losses.
  • With the ¼ golf transmission line and the supporting stub tuners all paracitic effects in the EUT box are eliminated.
  • The amplifier ‘sees’ under all conditions 50 Ω
  • Full power available for the ‘destructive’ test

HF Technology, Eindhoven, April 2012

more information
More information

AR Benelux B.V.

Frankrijklaan 7

2391 PX HAZERSWOUDE-DORP

Telefoon : +31 (0)172 423000

Web-site : www.arbenelux.com

E-mail : arbeneluxinfo@arworld.us

HF Technology, Eindhoven, April 2012