1 / 4

Hess’ Law: Adding Reaction Enthalpies

Hess’ Law: Adding Reaction Enthalpies. Some chemical reactions can not be carried out easily in order to determine the amount of heat or energy that can be obtained. Eg : Mg (s) + 1/2O 2(g)  MgO (s) + light ?.

mohawk
Download Presentation

Hess’ Law: Adding Reaction Enthalpies

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Hess’ Law: Adding Reaction Enthalpies Some chemical reactions can not be carried out easily in order to determine the amount of heat or energy that can be obtained. Eg: Mg(s) + 1/2O2(g)  MgO(s) + light ?

  2. G.H. Hess recognized a relationship between algebra and chemical equations. Chemical reactions can be added, subtracted, multiplied, and divided like math equations. For any chemical reaction that can be written in a series of steps, the overall enthalpy of the reaction is the result of adding up the sum of all the individual steps of the reaction.

  3. Eg: Calculate the enthalpy of reaction for the formation of rust. 2Fe(s) + 3/2O2(g)  Fe2O3(s) Given: • Fe2O3(s) + 3CO(g)  2Fe(s) + 3CO2(g) DHo= -26.7 kJ • CO(g) + 1/2O2(g)  CO2(g)DHo= -282.7 kJ We can rearrange the given equations in a manner that will yield the overall reaction.

  4. X-1 2Fe(s) + 3CO2(g)  Fe2O3(s) + 3CO(g) DHo= +26.7kJ • X3 3CO(g) + 3/2O2(g)  3CO2(g) DHo=-848.1kJ _____________________________________________ 2Fe(s) + 3/2O2(g)  Fe2O3(s) DHo=-821.4kJ

More Related