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Section 5.3

Section 5.3. Matrices And Systems of Equations. Systems of Equations in Two Variables. Matrices. A rectangular array of numbers is called a matrix (plural, matrices ). Example:

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Section 5.3

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  1. Section 5.3 Matrices And Systems of Equations

  2. Systems of Equations in Two Variables

  3. Matrices • A rectangular array of numbers is called a matrix (plural, matrices). Example: • The matrix shown above is an augmented matrix because it contains not only the coefficients but also the constant terms. • The matrix is called the coefficient matrix.

  4. Matrices continued • The rows of a matrix are horizontal. • The columns of a matrix are vertical. • The matrix shown has 2 rows and 3 columns. • A matrix with m rows and n columns is said to be of orderm n. • When m = n the matrix is said to be square.

  5. Gaussian Elimination with Matrices • Row-Equivalent Operations 1. Interchange any two rows. 2. Multiply each entry in a row by the same nonzero constant. 3. Add a nonzero multiple of one row to another row.

  6. Example Solve the following system: .

  7. Example continued First, we write the augmented matrix, writing 0 for the missing y-term in the last equation. Our goal is to find a row-equivalent matrix of the form

  8. Example continued New row 1 = row 2 New row 2 = row 1

  9. Example continued • We multiply the first row by 2 and add it to the second row. • We also multiply the first row by 4 and add it to the third row.

  10. Example continued We multiply the second row by 1/5 to get a 1 in the second row, second column.

  11. Example continued We multiply the second row by 12 and add it to the third row.

  12. Example continued Now, we can write the system of equations that corresponds to our last matrix.

  13. Example continued • We back-substitute 3 for z in equation (2) and solve for y.

  14. Example continued • Next, we back-substitute 1 for y and 3 for z in equation (1) and solve for x. • The triple (2, 1, 3) checks in the original system of equations, so it is the solution.

  15. Row-Echelon Form 1. If a row does not consist entirely of 0’s, then the first nonzero element in the row is a 1 (called a leading 1). 2. For any two successive nonzero rows, the leading 1 in the lower row is farther to the right than the leading 1 in the higher row. 3. All the rows consisting entirely of 0’s are at the bottom of the matrix. If a fourth property is also satisfied, a matrix is said to be in reduced row-echelon form: 4. Each column that contains a leading 1 has 0’s everywhere else.

  16. Example Which of the following matrices are in row-echelon form? a) b) c) d)

  17. Gauss-Jordan Elimination • We perform row-equivalent operations on a matrix to obtain a row-equivalent matrix in row-echelon form. We continue to apply these operations until we have a matrix in reduced row-echelon form. .

  18. Gauss-Jordan Elimination Example • Example: Use Gauss-Jordan elimination to solve the system of equations from the previous example.

  19. Gauss-Jordan Elimination continued We continue to perform row-equivalent operations until we have a matrix in reduced row-echelon form.

  20. Gauss-Jordan Elimination continued Next, we multiply the second row by 3 and add it to the first row.

  21. Gauss-Jordan Elimination continued • Writing the system of equations that corresponds to this matrix, we have We can actually read the solution, (2, 1, 3), directly from the last column of the reduced row-echelon matrix.

  22. Special Systems • When a row consists entirely of 0’s, the equations are dependent and the system is equivalent.

  23. Special Systems • When we obtain a row whose only nonzero entry occurs in the last column, we have an inconsistent system of equations. For example, in the matrix the last row corresponds to the false equation 0 = 9, so we know the original system has no solution.

  24. Another Example Solve the system of equations using Gaussian elimination. x + 3y – 6z = 7 2x – y + 2z = 0 x + y + 2z = -1

  25. Yet Another Example Solve the system of equations using Gaussian elimination. x + 2y = 1 2x + 4y = 3

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