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The Mole Concept: “How Chemist’s Measure” and Stoichiometry : “Balancing of Chemical Rxns ”

The Mole Concept: “How Chemist’s Measure” and Stoichiometry : “Balancing of Chemical Rxns ”. Ch# 3, Ch#7, Ch#9. I. Chemistry = Quantitative Science. Quantitative : Analyze/describe via definite numeric results. Ex:___________________

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The Mole Concept: “How Chemist’s Measure” and Stoichiometry : “Balancing of Chemical Rxns ”

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  1. The Mole Concept: “How Chemist’s Measure”and Stoichiometry: “Balancing of Chemical Rxns” Ch# 3, Ch#7, Ch#9

  2. I. Chemistry = Quantitative Science • Quantitative: Analyze/describe via definite numeric results. Ex:___________________ • Qualitative: Analyze via nonnumeric or descriptive results (words) Ex:____________________ • We measure the amt. of matter to do calculations relating quantities of reactants to products to chemical equations. REACTANTS PRODUCTS Yields

  3. D. We often use very small and very large numbers in chemistry. E. Scientific notation is a method to express these numbers in a manageable fashion. -Thus 0.000 000 1 cm can be written 1 x 10-7 cm. • Scientific notation expresses a number as the • product of two factors, the first falling between 1 and 10 and the second being a power of 10.

  4. Format is Mantissa x Base Power Decimal part of original number Decimal you moved 6.02 x 1023 We just move the decimal point around. 602000000000000000000000

  5. G. Converting into scientific notation: • Move decimal until there’s 1 digit to its left. Places moved = exponent. • If number converting is: • Large # (>1)  positive exponent • Small # (<1)  negative exponent • Only include sig. figs. 2,500,080,000 0 . 0 0 0 0 2 2 0 5

  6. H. Powers of 10 to know: Metric • 0.000 000 001 or • 0.000 001 or • 0.001 or • 0.01 or • 0.1 • 1000 or

  7. Symbols Used in Chemical Equations “Yields”; indicates result of reaction Used to indicate a reversible reaction A reactant or product in the solid state; also used to indicate a precipitate Alternative to (s), but used only to indicate a precipitate A reactant or product in the liquid state A reactant or product in an aqueous solution (dissolved in water) A reactant or product in the gaseous state (s) (l) (aq) (g)

  8. Additional Symbols Used in Chemical Equations Alternative to (g), but used only to indicate a gaseous product Reactants are heated Pressure at which reaction is carried out, in this case 2 atm Pressure at which reaction is carried out exceeds normal atmospheric pressure Temperature at which reaction is carried out, in this case 0 oC Formula of catalyst, in this case manganese (IV) oxide, used to alter the rate of the reaction , NOT CONSUMED Example: H2O2(aq)H2O (l) + O2 (g) D 2 atm pressure 0 oC MnO2 MnO2

  9. II. Measuring Matter • Measure by: • Counting (How many Ss are in this class?) • Weighing (Au sells for $25/gram) • Volume (The National Ave. for gas is $3.05/gal) • Sometimes by each (bananas10¢/ea , by lb., by quart) • Chemists needed a counting unit: mole = Amt. of Substance

  10. III. The Mole (Counting) • Matter is made of Particles: (Representative) • Elements = Atoms • Ionic Cmpds = Formula unit (3D/ Cube) • Molecular Cmpds = Molecules • 1 mole is the amount of substance that contains as many particles (atoms or molecules) as there are in 12.0 g of C-12. • Count them using Avagadro’s Number: • Dozen (doz) eggs = 12 eggs • 1 mole = 6.02 X 1023 Particles

  11. Pics of Particles/Pieces

  12. 3. Amedeo Avagadro (1766-1856) – Italian scientist & lawyer who first tried to experimentally determine the # of particles in a mole. • never knew his own number; • it was named in his honor by a French scientist in 1909. • its value was first estimated by Josef Loschmidt, an Austrian chemistry teacher, in 1895.

  13. How Big is a Mole? One mole of marbles would cover the entire Earth (oceans included) for a depth of two miles. One mole of $1 bills stacked one on top of another would reach from the Sun to Pluto and back 7.5 million times. It would take light 9500 years to travel from the bottom to the top of a stack of 1 mole of $1 bills.

  14. 1 mol = molar mass 1 mole = 22.4 L @ STP 1 mol = 6.02 x 1023 particles Welcome to Mole Island

  15. Mass, Volume, Mole Relationship

  16. IV. Particle Conversions: A. Particles  Moles & Moles Particles • How many moles of Mg is 3.01X1022 Atoms of Mg? Unknown = Known = Conv: Soln: 3.01 x 1022 Atoms MgX 1 Mol Mg 6.02 x 1023Atoms Mg = 5.00 X 10-2 Mol Mg

  17. 2. How many moles are 1.20 X 1025 atoms of phosphorus? 3. How many atoms are in 0.750 mol of zinc?

  18. 4. How many molecules are there in 4.00 mol of glucose, C6H12O6? Atoms, F. U.’s, or Molecules

  19. B. Analogy: Have a doz. packages of pencils. How many pencils do you have? 8 in a package = 8 x 12 = 96 C. To find the # of atoms in a Mol of a cmpd, must determine the # of atoms in a representative formula of that cmpd. • How many Fluoride ions are in 1.46 mol of aluminum fluoride?

  20. How many ammonium ions are in 0.036 mol ammonium phosphate? • How many C atoms are in a mixture of 3.00 mol C2H2 and 0.700 mol CO?

  21. V. Mole (Mass/Weight) • Learned - mass of a single atom is given in amu (atomic mass units). • Gram Atomic Mass (gam) – # of grams of an element numerically equal to amu (we will use the entire #). Ex. C (gam) = 12.01115 g/mol (grams/mole) H (gam) = 1.0079 g/mol • The gam = 1 mole = 6.02 x 1023 particles for a mono-atomic element!!!

  22. 1 Mole of Particles Do They look alike ? Do you think they will have the same mass if 1 mole?

  23. Ex. What is the mass of 1 mol of each of these monatomic elements? • Sodium b. Arsenic c. Uranium • What is the mass of 1 mole of a cmpd? • Formula of a cmpd tells us the # of atoms of each element in a rep. particle of that cmpd. • Calculate the gram molecular mass (gmm) or gram formula mass (gfm) by adding together the atomic masses of the atoms making up a molecule or F.U.

  24. Examples: Sulfur Trioxide: Ammonium Phosphate: Aluminum Sulfate:

  25. gam, gfm, & gmm are commonly referred to as molar mass in chemistry. (1 mol= mass from pd table= 6.02x1023 parts) • Mole  Mass (g) Conversions use Molar Mass • Molar mass of an element or cmpd is used to convert grams of a substance into moles and vice versa. • Examples: • How many grams are in 7.20 mol of dinitrogen trioxide?

  26. Find the number of moles in 922g of iron (III) oxide. • What is the mass of 2.65 x 1024 molecules of Carbon Tetrachloride?

  27. A sample of chlorous acid has a mass of 3500.1 grams, how many representative particles are present in this sample?

  28. Each substance is a mole, so why do they look so different?

  29. One mole each of a solid, a liquid, and a gas: . One mole of NaCl(the solid) mass = 58.45 g One mole Water, mass= 18.0 g occupies a volume of 18.0 mL. One mole of the O2 gas has a mass of 32.0 g & 22.4L volume

  30. VI. Mole (Volume of A Gas) • Volumes of moles of different substances can be different. • Vol of a mole of gas is much more predictable. • Vol of a gas is measured at STP (Standard Temperature & Pressure) • Standard Temp = 0oC • Standard Pressure = 1 atm (atmosphere) How do we measure pressure?

  31. At STP, 1 mol of any gas occupies a vol of 22.4 L aka molar volume of a gas. 1 mol = 6.02 x 1023 P = Molar Mass ? = 22.4L • Problems: • Determine the volume, in liters, of 0.600 mol of SO2 gas at STP.

  32. Determine the number of moles in 333.6 mL of He gas.

  33. What is the volume at STP for 3.25 x 1024 molecules of CO2 gas?

  34. Homework Problems: 1. What is the vol at STP of 0.960 mol CH4? 2. Determine the vol (in L) of 127.80 g of Titanium (II) Oxide gas.

  35. VII. Calculating Percent Composition • When a new cmpd is made in a laboratory, we need to determine its formula. • So we use percent composition which is simply finding the percent (%) by mass of each element in a compound. • The % comp includes as many %’s as there are elements in the cmpd.

  36. For Example: K2CrO4 % comp: 40.3% K, 26.8% Cr, & 32.9% O(∑=100%) D. Percent Composition Formula: is the # of grams of the element divided by the grams of the cmpd, multiplied by 100% Or % Comp = grams of element x 100% grams of cmpd We Can Use This Formula 2 Ways!!!!

  37. Most Common Use:

  38. Example Problems: (given g amts < or > 1 mol  use #’s directly) • An 8.20 g piece of Mg combines completely w/ 5.40 g of O to form a cmpd. What is the % comp of this cmpd?

  39. Calculate the % comp of ethane, C2H6. (Given no #’s so you assume 1 mol & use molar mass)

  40. VIII. Determining Formulas from % Comp: • Empirical Formula: formula showing the smallest whole number ratio of elements present. C6H12O6 = Molecular Formula CH2O = Empirical Formula

  41. B. Finding Empirical Formula: 1. Find % Composition: -Unknown has 63% Mn & 37% O 2. Convert % to moles:(Assume 100g sample) Mn: 63 g Mn x 1 mole Mn = 1.1 mole Mn 54.9 g Mn O:

  42. 3. Convert Moles to Whole Numbers: Method: divide all molar amounts by the smallest molar amount Mn:1.1 mol Mn = 1 mol Mn 1.1 MnO2 O:2.3 mol O = 2.1 mol O 1.1 Rule: round #’s to nearest whole # unless…. If answer is 0.4, 0.5, 0.6 then double ALL!

  43. Practice Problem 1 Given the following data, find the correct empirical formula: 49.0% C, 2.70% H, 48.2% Cl

  44. Practice Problem 2 Given the following data find the empirical formula: N = 26.2%, H = 7.50%, Cl = 66.4%

  45. C. Molecular Formula: • First find the empirical formula. • Then compare the formula mass for your empirical formula with the formula mass for the molecular formula. • You may have to multiply the subscripts in your empirical formula by some factor.

  46. Example #1: Given: 38.7% C, 9.70% H, 51.6% O and a Molecular mass of (gmm=62.0g) find the true molecular formula: 1.Empirical Formula: 2. gmm of E.F.: 3. Divide Masses: 4. Multiply E.F. by Factor:

  47. Practice Problem #2 Given the following data, find the correct molecular formula: 24.3% C, 4.1% H, 71.6% Cl: gmm = 99.0g

  48. Practice #3 Given the following data, find the correct molecular formula: 54.6% C, 9.00% H, 36.4% O and gmm: 176g

  49. IX. Balancing Chemical Equations • All equations we have written have been correct in Qualitative sense but not Quantitative. • Equation must be balanced so that they are quantitatively correct. --balanced equation: each side of the equation has the same number of atoms of each element. Law of Conservation of Mass!!! Atoms can’t be created or destroyed just REARRANGED!

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