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Conservation of Energy Physics Problem Solution

Solve a physics problem involving velocity, mass, and energy conservation with a bullet and block collision. Understand momentum and energy calculations in a real-world scenario. Practice solving physics equations to determine post-collision variables accurately.

micah-mercado
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Conservation of Energy Physics Problem Solution

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  1. Quandary v = 0 m/s m = 845 grams Before v = 560 m/s m = 100. grams Block O Wood bullet v = ??? After • Calculate: • Velocity after • Total energy before • Total energy after • (1/2mv2) Bullet and Block combo

  2. So for momentum, the equation looks like (.1 kg)(560 m/s) = (.845 kg)v, so v = 59.25925926 Energy before is ½(.1 kg)(560 m/s)2 = 15,680 J Energy after is ½(.945 kg)(59.25925926 m/s)2 = 1659.259259 J (The repeating decimal is creepy) So energy is conserved, just not kinetic energy. Some of the original kinetic energy turns to sound and heat.

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