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Combustion analysis

Explore the process of combustion analysis and various reactions, including the synthesis of acetic acid, ethanol, iron(III) oxide with aluminum, and titanium(IV) chloride, with detailed molecular formulas and weights provided.

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Combustion analysis

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  1. Combustion analysis 1 mol CO2 44 g CO2 1 mol C atoms 1 mol CO2 = 0.10 mol C atom 4.40 g CO2 1 mol H2O 18 g H2O 2 mol H atoms 1 mol H2O = 0.20 mol H atom 1.80 g H2O 3.00g = weight O + weight C + weight H weight O = 3.00g - weight C weight H weight O = 3.00g – 12g/mol(0.1molC) – 1g/mol(0.2molH) 1 mol O atom 16 g O = 1.60 g O = 0.10 mol O atom

  2. Combustion analysis (cont) Empirical formula: CH2O Original molecular weight: 180 g/mol Formula weight of CH2O: 30 g/mol 6 CH2O units required to get to formula weight. Thus the molecular formula is: C6H12O6

  3. Acetic Acid and Ethanol 1 mol acetic 60 g acetic 1 mol ester 1 mol acetic 88g ester 1 mol ester = 6.16g ester 4.20 g Acetic Total of 6.16 g of ethyl acetate can be made from this reaction

  4. Iron(III) Oxide + Aluminum 1 mol Fe2O3 159.7 g Fe2O3 2 mol Fe 1 mol Fe2O3 55.84g Fe 1 mol Fe = 106 g Fe 152 g Fe2O3 1 mol Al 26.98 g Al 2 mol Fe 2 mol Al 55.84g Fe 1 mol Fe 74.2 g Al = 154 g Fe Thus the Fe2O3 is the limiting reagent

  5. Iron(III) Oxide + Aluminum 1 mol Fe2O3 159.7 g Fe2O3 2 mol Al 1 mol Fe2O3 26.98g Al 1 mol Al = 51.4 g Al 152 g Fe2O3 Aluminum Remaining = Starting – Used Remaining = 74.2 g Al – 51.4 g Al = 22.8 g Al

  6. Titanium(IV) Chloride 1 mol TiO2 79.9 g TiO2 3 mol TiCl4 3 mol TiO2 189.7gTiCl4 1 mol TiCl4 = 9.82 g TiCl4 4.15 g TiO2 189.7gTiCl4 1 mol TiCl4 1 mol C 12.01 g C 3 mol TiCl4 4 mol C 5.67 g C = 67.2 g TiCl4 1 mol Cl2 70.9 g Cl2 3 mol TiCl4 6 mol Cl2 189.7gTiCl4 1 mol TiCl4 6.78 g Cl2 = 9.07 g TiCl4 Thus the Cl2 is the limiting reagent.

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