1 / 12

Week 12 day 1

•. Week 12 day 1. The graph shows the height of a tennis ball from the time it is served to the time it hits the ground on the other side of the net. How many seconds elapse while the ball is 7 feet or more above the ground?. 8. 6. height (ft). 4. 2. 0. .2. .4. .6. .8. 1.0.

merritt-pickett
Download Presentation

Week 12 day 1

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. • Week12 day 1 The graph shows the height of a tennis ball from the time it is served to the time it hits the ground on the other side of the net. How many seconds elapse while the ball is 7 feet or more above the ground? 8 6 height (ft) 4 2 0 .2 .4 .6 .8 1.0 1.2 1.4 1.6 1.8 time (s) Record your answer and be sure to use the correct place value. 2

  2. 8.2 Special Right Triangles

  3. 450 s2 s 450 s 450-450-900 Triangle Theorem  In a 450-450-900 triangle, both legs are congruent and the length of the hypotenuse is 2 times the length of a leg. hypotenuse =2leg Pardekooper

  4. Lets try a problem 450 h 450 9 h=92 h=12.72 Pardekooper

  5. Lets try one more 450 22 h 450 h=222 h=4 Pardekooper

  6. Here’s one for baseball. A high school baseball diamond is a square. The distance from base to base is 90 ft. To the nearest foot, how far does the catcher throw the ball from home plate to second base ? 90 ft. x=902 x ft. x=126.9 x=127 Pardekooper

  7. 600 2s s 300 s3 300-600-900 Triangle Theorem In a 300-600-900 triangle, the length of the hypotenuse is twice the length of the shorter leg. The length of the longer leg is 3 times the length of the shorter leg.. hypotenuse =2shorter leg longer leg= 3shorter leg Pardekooper

  8. Lets try a problem 600 h 5 300 l h=2s l=s3 h=2(5) l=53 h=10 l=8.65 Pardekooper

  9. Here’s another 600 8 s 300 l l=s3 h=2s 8=2s l=43 2 2 l=6.92 4=s Pardekooper

  10. Just one more a 72 c 450 300 d b a=14 c=7 d=7 b=12.11 h=2s h=s2 h=2(7) h=72 h=14 s=7 l=s3 l=73 Pardekooper l=12.11

  11. Workbook P. 399 Pardekooper

  12. Assignment Workbook Page 399 all

More Related