1 / 11

Linear-time Median

Linear-time Median. Def: Median of elements A=a 1 , a 2 , …, a n is the (n/2)-th smallest element in A. How to find median? sort the elements, output the elem. at (n/2)-th position - running time ?. Linear-time Median.

mckeel
Download Presentation

Linear-time Median

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Linear-time Median Def: Median of elements A=a1, a2, …, an is the (n/2)-th smallest element in A. • How to find median? • sort the elements, output the elem. at (n/2)-th position • - running time ?

  2. Linear-time Median Def: Median of elements A=a1, a2, …, an is the (n/2)-th smallest element in A. • How to find median? • sort the elements, output the elem. at (n/2)-th position • - running time: (n log n) • we will see a faster algorithm • - will solve a more general problem: • SELECT ( A, k ): returns the k-th smallest element in A

  3. Linear-time Median Idea: Suppose A = 22,5,10,11,23,15,9,8,2,0,4,20,25,1,29,24,3,12,28,14,27,19,17,21,18,6,7,13,16,26

  4. Linear-time Median • SELECT (A, k) • split A into n/5 groups of five elements • let bi be the median of the i-th group • let B = [b1, b2, …, bn/5] • medianB = SELECT (B, B.length/2) • rearrange A so that all elements smaller than • medianB come before medianB, all elements • larger than medianB come after medianB, and • elements equal to medianB are next to medianB • 6. j1,j2 = the first and the last position of • medianB in rearranged A • 7. if (k < j1) return SELECT ( A[1…j1-1], k ) • 8. if (k ¸ j and k · j2) return medianB • 9. if (k > j2) return SELECT ( A[j2+1…n], k-j2 )

  5. Linear-time Median Running the algorithm:

  6. Linear-time Median Running the algorithm: Rearrange columns so that medianB in the “middle.” Recurrence:

  7. Linear-time Median Recurrence: T(n) < T(n/5) + T(3n/4) + cn T(n) < c if n > 5 if n < 6 Claim: There exists a constant d such that T(n) < dn.

  8. Randomized Linear-time Median Idea: Instead of finding medianB, take a random element from A. • SELECT-RAND (A, k) • x = ai where i = a random number from {1,…,n} • rearrange A so that all elements smaller than • x come before x, all elements larger than x • come after x, and elements equal to x are • next to x • 3. j = position of x in rearranged A (if more • x’s, then take the closest position to n/2) • 4. if (k < j) return SELECT-RAND ( A[1…j-1], k ) • 5. if (k = j) return medianB • 6. if (k > j) return SELECT-RAND ( A[j+1…n], k-j)

  9. Randomized Linear-time Median Worst case running time: O(n2). • SELECT-RAND (A, k) • if A.length < 1: return • x = ai where i = a random number from {1,…,n} • rearrange A so that all elements smaller than • x come before x, all elements larger than x • come after x, and elements equal to x are • next to x • 3. j1,j2 = the first and the last position of • x in rearranged A • 4. if (k < j1) return SELECT-RAND(A[1…j1-1], k) • 5. if (k ¸ j1 and k · j2) return x • 6. if (k > j2) return SELECT-RAND(A[j2+1…n], k-j)

  10. Randomized Linear-time Median Worst case running time: O(n2). Claim: Expected running time is O(n).

  11. Master Theorem • Let a ¸ 1 and b>1 be constants, f(n) be a function and for positive integers we have a recurrence for T of the form • T(n) = a T(n/b) + f(n), • where n/b is rounded either way. • Then, • If f(n) = O(nlog a/log b - e) for some constant e> 0, then • T(n) = (nlog a/log b). • If f(n) = (nlog a/log b), then T(n) = (nlog a/log blog n). • If f(n) = (nlog a/log b + e) for some constant e > 0, and if af(n/b) · cf(n) for some constant c < 1 (and all sufficiently large n), then • T(n) = (f(n)).

More Related