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Physics of Inclined Plane: Box Rest or Accelerate?

Explore the forces on a 10kg box on a 37-degree inclined plane to determine if it will stay at rest or accelerate. Calculate normal force, friction, and net force.

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Physics of Inclined Plane: Box Rest or Accelerate?

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  1. A 10kg wooden box is placed on a wooden inclined plane that forms an angle of 37 degrees with the horizontal. Will the box stay at rest or accelerate? 10kg 37˚

  2. FW=100N 37˚

  3. FN=? FW=100N 37˚

  4. FN=? 37˚ Fperpendicular=FW ·cos(37˚) FW=100N Fparallel=FW ·sin(37˚) 37˚

  5. FN=? Ffriction=? 37˚ Fperpendicular=FW ·cos(37˚) FW=100N Fparallel=FW ·sin(37˚) 37˚

  6. FN=? Fperpendicular=FW ·cos(37˚) Ffriction=? 37˚ Fperpendicular=FW ·cos(37˚) FW=100N Fparallel=FW ·sin(37˚) 37˚

  7. FN=? Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚) Ffriction=? 37˚ Fperpendicular=FW ·cos(37˚) FW=100N Fparallel=FW ·sin(37˚) 37˚

  8. FN=? Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚

  9. FN=? Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚

  10. FN=80N Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular=80N Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚

  11. FN=80N Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular=80N Ffriction=? Fparallel=FW ·sin(37˚) 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚

  12. FN=80N Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular=80N Ffriction=? Fparallel=FW ·sin(37˚) Fparallel=100N·sin(37˚) 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚

  13. FN=80N Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular=80N Ffriction=? Fparallel=FW ·sin(37˚) Fparallel=100N·sin(37˚)=60N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚

  14. FN=80N Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚

  15. FN=80N Ffriction=μ· FN Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚

  16. FN=80N Ffriction=μ· FN Ffriction= 0.42· 80N Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚

  17. FN=80N Ffriction=μ· FN Ffriction= 0.42· 80N=34N Ffriction=34N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚

  18. FN=80N Ffriction=34N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚

  19. FN=80N Fnet=Fparallel-Ffriction Fnet=60N-34N=26N Ffriction=34N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚

  20. FN=80N Fnet=Fparallel-Ffriction Fnet=60N-34N=26N Ffriction=34N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚

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