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This course content focuses on the essential topics in kinematics, covering motion descriptions, displacement, velocity, and acceleration. Students will explore one-dimensional motion through practical examples, including ball trajectories and free-fall acceleration. The module emphasizes understanding velocity as instantaneous and average, as well as grasping the kinematic equations for constant acceleration. Additionally, students will engage in labs and homework assignments designed to reinforce their understanding of motion through real-world applications and problem-solving frameworks.
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PHSX213 class • Questions from last time ? • Note: Labs today for some of you. • The web-site has a link to the eGradePlus resources. You should register and check this out. • Warm-ups may be posted there. • HW2 should appear soon. • Hand-outs: syllabus, course info., problem 3.24 solution, doing problems resources. • Describing Motion (Kinematics) • Chapter 2 leading into 4.
Kinematics: Special Case (1-D) Up-down Ball • Reference frame • Origin, (x, y, z)-axes • Position Vector, x = x i • Displacement, ≡ Dx = x2 – x1 • Instantaneous Velocity, v≡ d x /dt • Instantaneous Acceleration, a ≡ d v/dt ≡ d2 x /dt2 ^ → Draw graphs → → → → → → → →
What does all this mean ? • Position • Displacement (change in position over a time interval) • Velocity • Is synonymous (to me) with instantaneous velocity • average velocity, vave≡ Dr / Dt • Speed = magnitude of the velocity. • Acceleration • Instantaneous acceleration • average acceleration, aave≡ Dv / Dt • Can something traveling with constant speed be accelerating ?
Meter stick • Reaction time measurement
Draw graphs • 1) car (moving with constant speed) • 2) ball • 3) ball off ledge
Kinematic Equations • In general. • Will be useful for lab project, MX • Specific case of CONSTANT acceleration • v = v0 + a t • x – x0 = v0 t + ½ a t2 • v2 = v02 + 2 a (x – x0)
Free-Fall Acceleration • Falling Objects – Galileo • In the absence of air resistance, objects fall with the same acceleration, g, ≈ 9.8 m/s2 near the surface of the Earth. • We will return, to understand gravity in Ch. 13. • See Penny and Feather Video Experiment 2.2 • In vacuum, penny and feather hit ground at same time • Paper Demo • Glycerin Demo (will do this in next class) • Acceleration is not constant. Table 2.1 eqns don’t apply. • Use method of section 2.8 but with a(t).
Let’s say the dollar bill fell 16 cm before Jennifer tried to catch it. Calculate her reaction time. ( g = 9.8 m/s2 ) y – y0 = v0 t + ½ a t2 y0 = 0, v0 = 0, a = -g, y = -0.16 m So, t2 = - 2 y / g = (- 2 ) (-0.16) / (9.8) = 0.03265 s2 So, t = 0.1807 s = 0.18 s (only 2 sig. figs justified) Falling Dollar/Meter Stick/Reaction time Check dimensions Check if reasonable
Another constant acceleration example • Sample problem 2.7 is quite instructive. • A pitcher tosses a baseball up with an initial speed of 12 m/s • How long does the ball take to reach its maximum height ? • What is the ball’s maximum height ? • How long does it take to reach a height of 5.0 m ?
More about x, v, a graphs • From calculus, we know that • i) the slope of the graph is the first derivative. • So eg. x(t) vs t. The slope is dx/dt = v • v(t) vs t. The slope is dv/dt = a • ii) similarly, we know the area under the curve is the integral. • So eg. a(t) vs t. Area is ∫ a(t) dt = D v • v(t) vs t. Area is ∫ v(t) dt = D x
Which position-versus-time graph goes with this velocity-versus-time graph on the left? The particle’s position at ti = 0 s is xi = –10 m .
Which position-versus-time graph goes with this velocity-versus-time graph on the left? The particle’s position at ti = 0 s is xi = –10 m .
Kinematics: General Case (3-D) • Reference frame • Origin, (x, y, z)-axes • Position Vector, r = x i + y j + z k • Displacement, ≡ Dr = r2 – r1 • Instantaneous Velocity, v≡ d r /dt • Instantaneous Acceleration, a ≡ d v/dt ≡ d2 r /dt2 ^ ^ ^ → → → → → → → → →
Next time • Projectiles • Uniform Circular Motion • Remember HW1 !