Work Problems

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# Work Problems - PowerPoint PPT Presentation

Work Problems. Chapter 14.1. In the equation for work, F is the___________ applied to the object and d is the _________ through which the force is applied. Force. DISTANCE. A boy lifts a 30N dragon 2 meters above the ground. How much work did the boy do on the dragon?. W= F x D

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## PowerPoint Slideshow about 'Work Problems' - mallory-slater

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### Work Problems

Chapter 14.1

In the equation for work, F is the___________ applied to the object and d is the _________ through which the force is applied.

Force

DISTANCE

### A boy lifts a 30N dragon 2 meters above the ground. How much work did the boy do on the dragon?

W= F x D

W= 30N x 2m

W=60J

Work = Force x Distance

Nothing moved so no work is done!

Which of the following is having work done on it?
• a grocery bag as you lift it up
• a crane moving dirt
• a crate as you push it along the floor
• a car parked on a ramp
• Yes
• Yes
• Yes
• No, nothing is moving!

Suppose you want to calculate how much work it takes to lift a 160 N barbell. Besides the mass of the barbell, what other information do you need to know?

• the shape of the weights
• how high the barbell is being lifted
• the strength of the person doing the lifting
• No
• Yes, how far does it move!
• no
If you are in a car that is being pulled down a 56.0 m path with a force of 12.5 Newton’s (N), what is the “work” done on the car?
• W = F x D
• F = 12.5N
• D = 56m
• W = FxD
• W=12.5N x 56m

W = 700J

A crane does work of 13,500 J with a force of 5200 N to lift a beam. How far can the beam be lifted (in meters)?
• D=W/F
• W = 13500J
• F = 5200N

D =13500J

5200N

D = 2.60m

A 600 kg great white shark is lurking below an observation cage. His movement is being studied from a series of motion sensors below the boat. The shark leisurely charges the cage, strikes it and makes the cage rattle. Later, the shark returns for another run at the cage. The shark strikes the cage with 12,800 N of force. The shark traveled for 10 m in making its run. The cage is designed to withstand 124,500 J of “work” before it breaks. Should the man in the cage be worried?

F = 12800N

D = 10m

W= 12800N x 10m

W = 128000J