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Dive into Bertrand's Paradox, a fascinating problem in probability theory that challenges traditional assumptions and offers valuable insights. Explore its implications and solutions for a deeper understanding of randomness and chance.
E N D
-1 1
D A -1 1
1/2 π/3 -1 1
D A -1 1 0 < D < ½ π/3 < A < π/2
P(E) = P(D < ½) = ½ D A -1 1 0 < D < ½ π/3 < A < π/2
P(E) = P(D < ½) = ½ P(E) = P(A > π/3) = 1/3 D A -1 1 0 < D < ½ π/3 < A < π/2