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## Graph

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**1.**- y – 3 = x 2 3 Warm Up Graph 2. Find the slope of the line that passes through (5, 2) and (-5, -3).**Graphing Equations in Standard Form**Step 1: Find the x-intercept by letting y = 0 and solving for x. Plot (x, 0) Step 2: Find the y-intercept by letting x = 0 and solving for y. Plot (0, y). Step 3: Draw a line through the two points .**Example 3**( ( ) ) 3 2 0 0 Let x = 0 Graph 3x + 2y = 12 + 2y 12 = Let y = 0 3x + 12 = Draw Quick Graphs STEP 1 Find the x-intercept. 3x = 12 3 3 x = 4 The x-intercept is 4, so plot the point (4, 0). STEP 2 Find the y-intercept. 2y = 12 2 2 y = 6 The y-intercept is 6, so plot the point (0, 6). STEP 3 Draw a line through the intercepts.**Example 3**Graph 3x + 2y = 12 Short cut version**Checkpoint**1. x + y 2 = Draw Quick Graphs Graph the equation.**Checkpoint**5x + 2y 10 = 2. Draw Quick Graphs Graph the equation.**Graphing x = #**Ex. Graph x = -3 The x coordinate is -3 no matter what the value of y is. • Choose any value of y • • • So, the graph of x = # is always a VERTICAL LINE**Ex. Graph x = 4**The graph of x = 4 is VERTICAL LINE at 4.**Graphing y = #**Ex. Graph y = 2 The y coordinate is 2 no matter what the value of x is. Choose any value of x • • • • So, the graph of y = # is always a HORIZONTAL LINE**Ex. Graph y = -4**The graph of y = -4 is HORIZONTAL LINE at -4.**Homework:**WS: Graphing Equations in Standard Form