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# 和数形结合思想解题 - PowerPoint PPT Presentation

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## PowerPoint Slideshow about '和数形结合思想解题' - lorne

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A（x1,y1)、B（ x 2 ,y2 )两点，求x1y2 - 3x2y1的值。

∴ x1y2- 3x2y1

=x1(-y1)-3(- x1y1)

=2x1y1= -10.

y

B

P

o

x

C

P(x,y),C(- x , - y), B(0,y)

（数）

（形）

⊿ABD的面积=

⊿BCD的面积

Y=k1x

A

Y=k2x

B

， 求 的值。

P

A

O

B

Q

P

A

O

B

E

F

Q

y

B

P

o

x

C

P

A

O

B

E

F

Q

6

6

- 6

-6

x

（形）

（数）

Y=-x+3,双曲线和直线的交点的横坐标就是原方程

A. 3个 B.2个 C.1个 D.0个

（形）

（数）

F

E

=OA OC

=2DF 2DE

=4DFDE

=4 2

=8

=