2writing evaluating and finding equivalent expressions with rational numbers part 2
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2Writing, Evaluating, and Finding Equivalent Expressions with Rational Numbers Part 2. 2π‘₯ + 2(π‘₯ – 6) . 4π‘₯ – 16 . 1(π‘₯ + 2) + 2(π‘₯ – 2) . 4(3 – π‘₯) . 4(2π‘₯ + 1) – 12π‘₯ . 3π‘₯ – 6 . Show tape diagram. What is the process to find a percent of a number without using a tape diagram?

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2writing evaluating and finding equivalent expressions with rational numbers part 2

2Writing, Evaluating, and Finding Equivalent Expressions with Rational Numbers Part 2









2writing evaluating and finding equivalent expressions with rational numbers part 2

  • What is the process to find a percent of a number without using a tape diagram?

  • Under what circumstances would you prefer to use a tape diagram to help you calculate the percent of a number?

  • When the original price is not known, how can an expression be used to represent the new price?

  • When a discount of 20% is being deducted, what percent is being paid? How do you know?

  • How is π‘₯ βˆ’ 0.2π‘₯ = 0.8π‘₯?

  • Describe the meaning of π‘₯ βˆ’ 0.2π‘₯ = 0.8π‘₯ in the context of the problem.


2writing evaluating and finding equivalent expressions with rational numbers part 2

  • An item that has an original price of π‘₯ dollars is discounted 33%.

  • a. Write an expression that represents the amount of the discount.

  • b. Write two equivalent expressions that represent the new, discounted price.

  • c. Use one of your expressions to calculate the new, discounted price if the original price was $56.

  • d. How would the expressions you created in parts (a) and (b) have to change if the item’s price had increased by 33% instead of discounted 33%?



2writing evaluating and finding equivalent expressions with rational numbers part 2


2writing evaluating and finding equivalent expressions with rational numbers part 2

Describe the meaning of the expression (π‘₯ βˆ’0.20π‘₯)? many parts would the tape diagram need to be broken? Explain how you knew that.

Describe why ((π‘₯ βˆ’ 0.20π‘₯) + 0.08(π‘₯ βˆ’ 0.20)) is equivalent to 1.08(π‘₯ βˆ’ 0.20π‘₯)

Describe why (π‘₯ βˆ’ 0.20π‘₯) + 0.08(π‘₯ βˆ’ 0.20π‘₯) and 1.08(π‘₯ βˆ’ 0.20π‘₯) are equivalent to 1.08(0.80π‘₯).


2writing evaluating and finding equivalent expressions with rational numbers part 2