PRESS F5 TO START. This presentation contains Intermediate 2 past paper questions complete with solutions for the year 2003. The questions are sorted into topics based on the specific outcomes for the Intermediate 2 course.
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This presentation contains Intermediate 2 past paper questions complete with solutions for the year 2003.
The questions are sorted into topics based on the specific outcomes for the Intermediate 2 course.
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b = 2 ( period = 360 ÷ 2 = 180
(7 – x)(1 + x)
(b) Roots are; x = 7 and x = -1
(c Turning Point halfway between –1 and 7.
i.e. x = 3
So y = 7 + (6 x 3) – (32)
= 7 + 18 – 9
Coords of Max T.P. (3,16)
PLJ = 90° – 47° = 43°
PKL = 90° (angle in a semi circle)
PLK = 180° – (90° + 31°) = 59°
KLJ = PLK + PLJ
= 43° + 59° = 102°
=(30 x 46) + (3.14 x 15²)
Volume of prism = Ah
= area of cross section x height
= 2086.5 x 25
= 52162.5 cm³
= 52 000 cm³ (2 sig figs)
(b) So volume of quarter of a cylinder.
Vol = ¼πr2h
30 000 = ¼ x 3.14 x r2 x 20
r2 = 30 000 x 4
3.14 x 20
r = √1910.8 = 43.7cm