Download
the remainder and factor theorems n.
Skip this Video
Loading SlideShow in 5 Seconds..
The Remainder and Factor Theorems PowerPoint Presentation
Download Presentation
The Remainder and Factor Theorems

The Remainder and Factor Theorems

121 Views Download Presentation
Download Presentation

The Remainder and Factor Theorems

- - - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

  1. The Remainder and Factor Theorems

  2. The Remainder Theorem If a polynomial f(x) is divided by (x – a), the remainder is the constant f(a), and f(x) = q(x) ∙ (x – a) + f(a) where q(x) is a polynomial with degree one less than the degree of f(x). Dividend equals quotient times divisor plus remainder.

  3. The Remainder Theorem Find f(3) for the following polynomial function. f(x) = 5x2 – 4x + 3 f(3) = 5(3)2 – 4(3) + 3 f(3) = 5 ∙ 9 – 12 + 3 f(3) = 45 – 12 + 3 f(3) = 36

  4. The Remainder Theorem Now divide the same polynomial by (x – 3). 5x2 – 4x + 3 3 5 –4 3 15 33 5 11 36

  5. The Remainder Theorem 5x2 – 4x + 3 3 5 –4 3 15 33 5 11 36 f(x) = 5x2 – 4x + 3 f(3) = 5(3)2 – 4(3) + 3 f(3) = 5 ∙ 9 – 12 + 3 f(3) = 45 – 12 + 3 f(3) = 36 Notice that the value obtained when evaluating the function at f(3) and the value of the remainder when dividing the polynomial by x – 3 are the same. Dividend equals quotient times divisor plus remainder. 5x2 – 4x + 3 = (5x + 11) ∙ (x – 3) + 36

  6. The Remainder Theorem Use synthetic substitution to find g(4) for the following function. f(x) = 5x4 – 13x3 – 14x2 – 47x + 1 4 5 –13 –14 –47 1 20 28 56 36 5 7 14 9 37

  7. The Remainder Theorem Synthetic Substitution – using synthetic division to evaluate a function This is especially helpful for polynomials with degree greater than 2.

  8. The Remainder Theorem Use synthetic substitution to find g(–2) for the following function. f(x) = 5x4 – 13x3 – 14x2 – 47x + 1 –2 5 –13 –14 –47 1 –10 46 –64 222 5 –23 32 –111 223

  9. The Remainder Theorem Use synthetic substitution to find c(4) for the following function. c(x) = 2x4 – 4x3 – 7x2 – 13x – 10 4 2 –4 –7 –13 –10 8 16 36 92 2 4 9 23 82

  10. The Factor Theorem The binomial (x – a) is a factor of the polynomial f(x) if and only if f(a) = 0.

  11. The Factor Theorem When a polynomial is divided by one of its binomial factors, the quotient is called a depressed polynomial. If the remainder (last number in a depressed polynomial) is zero, that means f(#) = 0. This also means that the divisor resulting in a remainder of zero is a factor of the polynomial.

  12. The Factor Theorem x3 + 4x2 – 15x – 18 x – 3 3 1 4 –15 –18 3 21 18 1 7 6 0 Since the remainder is zero, (x – 3) is a factor of x3 + 4x2 – 15x – 18. This also allows us to find the remaining factors of the polynomial by factoring the depressed polynomial.

  13. The Factor Theorem x3 + 4x2 – 15x – 18 x – 3 3 1 4 –15 –18 3 21 18 1 7 6 0 The factors of x3 + 4x2 – 15x – 18 are (x – 3)(x + 6)(x + 1). x2 + 7x + 6 (x + 6)(x + 1)

  14. The Factor Theorem (x – 3)(x + 6)(x + 1). Compare the factors of the polynomials to the zeros as seen on the graph of x3 + 4x2 – 15x – 18.

  15. The Factor Theorem Given a polynomial and one of its factors, find the remaining factors of the polynomial. Some factors may not be binomials. • x3 – 11x2 + 14x + 80 • x – 8 • 2. 2x3 + 7x2 – 33x – 18 • x + 6 (x – 8)(x – 5)(x + 2) (x + 6)(2x + 1)(x – 3)