Differentiate. g(x) = 4 sec x + tan x

1 / 5

# Differentiate. g(x) = 4 sec x + tan x - PowerPoint PPT Presentation

1. 2. 3. 4. Differentiate. g(x) = 4 sec x + tan x. {image} {image} {image} {image}. 1. 2. 3. 4. 5. Differentiate. &amp;#160;&amp;#160; {image}. {image} {image} {image} {image} {image}. 1. 2. 3. 4. 5. 6.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about 'Differentiate. g(x) = 4 sec x + tan x' - lihua

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

1.

2.

3.

4.

Differentiate. g(x) = 4 sec x + tan x
• {image}
• {image}
• {image}
• {image}

1.

2.

3.

4.

5.

Differentiate. &#160;&#160; {image}
• {image}
• {image}
• {image}
• {image}
• {image}

1.

2.

3.

4.

5.

6.

Find an equation of the tangent line to the curve {image} &#160; at the point ( {image} , -2.5).
• {image}
• {image}
• {image}
• {image}
• {image}
• {image}

A ladder 7 feet long rests against a vertical wall. Let &#160; {image} &#160; be the angle between the top of the ladder and the wall and let x be the distance from the bottom of the ladder to the wall. If the bottom of the ladder slides away from the wall, how fast does x change with respect to &#160; {image} &#160; when &#160; {image} ?

• 1
• 2
• 0.5
• 2.5
• 6.5
• 3.5

1.

2.

3.

4.

A semicircle with diameter sits on an isosceles triangle to form a region shaped like an ice-cream cone, as shown in the figure. If {image} is the area of the semicircle and {image} is the area of the triangle, find {image} {image}

• {image}
• {image}
• {image}
• {image}