1 / 6

Sullivan Algebra and Trigonometry: Section 3.6

Sullivan Algebra and Trigonometry: Section 3.6. Objectives Construct and analyze functions. Example: The price p and the quantity x sold of a certain product obey the demand equation. a.) Express the revenue R as a function of the quantity of items sold (x).

lewisdonald
Download Presentation

Sullivan Algebra and Trigonometry: Section 3.6

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Sullivan Algebra and Trigonometry: Section 3.6 • Objectives • Construct and analyze functions

  2. Example: The price p and the quantity x sold of a certain product obey the demand equation a.) Express the revenue R as a function of the quantity of items sold (x). Revenue = (Price)(Items sold) = (x)(p)

  3. b.) What is the revenue if 150 items are sold? c.) Graph the function R(x) on a graphing utility. d.) Using the graph, find the number of items x that will maximize revenue. What is the maximum revenue? Quantity that maximizes revenue: 200 items Maximum Revenue: $10,000

  4. e. What price should be charge for each item to achieve maximum revenue? Maximum Revenue occurs when x = 200 items Price = $50 should be charged to achieve maximum revenue.

  5. Example: An open box with a square base is to made from a square piece of cardboard 30 inches on a side by cutting out a square from each corner and turning up the sides. a.) Express the volume V of the box as a function of the length x of the side of the square cut from each corner. The volume of a box is given by: V = (length)(width)(height)

  6. x x x x 30 in. x x x x 30in. Length = 30 - 2x Width = 30 - 2x Height = x So, Volume = (30 - 2x)(30 - 2x)(x) c.) Graph V(x) using a graphing utility and estimate what value of x will maximize V. At x = 5 inches, the volume is maximum (2000 cubic inches)

More Related