Create Presentation
Download Presentation

Download Presentation
## JEOPARDY! Algebra 2 – Unit 3 Review

- - - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - - -

**JEOPARDY!**Algebra 2 – Unit 3 Review • All students will pair up with their assigned partner (or a group of three as selected by the teacher) to compete AGAINST EACH OTHER! • All students will play EVERY ROUND and show work on a separate sheet of paper (to be turned in). • Students will keep score together – winner gets bonus credit.**A Picture Is Worth A Thousand Words**Word World! 3’s Company The Basics 100 200 200 100 300 200 500 300 500 400 1000 500 700 We’re Done! Good Luck on the Test!!**100**Solve for x and y: x + 2y = 11 2x – y = 2**x + 2y = 11 x + 2y = 11**(2x – y = 2) 2 4x – 2y = 4 5x = 15 x = 3 100 x = 3, y = 4 or (3, 4)**200**Solve for x and y: x = 2y – 3 y – 3x = –1**x = 2y – 3**y – 3x = –1 y – 3(2y – 3) = –1 -5y + 9 = -1 y = 2 x = 2(2) – 3 = 1 x = 1, y = 2 or (1, 2) 200**400**Solve for x and y: 4x – 3y = 5 8x – 6y = 12**( 4x – 3y = 5 ) –2 –8x + 6y = –10**8x – 6y = 12 8x – 6y = 12 0 = 2 400 Since 0 = 2 can NEVER be true … “NO SOLUTION” !!!**200**The sum of two numbers is 24. The first number is 4 less than the second number. Find the two numbers.**Let x = first number**Let y = second number x + y = 24 x = y – 4 x = 10, y = 14 200**300**Brandon has a pocket full of nickels and dimes. If he has 20 coins worth $1.30 in his pocket, how many of each coin does he have?**300**Let N = # of nickels Let D = # of dimes ( N + D = 20 ) –5 ( .05N + .10D = 1.30 ) 100 N = 14, D = 6**500**Twyla is taking her friends to a concert. Tickets cost $8 for general admission and $10 for reserved seating. If Twyla buys 12 tickets for a total of $102, how many of each kind of ticket did she buy?**500**Let G = # of general tickets Let R = # of reserved tickets ( G + R = 12 ) –8 8G + 10R = 102 G = 9, R = 3**700**The perimeter of a rectangle is 44. If the length is 6 more than the width, then find the length and the width.**Let L = length, W = width**2L + 2W = 44 L = W + 6 Substitute to get … 2(W + 6) + 2w = 44 L = 14, W = 8 700**100**Graph the following and identify the solution: y = 2x – 8 2y + x = 4**y = 2x – 8**2y + x = 4 y = –½ x + 2 100 (4, 0)**300**Graph the following and identify the solution: y 3x – 3 y –2x + 4**y 3x – 3**y –2x + 4 300**500**Graph the following and identify the solution: y –5 x 2 y x + 4**y –5**x 2 y x + 4 500**200**Solve for x, y and z: 3x + 5y + z = 5 x – 2y = –9 2x = –10**3x + 5y + z = 5**x – 2y = –9 2x = –10 200 x = –5 y = 2 z = 10**500**Solve for x, y, and z: 2x – y = 2 2y – z = 8 3x + z = 9**2x – y = 2**2y – z = 8 4x – 2y = 4 3x + z = 9 3x + 2y = 17 7x = 21 500 x = 3 y = 4 z = 0**1000**Solve for x, y and z: x – y + z = –2 3x + 2y + z = 6 2x + 3y – 2z = 10**x – y + z = –2**3x + 2y + z = 6 2x + 3y – 2z = 10 1000 x = 1 y = 2 z = –1