Test for the Population Proportion

1 / 5

# Test for the Population Proportion - PowerPoint PPT Presentation

Test for the Population Proportion. When we have a qualitative variable in the population we might like to know about the population proportion of one of the categories of the variables. For example, with gender we might like to know about the proportion who are female.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## Test for the Population Proportion

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

### Test for the Population Proportion

When we have a qualitative variable in the population we might like to know about the population proportion of one of the categories of the variables. For example, with gender we might like to know about the proportion who are female.

In this context our hypothesis testing will follow a normal distribution and we will calculate a z statistic. We can have one or two-tailed tests. When the sample proportion is p hat = X/n,

The z test stat is (p hat – p under null)/standard error.

The standard error of p= sqrt[(p under null)(1 – p under null)/sample size].

Now, punder null is the hypothesized value of the proportion.

.05

Alpha/2 = .05

Upper Critical z

Lower critical z

Let’s do a problem. Say a magazine claims that 25% of its readers are college students.

Ho: p = .25 (.25 is punder null, here)

Ha: p ≠.25

With a level of significance of .1 and a two-tailed test each tail will have .05. From the z table the critical z’s are – 1.645 and 1.645.

A sample of 200 college students were asked if they read the magazine and the sample proportion that said yes was .21. The z statistic from the sample is

(.21 - .25)/sqrt[(.25)(.75)/200] = - 1.31 and thus we can not reject the null.

Since the z from the sample is – 1.31 and we have a two-tailed test the p-value is 2(.0951)=.1902.

Note the .0951 is the tail area in the z table for a z = -1.31

Zstat = (.22-.20)/sqrt((.2)(.8)/400) = 1.00

The critical values of Z at alpha = .05 with a two tailed alternative are -1.96 and 1.96. Since our zstat is in the middle, we do not reject the null.

The p-value for a Zstat = 1.00 with two tails is 2( 1- .8413) = .3174 and since this is not less than alpha = .05 we do not reject.