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G5 - ELECTRICAL PRINCIPLES [3 exam questions - 3 groups] PowerPoint Presentation

G5 - ELECTRICAL PRINCIPLES [3 exam questions - 3 groups]

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G5 - ELECTRICAL PRINCIPLES [3 exam questions - 3 groups] . G5A Resistance; reactance; inductance; capacitance; impedance; impedance matching G5B The Decibel; current and voltage dividers; electrical power calculations; sine wave root-mean-square (RMS) values; PEP calculations

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B. 100 watts

B. 625 watts

B. 1060 watts

C. Mutual inductance

C. 150 ohms

G5 - ELECTRICAL PRINCIPLES [3 exam questions - 3 groups]

- G5A Resistance; reactance; inductance; capacitance; impedance; impedance matching
- G5B The Decibel; current and voltage dividers; electrical power calculations; sine wave root-mean-square (RMS) values; PEP calculations
- G5C Resistors, capacitors, and inductors in series and parallel; transformers

Electrical Principles

G5A Resistance; Reactance

- Reactance
- Is the opposition to the flow of alternating current cause by capacitance or inductance
- Causes opposition to the flow of alternating current in an inductor
- Causes opposition to the flow of alternating current in a capacitor

Electrical Principles

G5A Inductance

- A coil reacts to AC such that as the frequency of the applied AC increases, the reactance increases (directly proportional)
- X L= 2∏FL
- Inductance Reactance = 2*PI*Frequency*Inductance

Electrical Principles

G5A Capacitance

- A capacitor reacts to AC such that as the frequency of the applied AC increases, the reactance decreases (inversely proportional)
- 1
- XC= 2 *∏*F*C
- XC = 1 divided by (2*PI*Frequency*Capacitance)

Electrical Principles

G5A Impedance

- Impedance is the opposition to the flow of current in an AC circuit
- When the impedance of an electrical load is equal to the internal impedance of the power source the source can deliver maximum power to the load
- The Ohm is the unit used to measure impedance

Electrical Principles

G5A Impedance matching

- Impedance matching is important –
- So the source can deliver maximum power to the load
- One reason to use an impedance matching transformer is to maximize the transfer of power

- Core saturation of a conventional impedance matching transformer should be avoided because harmonics and distortion could result

Electrical Principles

G5A Impedance matching cont’d

- All the following devices can be used for impedance matching at radio frequencies:
- A transformer
- A Pi-network
- A length of transmission line

- One method of impedance matching between two AC circuits is to insert an LC network between the two circuits

Electrical Principles

G5A01 What is impedance?

- A. The electric charge stored by a capacitor
- B. The inverse of resistance
- C. The opposition to the flow of current in an AC circuit
- D. The force of repulsion between two similar electric fields

Electrical Principles

G5A01 What is impedance? C. The opposition to the flow of current in an AC circuit

- A. The electric charge stored by a capacitor
- B. The inverse of resistance

- D. The force of repulsion between two similar electric fields

Electrical Principles

Resonant Circuit

Electrical Principles

G5A02 What is reactance?

- A. Opposition to the flow of direct current caused by resistance
- B. Opposition to the flow of alternating current caused by capacitance or inductance
- C. A property of ideal resistors in AC circuits
- D. A large spark produced at switch contacts when an inductor is deenergized

Electrical Principles

G5A02 What is reactance? B. Opposition to the flow of alternating current caused by capacitance or inductance

- A. Opposition to the flow of direct current caused by resistance

- C. A property of ideal resistors in AC circuits
- D. A large spark produced at switch contacts when an inductor is deenergized

Electrical Principles

G5A03 Which of the following causes opposition to the flow of alternating current in an inductor?

- A. Conductance
- B. Reluctance
- C. Admittance
- D. Reactance

Electrical Principles

G5A03 Which of the following causes opposition to the flow of alternating current in an inductor? D. Reactance

- A. Conductance
- B. Reluctance
- C. Admittance

Electrical Principles

G5A04 Which of the following causes opposition to the flow of alternating current in a capacitor?

- A. Conductance
- B. Reluctance
- C. Reactance
- D. Admittance

Electrical Principles

G5A04 Which of the following causes opposition to the flow of alternating current in a capacitor? C. Reactance

- A. Conductance
- B. Reluctance

- D. Admittance

Electrical Principles

G5A05 How does a coil react to AC? of alternating current in a capacitor?

- A. As the frequency of the applied AC increases, the reactance decreases
- B. As the amplitude of the applied AC increases, the reactance increases
- C. As the amplitude of the applied AC increases, the reactance decreases
- D. As the frequency of the applied AC increases, the reactance increases

Electrical Principles

G5A05 How does a coil react to AC? of alternating current in a capacitor? D. As the frequency of the applied AC increases, the reactance increases

- A. As the frequency of the applied AC increases, the reactance decreases
- B. As the amplitude of the applied AC increases, the reactance increases
- C. As the amplitude of the applied AC increases, the reactance decreases

Electrical Principles

G5A06 How does a capacitor react to AC? of alternating current in a capacitor?

- A. As the frequency of the applied AC increases, the reactance decreases
- B. As the frequency of the applied AC increases, the reactance increases
- C. As the amplitude of the applied AC increases, the reactance increases
- D. As the amplitude of the applied AC increases, the reactance decreases

Electrical Principles

G5A06 How does a capacitor react to AC? of alternating current in a capacitor?

- A. As the frequency of the applied AC increases, the reactance decreases
- B. As the frequency of the applied AC increases, the reactance increases
- C. As the amplitude of the applied AC increases, the reactance increases
- D. As the amplitude of the applied AC increases, the reactance decreases

Electrical Principles

G5A07 What happens when the impedance of an electrical load is equal to the internal impedance of the power source?

- A. The source delivers minimum power to the load
- B. The electrical load is shorted
- C. No current can flow through the circuit
- D. The source can deliver maximum power to the load

Electrical Principles

G5A07 What happens when the impedance of an electrical load is equal to the internal impedance of the power source? D. The source can deliver maximum power to the load

- A. The source delivers minimum power to the load
- B. The electrical load is shorted
- C. No current can flow through the circuit

Electrical Principles

G5A08 Why is impedance matching important? is equal to the internal impedance of the power source?

- A. So the source can deliver maximum power to the load
- B. So the load will draw minimum power from the source
- C. To ensure that there is less resistance than reactance in the circuit
- D. To ensure that the resistance and reactance in the circuit are equal

Electrical Principles

G5A08 Why is impedance matching important? is equal to the internal impedance of the power source?

- A. So the source can deliver maximum power to the load
- B. So the load will draw minimum power from the source
- C. To ensure that there is less resistance than reactance in the circuit
- D. To ensure that the resistance and reactance in the circuit are equal

Electrical Principles

G5A09 What unit is used to measure reactance? is equal to the internal impedance of the power source?

- A. Farad
- B. Ohm
- C. Ampere
- D. Siemens

Electrical Principles

G5A09 What unit is used to measure reactance? is equal to the internal impedance of the power source? B. Ohm

- A. Farad

- C. Ampere
- D. Siemens

Electrical Principles

G5A10 What unit is used to measure impedance? is equal to the internal impedance of the power source?

- A. Volt
- B. Ohm
- C. Ampere
- D. Watt

Electrical Principles

G5A10 What unit is used to measure impedance? is equal to the internal impedance of the power source? B. Ohm

- A. Volt

- C. Ampere
- D. Watt

Electrical Principles

G5A11 Why should core saturation of a conventional impedance matching transformer be avoided?

- A. Harmonics and distortion could result
- B. Magnetic flux would increase with frequency
- C. RF susceptance would increase
- D. Temporary changes of the core permeability could result

Electrical Principles

G5A11 Why should core saturation of a conventional impedance matching transformer be avoided?

- A. Harmonics and distortion could result
- B. Magnetic flux would increase with frequency
- C. RF susceptance would increase
- D. Temporary changes of the core permeability could result

Electrical Principles

G5A12 What is one reason to use an impedance matching transformer?

- A. To reduce power dissipation in the transmitter
- B. To maximize the transfer of power
- C. To minimize SWR at the antenna
- D. To minimize SWR in the transmission line

Electrical Principles

G5A12 What is one reason to use an impedance matching transformer? B. To maximize the transfer of power

- A. To reduce power dissipation in the transmitter

- C. To minimize SWR at the antenna
- D. To minimize SWR in the transmission line

Electrical Principles

G5A13 Which of the following devices can be used for impedance matching at radio frequencies?

- A. A transformer
- B. A Pi-network
- C. A length of transmission line
- D. All of these choices are correct

Electrical Principles

G5A13 Which of the following devices can be used for impedance matching at radio frequencies? D. All of these choices are correct

- A. A transformer
- B. A Pi-network
- C. A length of transmission line

Electrical Principles

G5A14 Which of the following describes one method of impedance matching between two AC circuits?

- A. Insert an LC network between the two circuits
- B. Reduce the power output of the first circuit
- C. Increase the power output of the first circuit
- D. Insert a circulator between the two circuits

Electrical Principles

G5A14 Which of the following describes one method of impedance matching between two AC circuits?

- A. Insert an LC network between the two circuits
- B. Reduce the power output of the first circuit
- C. Increase the power output of the first circuit
- D. Insert a circulator between the two circuits

Electrical Principles

G5B The Decibel impedance matching between two AC circuits?

- A two-times increase or decrease in power results in a change of 3 dB
- A percentage of 20.5 per cent power loss would result from a transmission line lose of 1 dB
- CURRENT AND VOLTAGE DIVIDERS
- The total current equals the sum of the currents through each branch of a parallel circuit

Electrical Principles

G5B Electrical power calculations impedance matching between two AC circuits?

- There are 200 watts of electrical power used if 400 VDC is supplied to an 800-ohm circuit
- P = E2/R
- P = 4002/800
- P = 1600/800
- P = 200 watts

- There are 2.4 watts of electrical power used by a 12-VDC light bulb that draws 0.2 amperes
- P = I * E
- P = 0.2 * 12
- P = 2.4 watts

Electrical Principles

G5B Electrical power calculations cont’d impedance matching between two AC circuits?

- Approximately 61 milliwatts are being dissipated when a current of 7.0 milliamperes flows through 1.25 kilohms
- P = I2 R
- P = .0072 * 1250
- P = 61 mW or 0.061 watts

- The voltage across a 50-ohm dummy load dissipating 1200 watts would be 245 volts
- P = I * E and E = I * R therefore E = SQRT ( P * R)
- E = √(1200*50)
- E = √60000
- E = 245 volts

Electrical Principles

G5B Sine wave root-mean-square (RMS) values impedance matching between two AC circuits?

- The RMS value measurement of an AC signal is equivalent to a DC voltage of the same value
- Most ac voltages are specified by their effective voltage
- The phrase root-mean-square describes the actual process of calculating the effective voltage

- The RMS voltage of a sine wave with a value of 17 volts peak is 12 volts RMS
- 0.707071* volt peak = volts RMS
- VRMS = 0.707071 * 17 = 12 volts RMS

Electrical Principles

G5B PEP calculations impedance matching between two AC circuits?

- The peak-to-peak (PEP) output power from a transmitter is 100 watts if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitted output
- (Peak envelope voltage x 0.707)2
- PEP = R
- Peak-to-peak envelope voltage
- Peak envelope voltage = 2
- (100x 0.707)2
- PEP = 50 = 100W

Electrical Principles

G5B PEP calculations cont’d impedance matching between two AC circuits?

- The peak-to-peak voltage of a sine wave that has an RMS voltage of 120 volts is 339.4 volts
- If you know the RMS voltage and want to know the peak value , multiply the RMS by the square root of 2 (which is 1.414). If you want to know peak-to-peak, double the result
- 120 x 1.414 x 2 = 339.4 V

- The ratio of peak envelope power to average power for an unmodulated carrier is 1.00

Electrical Principles

G5B PEP calculations cont’d impedance matching between two AC circuits?

- The output PEP from a transmitter if an oscilloscope measures 500 volts peak-to-peak across a 50-ohm resistor connected to the transmitter output is 625 watts
- Use the formulas
- ERMS2
- (1) PEP = R , (2) EPEAK = EPK-PK/ 2,
- (3) ERMS = 0.707 x E PEAK
- EPEAK = 500/2 = 250
- ERMS = 0.707 x 250 = 176.75
- PEP = (176.75)2 = 31222/50 =625 watts
- R

Electrical Principles

G 5B PEP calculations cont’d impedance matching between two AC circuits?

* If an average reading wattmeter connected to the transmitter output indicates 1060 watts the output PEP of an unmodulated carrier is 1060 watts

Electrical Principles

G5B01 A two-times increase or decrease in power results in a change of how many dB?

- A. 2 dB
- B. 3 dB
- C. 6 dB
- D. 12 dB

Electrical Principles

G5B01 A two-times increase or decrease in power results in a change of how many dB? B. 3 dB

- A. 2 dB

- C. 6 dB
- D. 12 dB

Electrical Principles

G5B02 How does the total current relate to the individual currents in each branch of a parallel circuit?

- A. It equals the average of each branch current
- B. It decreases as more parallel branches are added to the circuit
- C. It equals the sum of the currents through each branch
- D. It is the sum of the reciprocal of each individual voltage drop

Electrical Principles

G5B02 How does the total current relate to the individual currents in each branch of a parallel circuit? C. It equals the sum of the currents through each branch

- A. It equals the average of each branch current
- B. It decreases as more parallel branches are added to the circuit

- D. It is the sum of the reciprocal of each individual voltage drop

Electrical Principles

Ohm’s Law and Power Calculations currents in each branch of a parallel circuit?

E

P

I

R

I

E

E=Voltage (Volts)

I=Current (Amps)

R=Resistance (Ohms)

P=Power (Watts)

Electrical Principles

G5B03 How many watts of electrical power are used if 400 VDC is supplied to an 800-ohm load?

- A. 0.5 watts
- B. 200 watts
- C. 400 watts
- D. 3200 watts

Electrical Principles

G5B03 How many watts of electrical power are used if 400 VDC is supplied to an 800-ohm load? B. 200 watts

- A. 0.5 watts

- C. 400 watts
- D. 3200 watts

Electrical Principles

G5B04 How many watts of electrical power are used by a 12-VDC light bulb that draws 0.2 amperes?

- A. 2.4 watts
- B. 24 watts
- C. 6 watts
- D. 60 watts

Electrical Principles

G5B04 How many watts of electrical power are used by a 12-VDC light bulb that draws 0.2 amperes?

- A. 2.4 watts
- B. 24 watts
- C. 6 watts
- D. 60 watts

Electrical Principles

G5B05 How many watts are being dissipated when a current of 7.0 milliamperes flows through 1.25 kilohms?

- A. Approximately 61 milliwatts
- B. Approximately 39 milliwatts
- C. Approximately 11 milliwatts
- D. Approximately 9 milliwatts

Electrical Principles

G5B05 How many watts are being dissipated when a current of 7.0 milliamperes flows through 1.25 kilohms?

- A. Approximately 61 milliwatts
- B. Approximately 39 milliwatts
- C. Approximately 11 milliwatts
- D. Approximately 9 milliwatts

Electrical Principles

G5B06 What is the output PEP from a transmitter if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?

- A. 1.4 watts
- B. 100 watts
- C. 353.5 watts
- D. 400 watts

Electrical Principles

G5B06 What is the output PEP from a transmitter if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?

- A. 1.4 watts

- C. 353.5 watts
- D. 400 watts

Electrical Principles

RMS, Peak and Peak to Peak Voltages oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?

Electrical Principles

G5B07 Which measurement of an AC signal is equivalent to a DC voltage of the same value?

- A. The peak-to-peak value
- B. The peak value
- C. The RMS value
- D. The reciprocal of the RMS value

Electrical Principles

G5B07 Which measurement of an AC signal is equivalent to a DC voltage of the same value? C. The RMS value

- A. The peak-to-peak value
- B. The peak value

- D. The reciprocal of the RMS value

Electrical Principles

G5B08 What is the peak-to-peak voltage of a sine wave that has an RMS voltage of 120 volts?

- A. 84.8 volts
- B. 169.7 volts
- C. 240.0 volts
- D. 339.4 volts

Electrical Principles

G5B08 What is the peak-to-peak voltage of a sine wave that has an RMS voltage of 120 volts? D. 339.4 volts

- A. 84.8 volts
- B. 169.7 volts
- C. 240.0 volts

Electrical Principles

G5B09 What is the RMS voltage of sine wave with a value of 17 volts peak?

- A. 8.5 volts
- B. 12 volts
- C. 24 volts
- D. 34 volts

Electrical Principles

G5B09 What is the RMS voltage of sine wave with a value of 17 volts peak? B. 12 volts

- A. 8.5 volts

- C. 24 volts
- D. 34 volts

Electrical Principles

G5B11 What is the ratio of peak envelope power to average power for an unmodulated carrier?

- A. .707
- B. 1.00
- C. 1.414
- D. 2.00

Electrical Principles

G5B11 What is the ratio of peak envelope power to average power for an unmodulated carrier? B. 1.00

- A. .707

- C. 1.414
- D. 2.00

Electrical Principles

G5B12 What would be the voltage across a 50-ohm dummy load dissipating 1200 watts?

- A. 173 volts
- B. 245 volts
- C. 346 volts
- D. 692 volts

Electrical Principles

G5B12 What would be the voltage across a 50-ohm dummy load dissipating 1200 watts? B. 245 volts

- A. 173 volts

- C. 346 volts
- D. 692 volts

Electrical Principles

G5B13 What percentage of power loss would result from a transmission line loss of 1 dB?

- A. 10.9 %
- B. 12.2 %
- C. 20.5 %
- D. 25.9 %

Electrical Principles

G5B13 What percentage of power loss would result from a transmission line loss of 1 dB? C. 20.5 %

- A. 10.9 %
- B. 12.2 %

- D. 25.9 %

Electrical Principles

G5B14 What is the output PEP from a transmitter if an oscilloscope measures 500 volts peak-to-peak across a 50-ohm resistor connected to the transmitter output?

- A. 8.75 watts
- B. 625 watts
- C. 2500 watts
- D. 5000 watts

Electrical Principles

G5B14 What is the output PEP from a transmitter if an oscilloscope measures 500 volts peak-to-peak across a 50-ohm resistor connected to the transmitter output?

- A. 8.75 watts

- C. 2500 watts
- D. 5000 watts

Electrical Principles

G5B15 What is the output PEP of an unmodulated carrier if an average reading wattmeter connected to the transmitter output indicates 1060 watts?

- A. 530 watts
- B. 1060 watts
- C. 1500 watts
- D. 2120 watts

Electrical Principles

G5B15 What is the output PEP of an unmodulated carrier if an average reading wattmeter connected to the transmitter output indicates 1060 watts?

- A. 530 watts

- C. 1500 watts
- D. 2120 watts

Electrical Principles

G5C Resistors, Inductors & Capacitors average reading wattmeter connected to the transmitter output indicates 1060 watts?

- Total value of resistors, capacitors and inductors connected in series and in parallel
- Resistors ( R) and inductors (I) act the same way
- Resistors in series add up: Rtotal = R1 + R2 + R3
- Inductors in series add up: Ltotal = L1 + L2 + L3

- Resistors and Inductors in Parallel combine with a resulting total value that is always LESS than the value of the lowest value resistor in parallel
- Capacitors in Parallel simply add up
- C total = C1 + C2 + C3

- Capacitors in SERIES combine with a resulting total value that is always less than the value of the lowest value capacitor in series

- Resistors ( R) and inductors (I) act the same way

Electrical Principles

G5C Transformers average reading wattmeter connected to the transmitter output indicates 1060 watts?

- Mutual inductance causes a voltage to appear across the secondary winding of a transformer when an ACC voltage is connected across its primary winding
- The source of energy is normally connected across the primary winding
- The current in the primary winding of a transformer if no load is attached to the secondary winding is called the magnetizing current

Electrical Principles

G5C Transformers cont’d average reading wattmeter connected to the transmitter output indicates 1060 watts?

- Turns ration problem
- The voltage of the secondary is equal to the voltage of the primary times the number turns of the secondary divided by the number of turns of the primary
- NS EP x NS
- ES = EP x NP = NP (**hint secondary/ primary)
- The voltage across a 500-turn secondary winding in a transformer is 26.7 volts if the 2250- turn primary is connected to 120 VAC
- EP =120 VAC
- NP = 2250 (** Hint 500/2500 = 1/5 of the primary)
- NS = 500 ~ 25 volts

Electrical Principles

G5C Transformers cont’d average reading wattmeter connected to the transmitter output indicates 1060 watts?

- The ration of turns of the primary, NP, to the turns on the secondary, NS, is equal to the square root of the ration of the primary impedance, ZP, to the secondary impedance, Zs
- 12.2 to 1 is the turns ration of a transformer used to match an audio amplifier having a 600-ohm output impedance to a speaker having a 4-ohm impedance
- NP √ZP
- NS = √ZS √600/4 = √150 = 12.25 to 1

Electrical Principles

G5C01 What causes a voltage to appear across the secondary winding of a transformer when an AC voltage source is connected across its primary winding?

- A. Capacitive coupling
- B. Displacement current coupling
- C. Mutual inductance
- D. Mutual capacitance

Electrical Principles

G5C01 What causes a voltage to appear across the secondary winding of a transformer when an AC voltage source is connected across its primary winding?

- A. Capacitive coupling
- B. Displacement current coupling

- D. Mutual capacitance

Electrical Principles

G5C02 Where is the source of energy normally connected in a transformer?

- A. To the secondary winding
- B. To the primary winding
- C. To the core
- D. To the plates

Electrical Principles

G5C02 Where is the source of energy normally connected in a transformer? B. To the primary winding

- A. To the secondary winding

- C. To the core
- D. To the plates

Electrical Principles

G5C03 What is current in the primary winding of a transformer called if no load is attached to the secondary?

- A. Magnetizing current
- B. Direct current
- C. Excitation current
- D. Stabilizing current

Electrical Principles

G5C03 What is current in the primary winding of a transformer called if no load is attached to the secondary?

- A. Magnetizing current
- B. Direct current
- C. Excitation current
- D. Stabilizing current

Electrical Principles

G5C04 What is the total resistance of three 100-ohm resistors in parallel?

- A. .30 ohms
- B. .33 ohms
- C. 33.3 ohms
- D. 300 ohms

Electrical Principles

G5C04 What is the total resistance of three 100-ohm resistors in parallel? C. 33.3 ohms

- A. .30 ohms
- B. .33 ohms

- D. 300 ohms

Electrical Principles

G5C05 What is the value of each resistor if three equal value resistors in parallel produce 50 ohms of resistance, and the same three resistors in series produce 450 ohms?

- A. 1500 ohms
- B. 90 ohms
- C. 150 ohms
- D. 175 ohms

Electrical Principles

G5C05 What is the value of each resistor if three equal value resistors in parallel produce 50 ohms of resistance, and the same three resistors in series produce 450 ohms?

- A. 1500 ohms
- B. 90 ohms

- D. 175 ohms

Electrical Principles

G5C06 What is the voltage across a 500-turn secondary winding in a transformer if the 2250-turn primary is connected to 120 VAC?

- A. 2370 volts
- B. 540 volts
- C. 26.7 volts
- D. 5.9 volts

Electrical Principles

G5C06 What is the voltage across a 500-turn secondary winding in a transformer if the 2250-turn primary is connected to 120 VAC? C. 26.7 volts

- A. 2370 volts
- B. 540 volts

- D. 5.9 volts

Electrical Principles

G5C07 What is the turns ratio of a transformer used to match an audio amplifier having a 600-ohm output impedance to a speaker having a 4-ohm impedance?

- A. 12.2 to 1
- B. 24.4 to 1
- C. 150 to 1
- D. 300 to 1

Electrical Principles

G5C07 What is the turns ratio of a transformer used to match an audio amplifier having a 600-ohm output impedance to a speaker having a 4-ohm impedance?

- A. 12.2 to 1
- B. 24.4 to 1
- C. 150 to 1
- D. 300 to 1

Electrical Principles

G5C08 What is the equivalent capacitance of two 5000 picofarad capacitors and one 750 picofarad capacitor connected in parallel?

- A. 576.9 picofarads
- B. 1733 picofarads
- C. 3583 picofarads
- D. 10750 picofarads

Electrical Principles

G5C08 What is the equivalent capacitance of two 5000 picofarad capacitors and one 750 picofarad capacitor connected in parallel? D. 10750 picofarads

- A. 576.9 picofarads
- B. 1733 picofarads
- C. 3583 picofarads

Electrical Principles

G5C09 What is the capacitance of three 100 microfarad capacitors connected in series?

- A. .30 microfarads
- B. .33 microfarads
- C. 33.3 microfarads
- D. 300 microfarads

Electrical Principles

G5C09 What is the capacitance of three 100 microfarad capacitors connected in series? C. 33.3 microfarads

- A. .30 microfarads
- B. .33 microfarads

- D. 300 microfarads

Electrical Principles

G5C10 What is the inductance of three 10 millihenry inductors connected in parallel?

- A. .30 Henrys
- B. 3.3 Henrys
- C. 3.3 millihenrys
- D. 30 millihenrys

Electrical Principles

G5C10 What is the inductance of three 10 millihenry inductors connected in parallel? C. 3.3 millihenrys

- A. .30 Henrys
- B. 3.3 Henrys

- D. 30 millihenrys

Electrical Principles

G5C11 What is the inductance of a 20 millihenry inductor in series with a 50 millihenry inductor?

- A. .07 millihenrys
- B. 14.3 millihenrys
- C. 70 millihenrys
- D. 1000 millihenrys

Electrical Principles

G5C11 What is the inductance of a 20 millihenry inductor in series with a 50 millihenry inductor? C. 70 millihenrys

- A. .07 millihenrys
- B. 14.3 millihenrys

- D. 1000 millihenrys

Electrical Principles

G5C12 What is the capacitance of a 20 microfarad capacitor in series with a 50 microfarad capacitor?

- A. .07 microfarads
- B. 14.3 microfarads
- C. 70 microfarads
- D. 1000 microfarads

Electrical Principles

G5C12 What is the capacitance of a 20 microfarad capacitor in series with a 50 microfarad capacitor? B. 14.3 microfarads

- A. .07 microfarads

- C. 70 microfarads
- D. 1000 microfarads

Electrical Principles

G5C13 What component should be added to a capacitor in a circuit to increase the circuit capacitance?

- A. An inductor in series
- B. A resistor in series
- C. A capacitor in parallel
- D. A capacitor in series

Electrical Principles

G5C13 What component should be added to a capacitor in a circuit to increase the circuit capacitance? C. A capacitor in parallel

- A. An inductor in series
- B. A resistor in series

- D. A capacitor in series

Electrical Principles

G5C14 What component should be added to an inductor in a circuit to increase the circuit inductance?

- A. A capacitor in series
- B. A resistor in parallel
- C. An inductor in parallel
- D. An inductor in series

Electrical Principles

G5C14 What component should be added to an inductor in a circuit to increase the circuit inductance? D. An inductor in series

- A. A capacitor in series
- B. A resistor in parallel
- C. An inductor in parallel

Electrical Principles

G5C15 What is the total resistance of a 10 ohm, a 20 ohm, and a 50 ohm resistor in parallel?

- A. 5.9 ohms
- B. 0.17 ohms
- C. 10000 ohms
- D. 80 ohms

Electrical Principles

G5C15 What is the total resistance of a 10 ohm, a 20 ohm, and a 50 ohm resistor in parallel?

- A. 5.9 ohms
- B. 0.17 ohms
- C. 10000 ohms
- D. 80 ohms

Electrical Principles

G5C16 What component should be added to an existing resistor in a circuit to increase circuit resistance?

- A. A resistor in parallel
- B. A resistor in series
- C. A capacitor in series
- D. A capacitor in parallel

Electrical Principles

G5C16 What component should be added to an existing resistor in a circuit to increase circuit resistance? B. A resistor in series

- A. A resistor in parallel

- C. A capacitor in series
- D. A capacitor in parallel

Electrical Principles

G5 - ELECTRICAL PRINCIPLES in a circuit to increase circuit resistance?[3 exam questions - 3 groups]

Electrical Principles

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