1 / 37

Chapter 19 PRECIPITATION REACTIONS

Chapter 19 PRECIPITATION REACTIONS. Solubility of Ionic Solids. Depends on the balance of two forces: Attraction between H 2 O molecules and ions of solid. Force of attraction between oppositely charged ions within solid. Solubility Rules.

kurt
Download Presentation

Chapter 19 PRECIPITATION REACTIONS

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 19PRECIPITATION REACTIONS WOLPA/AP CHEMISTRY/CDO

  2. Solubility of Ionic Solids • Depends on the balance of two forces: • Attraction between H2O molecules and ions of solid. • Force of attraction between oppositely charged ions within solid. WOLPA/AP CHEMISTRY/CDO

  3. Solubility Rules • Use in predicting results of precipitation reactions. MEMORIZE THE SOLUBILITY RULES!!!!! • Determine ions present and possible products. • Use solubility rules to determine if any are insoluble. WOLPA/AP CHEMISTRY/CDO

  4. Example 1 • Ba(NO3)2(aq) + Na2CO3(aq) WOLPA/AP CHEMISTRY/CDO

  5. Solubility Rules • 1. Salts containing Group I elements are soluble (Li+, Na+, K+, Cs+, Rb+). Exceptions to this rule are rare. Salts containing the ammonium ion (NH4+) are also soluble. • 2. Salts containing nitrate ion (NO3-) are generally soluble. • 3. Salts containing Cl-, Br-, I- are generally soluble. Important exceptions to this rule are halide salts of Ag+, Pb2+, and (Hg2)2+. Thus, AgCl, PbBr2, and Hg2Cl2 are all insoluble. WOLPA/AP CHEMISTRY/CDO

  6. Solubility Rules Continued • 4. Most silver salts are insoluble. AgNO3 and Ag(C2H3O2) are common soluble salts of silver; virtually anything else is insoluble. • 5. Most sulfate salts are soluble. Important exceptions to this rule include BaSO4, PbSO4, Ag2SO4 and SrSO4. • 6. Most hydroxide salts are only slightly soluble. Hydroxide salts of Group I elements are soluble. Hydroxide salts of Group II elements (Ca, Sr, and Ba) are slightly soluble. Hydroxide salts of transition metals and Al3+ are insoluble. Thus, Fe(OH)3, Al(OH)3, Co(OH)2 are not soluble. WOLPA/AP CHEMISTRY/CDO

  7. Solubility Rules Continued • 7. Most sulfides of transition metals are highly insoluble. Thus, CdS, FeS, ZnS, Ag2S are all insoluble. Arsenic, antimony, bismuth, and lead sulfides are also insoluble. • 8. Carbonates are frequently insoluble. Group II carbonates (Ca, Sr, and Ba) are insoluble. Some other insoluble carbonates include FeCO3 and PbCO3. • 9. Chromates are frequently insoluble. Examples: PbCrO4, BaCrO4 • 10. Phosphates are frequently insoluble. Examples: Ca3(PO4)2, Ag2PO4 • 11. Fluorides are frequently insoluble. Examples: BaF2, MgF2 PbF2. WOLPA/AP CHEMISTRY/CDO

  8. Example 1 Continued • Ba(NO3)2(aq) + Na2CO3(aq) WOLPA/AP CHEMISTRY/CDO

  9. Stoichiometry • Mole Relations • Coefficients in the net ionic equation can be used in the usual way to relate the moles of reactants and products. • Moles of ions can be deduced from solute concentrations. WOLPA/AP CHEMISTRY/CDO

  10. Example 2 • What is the molar concentration of Ba2+ and F- in a solution containing 0.0075 M BaF2 WOLPA/AP CHEMISTRY/CDO

  11. Precipitation Titrations • Used to determine the concentration of species in solution or in a solid mixture. • Indicator shows, usually by color change, when the species being analyzed for has been consumed WOLPA/AP CHEMISTRY/CDO

  12. General Principles • Involves formation of a precipitate • Must determine the volume of a standardized titrant needed to just precipitate all of the ion. • Need an indicator or electrode to determine when the precipitation is complete WOLPA/AP CHEMISTRY/CDO

  13. Solubility Equilibria • Solubility Product Constant, Ksp • Precipitation reactions like all reactions, reach a position of equilibrium. • Expression for Ksp MaXb <----------> aM+b + bX-a Ksp = [M+b]a [X-a]b WOLPA/AP CHEMISTRY/CDO

  14. Solubility Product Principle • In any water solution in equilibrium with a slightly soluble ionic compound, the product of the concentrations of its ions, each raised to a power equal to its coefficient in the solubility equation is a constant. This constant, Ksp, has a fixed value at a given temperature, independent of the concentrations of the individual ions. WOLPA/AP CHEMISTRY/CDO

  15. Two Ion Compound • AgCl WOLPA/AP CHEMISTRY/CDO

  16. Three Ion Compound • PbCl2 WOLPA/AP CHEMISTRY/CDO

  17. Four Ion Compound • Al(OH)3 WOLPA/AP CHEMISTRY/CDO

  18. Calculation of Ksp • Calculated from measured solubility • AgCl Ksp = (s) (s) = s2 • PbCl2 Ksp = (s) (2s)2 = 4s3 • Al(OH)3 Ksp = (s) (3s)3 = 27s4 WOLPA/AP CHEMISTRY/CDO

  19. Example 3 • At 20 oC, a saturated aqueous solution of silver acetate, AgC2H3O2, contains 1.0 g dissolved in 100.0 mL of solution. Calculate the Ksp for AgC2H3O2. WOLPA/AP CHEMISTRY/CDO

  20. Determination of Solubility • In pure water • Ksp = s2 s = (Ksp)1/2 • Ksp = 4s3 s = (Ksp/4)1/3 • Ksp = 27s4 s = (Ksp/27)1/4 WOLPA/AP CHEMISTRY/CDO

  21. Example 4 • Estimate the solubility of lead (II) bromide in (a) moles per liter and (b) grams per liter of pure water. Ksp = 6.3 x 10-6 WOLPA/AP CHEMISTRY/CDO

  22. Uses of Ksp • Calculation of concentration of one ion, knowing that of the other WOLPA/AP CHEMISTRY/CDO

  23. Example 5 • You have a solution that has a lead (II) concentration of 0.0012 M. What is the maximum concentration of chloride ions that would be present? Ksp = 1.7 x 10-5 WOLPA/AP CHEMISTRY/CDO

  24. Uses of Ksp • Determination of whether a precipitate will form • Compare original concentration product, P, to Ksp • if P < Ksp, no precipitate will form • if P > Ksp, precipitate forms until P becomes equal to Ksp WOLPA/AP CHEMISTRY/CDO

  25. Example 6 • You have 100.0 m of a solution that has a lead (II) concentration of 0.0012 M. Does PbCl2 precipitate when 1.20 g of solid NaCl is added? WOLPA/AP CHEMISTRY/CDO

  26. Determination of Solubility • In solution containing a common ion • Solubility is much less than in pure water WOLPA/AP CHEMISTRY/CDO

  27. Example 7 • Calculate the solubility of silver carbonate, Ag2CO3, in moles per liter, in pure water. Compare this with the molar solublity of Ag2CO3 in 225 mL of water to which 0.15 g of Na2CO3 has been added. WOLPA/AP CHEMISTRY/CDO

  28. Simultaneous Equilibria • Two or more reactions occur at the same time is a solution, all of them being described as equilibrium processes. • The equilibrium for the overall reaction is the product of the equilibrium constants for the summed reactions. That is Knet = K1 x K2 WOLPA/AP CHEMISTRY/CDO

  29. Solubility and pH • Any salt containing an anion that is the conjugate base of a weak acid dissolves in water to a greater extent than that given by Ksp because the ions undergo a hydrolysis reaction. WOLPA/AP CHEMISTRY/CDO

  30. Example 8 PbS • PbS(s) <----------> Pb2+(aq) + S2-(aq) Ksp = 8.4 x 10-28 • S2-(aq) + H2O(l) <----------> HS-(aq) + OH-(aq) Kb = 1 x 105 • Overall • PbS(s) + H2O(l) <---> Pb2+(aq) + HS-(aq) + OH-(aq) Knet = 8.4 x 10-23 WOLPA/AP CHEMISTRY/CDO

  31. In general, the solubility of a salt containing the conjugate base of a weak acid is increased by addition of a stronger acid to the solution. In contrast, the salts are not soluble in strong acid if the anion is the conjugate base of a strong acid. WOLPA/AP CHEMISTRY/CDO

  32. CaCO3 <--------> Ca2+(aq)+ CO32-(aq) K = Ksp = 3.8 x 10-9 • CO32-(aq) + H2O(l) <--------> HCO3-(aq) + OH-(aq) K = Kb = 2.1 x 10-4 • OH-(aq) + H3O+(aq) <--------> 2H2O(l) K = 1/Kw = 1 x 1014 WOLPA/AP CHEMISTRY/CDO

  33. NET • CaCO3(s) + H3O+(aq) <------> Ca2+(aq) + HCO3-(aq) + H2O(l) • Knet = (Ksp) (Kb)/(Kw) = 79.8 WOLPA/AP CHEMISTRY/CDO

  34. Solubility and Complex Ions • Examples of complex ions: AgCl2-, Ag(S2O3)23-, Ag(CN)2- • The solubility of certain “insoluble “ compounds can be increased when a complex ion is formed. Complex ions usually refer to cations in which surrounding water molecules have been replaced by some other electron pair donor. The equilibrium constant will equal the solubility constant times the formation constant for the complex ions. (Note - Chapter 23 in your textbook covers complex ions - their formation and nomenclature) WOLPA/AP CHEMISTRY/CDO

  35. Solubility and Complex ions • AgCl(s) + 2NH3 Ag(NH3)2+ + Cl- • K = (Ksp) (Kf) • = (1.8 x 10-10) (1.6 x 107) = 0.00288 = 0.0029 WOLPA/AP CHEMISTRY/CDO

  36. Example 9 • Solid gold (I) chloride AuCl, is dissolved when excess cyanide ions, CN-, are added to give a water soluble complex ion. • AuCl(s) + 2CN- (aq) Au(CN)-(aq) + Cl- • Show that this equation is the sum of two other equations and calculate the Knet. WOLPA/AP CHEMISTRY/CDO

  37. Solubility, Ion Separations, and Qualitative Analysis WOLPA/AP CHEMISTRY/CDO

More Related