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# Central Force - PowerPoint PPT Presentation

Central Force. Umiatin,M.Si. The aim : to evaluate characteristic of motion under central force field. A. Introduction. Central Force always directed along the line connecting the center of the two bodies Occurs in : motion of celestial bodies and nuclear interaction.

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### Central Force

Umiatin,M.Si

A. Introduction force field

• Central Force always directed along the line connecting the center of the two bodies

• Occurs in : motion of celestial bodies and nuclear interaction

Central Force Motion as One Body Problem force field

• Suppose isolated system consist two bodies and separated a distance r = |r| with interaction between them described by a central force F(r), we need six quantities used to describe motion of those particle :

Method 1 : force field

• To describe those, we need six quantities ( three component of r1 and three component of r2). The equation of motion of those particle are :

• If F(r) > 0: repusive , F(r) <0 : Attractive. Coupled by :

Method 2 force field

• Describe a system using center mass (R) and relative position (r).

• R describes the motion of the center of mass and r describes the relative motion of one particle with respect to the other

No external forces are acting on the system, so the motion of the center of mass is uniform translational motion.

R** = 0.

• Solve the equation of motion : of the center of mass is uniform translational motion.

• The center of mass moves with uniform velocity :

• By choosing the initial condition, vo, to, Ro = 0, the origin of coordinate coincides with center of mass R.

If mass :m2 >> m1, then reduced mass:

The eq of motion :

Become :

B. General properties of Central Force Thus, whenever we use mass

• Central Force is Confined to a Plane

If p is the linear momentum of a particle of mass µ, the torque τ about an axis passing through the center of force is :

• If the angular momentum L of mass Thus, whenever we use mass µis constant, its magnitude and direction are fixed in space. Hence, by definition of the cross product, if the direction of L is fixed in space, vectors r and p must lie in a plane perpendicular to L. That is, the motion of particle of mass µ is confined to a plane that is perpendicular to L.

2. Angular Momentum and Energy are Constant dimensional problem can be reduced into two dimensional. Using polar coordinate system :

The angular momentum of a particle of mass µat a distance r from the force center is :

3. Law of Equal Areas are conservative, the total energy is constant :

Consider a mass µ at a distance r(θ) at time t from the force center O :

• Subtituting are conservative, the total energy is constant :

C. Equation of Motion are conservative, the total energy is constant :

From the previous description :

• If we know V(r), these equations can be solved for θ(t) and r(t). The set [θ(t), r(t)] describes the orbit of the particle.

• Solve the equation, we find : are conservative, the total energy is constant :

• We will get t(r) then inverse r(t). But we are interested in the equation of the path in term r and θ

• We may write : are conservative, the total energy is constant :

• And subtitute :

• Then :

Suppose the Force is F(r) = Kr are conservative, the total energy is constant :n

• K = constant

• If n = 1  the solution is motion of harmonic oscillator

• If n = -2 , eq : coulomb and gravitation force

Other method : Use Lagrangian are conservative, the total energy is constant :

• Lagrangian of the system :

• We find

Example 1/r

1. Find the force law for a central force field that allow a particle to move in logarithmic spiral orbit given by (k and α are constant) :

2. Find r(t) and 1/rθ(t) !

Solution :

• Solution :

The equation for the path of a particle moving under the influence of a central force whose magnitude is inversely proportional to the distance between the particle can be obtain from :