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Group 6

Mohammad Tanvir Shahriar ID. 16024 Tashmeem Farhana Iftekhar ID. 16061 Tahniyat sultana Prova ID. 16017 Tanvir Ahmed ID. 16009 Md.Farhadul Islam ID. 16066. Group 6. Statistical Application Analysis On Dhaka Bank Ltd . _______________________________________.

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Group 6

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  1. Mohammad Tanvir Shahriar ID. 16024 Tashmeem Farhana Iftekhar ID. 16061 Tahniyat sultana Prova ID. 16017 Tanvir Ahmed ID. 16009 Md.Farhadul Islam ID. 16066 Group 6

  2. Statistical Application Analysis On Dhaka Bank Ltd ._______________________________________

  3. Dhaka Bank Limited is a private-owned commercial bank in Bangladesh. It has Authorized Capital of Tk. 1,000 million and Paid-up Capital of Tk. 100 million. It has 54 Branches, 4 SME Service Centers, 5 CMS Units & 2 offshore Banking Units It offers the full range of real-time online banking services through its all Branches, ATMs and Internet Banking Channels. Dhaka bank limited

  4. We used Input of spss

  5. Descriptive statistics

  6. MULTIPLE REGRATION EQUATION

  7. Formula of Multiple Regression Equation: Ŷ=a+b₁x₁+b₂x₂+b₃x₃ Here, a= constant X₁=Deposit X₂=Investment X₃=Fixed asset

  8. SPSS Output of Multiple Regression Equation: Ŷ= -14357.25+1.28x1+1.29x2+6.82x3 Total Asset= -14357.25+1.28Deposit+1.29Investment+6.82Fixed Asset

  9. Coefficient of Multiple Determination

  10. Characteristics of Coefficient of Multiple Regression • It is symbolized by a capital R squared. • It can range from 0 to 1 • It cannot assume negative values. • It is easy to interpret

  11. R² = = 1

  12. R²adj = 1- ÷ = .99

  13. Interpretation • Here R² is 1and Adjusted R² is .99, which is less than R² • R² is 1 so it means association between dependent and independent variables are strong • Only 1% of the variation if the estimation can not be explained through the adjustment of degrees of freedom

  14. Global Test: ANOVA • We can test the ability of the independent variables x1 ,x2, x3…xk to explain the behavior of the dependent variable Y. • Basically, it investigates whether it is a possible all the independent variables have zero regression equation.

  15. ANOVA Test Step 1 : State the null and alternate hypothesis: The null hypothesis is: The independent variables have less significant effect on dependent variable Ho: β1=β2=β3=0 The alternative hypothesis is: The independent variables have significant effect on dependent variable. H1: β1 ≠ β2 ≠ β3≠ 0

  16. Continued… Step 2: Select the level of significance: We will use .05 significance level Step 3: Determine the test statistics: The test statistics follows the F distribution F=

  17. Continued… Step 4: Formulate the decision rule: • The decision rule is reject Ho >216 • The critical value of F is found in Appendix B.4.It is 216. • The degrees of freedom for numerator is 3; • The degrees of freedom for denominator is 1, found by n-(k+1); 5-(3+1). Step 5: Perform calculations and make a decision: The value of F is : F= = =968.70

  18. Variables for T-Test Dependent Variables Independent Variables • Total Asset • Deposit • Investment • Fixed Asset

  19. SPSS Input (Data variables)

  20. SPSS Output of T-Test

  21. Conducting T-Test • The null hypothesis for three independent variables is: Ho: β1=0; β2=0; β3 =0 • The alternative hypothesis is: H1: β1 ≠0; β2 ≠0; β3≠0 • We will use .05 level of significance • The decision rule is reject Ho >12.706 • The value of t is found from the following equation: ti=bi - 0/sbi

  22. Comparison of value • Critical Value is: • t=12.706 • Calculated values are: • t1(Deposit)=7.20>12.706=Null hypothesis accepted • t2(Investment)=1.40<12.706=Null hypothesis accepted • t3(Fixed asset)=2.57>12.706=Null hypothesis accepted

  23. Conclusion

  24. Thank You All

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