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Sum-of-Years’-Digits Example. Assume depreciable asset is a car with:. 4 year useful life Original cost of \$22,000 Salvage Value of \$7,000. First, compute Depreciable Base = Cost – Salvage Value. = \$22,000 - \$7,000. = \$15,000. Then, depreciate base x Sum of Years’ Digits Multiplier.

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• Assume depreciable asset is a car with:

• 4 year useful life

• Original cost of \$22,000

• Salvage Value of \$7,000

First, compute Depreciable Base = Cost – Salvage Value

= \$22,000 - \$7,000

= \$15,000

Then, depreciate base x Sum of Years’ Digits Multiplier

Sum of Year’s Digits

This was corrected on July 16, 2002.

Depr. Fraction = Remaining Life/Sum of Years’ Digits

This was corrected on July 16, 2002.

This was corrected on July 16, 2002.

This was corrected on July 16, 2002.

This was corrected on July 16, 2002.

• Assume depreciable asset is a car with:

• 4 year useful life

• Original cost of \$22,000

• Salvage Value of \$7,000

Straight Line %age = 100%/Useful Life

Too much depreciation—below salvage value!

Throw out these final year computed values.

Make this enough to arrive exactly at ending salvage value.

Note that depreciation is complete after two years even

though asset has four year useful life.

Note that the prior examples assumed that the assets were put in use on January 1st of the year they were bought for use. Therefore, we took a full first year of depreciation expense.

In reality, assets are usually put into use at all times throughout the year. So, we need to prorate the first year’s depreciation expense and adjust the following years’ depreciation expense accordingly.

This is easy to do with straight-line:

JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1.

Normal annual depreciation = \$16,000 / 4 = \$4,000 per year

Year 1 use = 6 months/12 months = ½ year

This is easy to do with straight-line:

JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1.

Normal annual depreciation = \$16,000 / 4 = \$4,000 per year

This is easy to do with straight-line:

JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1.

Normal annual depreciation = \$16,000 / 4 = \$4,000 per year

This is easy to do with straight-line:

JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1.

Normal annual depreciation = \$16,000 / 4 = \$4,000 per year

This is easy to do with straight-line:

JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1.

Normal annual depreciation = \$16,000 / 4 = \$4,000 per year

This is easy to do with straight-line:

JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1.

Normal annual depreciation = \$16,000 / 4 = \$4,000 per year

This is easy to do with straight-line:

JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1.

Normal annual depreciation = \$16,000 / 4 = \$4,000 per year

This is harder to do with accelerated (Sum-of-Year’s Digits or Double-Declining Balance):

The idea for prorating in a partial period asset placement is the same regardless of the method used for accelerated depreciation.

This is harder to do with accelerated (Sum-of-Year’s Digits or Double-Declining Balance):

First, compute normal annual depreciation as if the asset were used the entire year.

Example: JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1. He uses double-declining balance method.

Example: JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1. He uses double-declining balance method.

Example: JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1. He uses double-declining balance method.

Example: JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1. He uses double-declining balance method.

Example: JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1. He uses double-declining balance method.

Since the car was place in service for only ½ the first year, we need to prorate and adjust the depreciation schedule.

We effectively do this by taking ½ the first year’s depreciation, and then rolling the rest of the depreciation schedule forward.

Example: JoePa bought a car for \$20,000, 4 yr. life, \$4,000 salvage value. He started driving the car on July 1. He uses double-declining balance method.

Normal Schedule

½ Use First Year Schedule

First, take ½ of the first year’s normal depreciation.

Normal Schedule

½ Use First Year Schedule

x 1/2

First, take ½ of the first year’s normal depreciation. Then roll forward the second ½ of the first year’s normal depreciation.

Normal Schedule

½ Use First Year Schedule

x 1/2

Then add ½ of the second year’s normal depreciation to the roll forward amount.

Normal Schedule

½ Use First Year Schedule

x 1/2

Then add ½ of the second year’s normal depreciation to the roll forward amount.

Normal Schedule

½ Use First Year Schedule

Then roll forward ½ of the second year’s normal depreciation to the third year schedule.

Normal Schedule

½ Use First Year Schedule

x 1/2

Then add ½ of the third year’s normal depreciation to the roll forward amount.

Normal Schedule

½ Use First Year Schedule

x 1/2

Then add ½ of the third year’s normal depreciation to the roll forward amount.

Normal Schedule

½ Use First Year Schedule

Finally, roll forward ½ of the third year’s normal depreciation to the fourth year schedule.

Normal Schedule

½ Use First Year Schedule

x 1/2

Yr 2

Yr 3

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

Yr 2

Yr 3

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

Yr 2

Yr 3

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$5,000

\$5,000

Yr 1

Yr 2

Yr 2

Yr 3

Yr 3

Yr 4

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$5,000

\$5,000

Yr 1

Yr 2

Yr 2

Yr 3

Yr 3

Yr 4

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$5,000

\$5,000

\$5,000

Yr 1

Yr 2

Yr 2

Yr 3

Yr 3

Yr 4

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$5,000

\$5,000

\$5,000

\$5,000

Yr 1

Yr 2

Yr 2

Yr 3

Yr 3

Yr 4

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$2,500

\$2,500

\$5,000

\$5,000

Yr 1

Yr 2

Yr 2

Yr 3

Yr 3

Yr 4

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$2,500

\$2,500

\$5,000

\$5,000

\$2,500

\$2,500

Yr 1

Yr 2

Yr 2

Yr 3

Yr 3

Yr 4

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$2,500

\$2,500

\$5,000

\$5,000

\$2,500

\$2,500

\$7,500

Yr 1

Yr 2

Yr 2

Yr 3

Yr 3

Yr 4

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$500

\$500

\$5,000

\$7,500

\$2,500

Yr 1

Yr 2

Yr 2

Yr 3

Yr 3

Yr 4

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$500

\$500

\$5,000

\$7,500

\$2,500

\$500

\$500

Yr 1

Yr 2

Yr 2

Yr 3

Yr 3

Yr 4

Yr 4

Partial Period Depreciation

Another way to look at it conceptually is with a timeline.

\$10,000

\$5,000

\$1,000

\$5,000

\$7,500

\$3,000

\$500

• Assume Company A has equipment:

• Original cost of \$120,000

• Accumulated depreciation of \$20,000

• Market value of \$97,000

• Market interest rate of 8%

• Expected cash flows:

• \$24,000 for four years (paid at end of yr.)

Recoverability Test (do we need to record an impairment?)

• Book value = \$120,000 – 20,000 = \$100,000

Orig. Cost

Accum. Depr.

Recoverability Test (do we need to record an impairment?)

• Book value = \$120,000 – 20,000 = \$100,000

• Net future cash flows = \$24,000 x 4 = \$96,000

Not discounted for interest rate

Recoverability Test (do we need to record an impairment?)

• Book value = \$120,000 – 20,000 = \$100,000

• Net future cash flows = \$24,000 x 4 = \$96,000

• NFCF < BV, so we need to record an impairment

Recoverability Test (do we need to record an impairment?)

• Book value = \$120,000 – 20,000 = \$100,000

• Net future cash flows = \$24,000 x 4 = \$96,000

• NFCF < BV, so we need to record an impairment

Amount of Impairment Loss

• Market value is determinable, so use BV – FMV:

• \$100,000 - \$97,000 = \$3,000

Recoverability Test (do we need to record an impairment?)

• Book value = \$120,000 – 20,000 = \$100,000

• Net future cash flows = \$24,000 x 4 = \$96,000

• NFCF < BV, so we need to record an impairment

Amount of Impairment Loss

• Market value is determinable, so use BV – FMV:

• \$100,000 - \$97,000 = \$3,000

3/31 Loss on Impairment 3,000

Accum. Depr, Equipment 3,000

Note: Record impairment to equipment

Recoverability Test (do we need to record an impairment?)

• Book value = \$120,000 – 20,000 = \$100,000

• Net future cash flows = \$24,000 x 4 = \$96,000

• NFCF < BV, so we need to record an impairment

Amount of Impairment Loss

• Market value is determinable, so use BV – FMV:

• \$100,000 - \$97,000 = \$3,000

• If FMV is undeterminable, use BV – Discounted CF

12/31/01

12/31/02

12/31/03

12/31/04

Fixed Asset Impairment Example

Discounted Cash Flows

12/31/01

12/31/02

12/31/03

12/31/04

Fixed Asset Impairment Example

Discounted Cash Flows

\$24,000

\$24,000

\$24,000

\$24,000

12/31/01

12/31/02

12/31/03

12/31/04

1

Each year’s discount rate =

(1 + int rate)year

Fixed Asset Impairment Example

Discounted Cash Flows

\$24,000

\$24,000

\$24,000

\$24,000

12/31/01

12/31/02

12/31/03

12/31/04

x

x

x

x

1

1

1

1

1

Each year’s discount rate =

(1.08)3

(1.08)1

(1.08)2

(1.08)4

(1 + int rate)year

Fixed Asset Impairment Example

Discounted Cash Flows

\$24,000

\$24,000

\$24,000

\$24,000

12/31/01

12/31/02

12/31/03

12/31/04

1

(1.08)1

Fixed Asset Impairment Example

Discounted Cash Flows

\$24,000

\$24,000

\$24,000

\$24,000

x 0.926

x 0.857

x 0.794

x 0.735

12/31/01

12/31/02

12/31/03

12/31/04

Fixed Asset Impairment Example

Discounted Cash Flows

\$24,000

\$24,000

\$24,000

\$24,000

x 0.926

x 0.857

x 0.794

x 0.735

= 22,224

= 20,568

= 19,056

= 17,640

12/31/01

12/31/02

12/31/03

12/31/04

Fixed Asset Impairment Example

Discounted Cash Flows

\$24,000

\$24,000

\$24,000

\$24,000

x 0.926

x 0.857

x 0.794

x 0.735

= 22,224

= 20,568

= 19,056

= 17,640

Net Discounted Cash Flows = 22,224 + 20,568 + 19,056 + 17,640 = \$79,488

12/31/01

12/31/02

12/31/03

12/31/04

Fixed Asset Impairment Example

Discounted Cash Flows

\$24,000

\$24,000

\$24,000

\$24,000

x 0.926

x 0.857

x 0.794

x 0.735

= 22,224

= 20,568

= 19,056

= 17,640

Net Discounted Cash Flows = 22,224 + 20,568 + 19,056 + 17,640 = \$79,488

Note: We can arrive at the same answer by using the Annuity formula:

Present Value of \$1 Annuity

Present Value of \$1 Annuity

12/31/01

12/31/02

12/31/03

12/31/04

Fixed Asset Impairment Example

Discounted Cash Flows

\$24,000

\$24,000

\$24,000

\$24,000

x 0.926

x 0.857

x 0.794

x 0.735

= 22,224

= 20,568

= 19,056

= 17,640

Net Discounted Cash Flows = 22,224 + 20,568 + 19,056 + 17,640 = \$79,488

Note: We can arrive at the same answer by using the Annuity formula:

\$24,000 x 3.312 = \$79,488

Recoverability Test (do we need to record an impairment?)

• Book value = \$120,000 – 20,000 = \$100,000

• Net future cash flows = \$24,000 x 4 = \$96,000

• NFCF < BV, so we need to record an impairment

Amount of Impairment Loss

• Market value is determinable, so use BV – FMV:

• \$100,000 - \$97,000 = \$3,000

• If FMV is undeterminable, use BV – Discounted CF:

• \$100,000 – 79,488 = \$20,512