1 / 10

# Ch 11.4 Dividing Rational Expressions - PowerPoint PPT Presentation

Ch 11.4 Dividing Rational Expressions. Objective: To divide algebraic fractions. Definitions. Rational Expression: A fraction containing a variable. Reciprocal: A fraction “flipped”. The reciprocal of is Divisor: The expression after the division symbol.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about 'Ch 11.4 Dividing Rational Expressions' - keefe

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

### Ch 11.4Dividing Rational Expressions

Objective:

To divide algebraic fractions.

Rational Expression:

A fraction containing a variable.

Reciprocal:

A fraction “flipped”. The reciprocal ofis

Divisor:

The expression after the division symbol.

Also, the denominator (bottom) in a fraction.

Restricted Value:

A number that cannot be a value for the variable. The denominator cannot be 0. A square root cannot be negative.

Multiplying

Dividing

• MultiplyACROSS

• FACTOR

• CANCEL common factors

• Find Restricted values

• RECIPROCATE divisor

• Multiply ACROSS

• FACTOR

• CANCEL common factors

• Find Restricted values

Denominator cannot be 0

Set each denominator unequal to 0 and solve for the variable

This value is Restricted

≠ 0

x – 5

≠ 0

x + 3

≠ 0

x − 1

x ≠ 5

x ≠ -3

x ≠ 1

x + 7

=

=

2x

Restricted values:

x ≠ {0, -1, -5, -7}

=

1

4 vv(5v + 7)

4v

=

=

3 v(5v + 7)

(v − 3)

3(v – 3)

Restricted values:

x ≠ {0, -7/5, 3}

=

1

4 n(n − 9)

4n

=

=

(n + 10)(n − 2)

(n − 9)

(n+10)(n–2)

Restricted values:

x ≠ {0, -10, 2, 9}

=

a + 4

(a − 5)(a − 8)

a + 4

=

=

a − 8

(a − 5)

1

Restricted values:

x ≠{8, 5}

1)

2)

3)

4)

5)

6)

7)

8)