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Lecture 23: Heat. Internal Energy Heat Specific Heat Latent Heat Phase Diagrams. Internal Energy. Energy of all molecules including: Random motion of individual molecules <K tr > = 3/2 k T for ideal gas Vibrational energy of molecules and atoms
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Lecture 23:Heat • Internal Energy • Heat • Specific Heat • Latent Heat • Phase Diagrams
Internal Energy • Energy of all molecules including: • Random motion of individual molecules • <Ktr> = 3/2 k T for ideal gas • Vibrational energy of molecules and atoms • Chemical energy in bonds and interactions • DOES NOT INCLUDE • Macroscopic motion of object • Potential energy due to interactions w/ other objects
Heat • Definition: Flow of energy between two objects due to difference in temperature • Note: similar to WORK • Object does not “have” heat (it has energy) • Units: calorie • Amount of heat needed to raise 1g of water 1ºC • 1 Calorie = 1000 calories = 4186 Joules
Specific Heat • Heat adds energy to object/system. • If system does NO work then: • Heat increases internal energy.Q = DU • Heat increases temperature! • Heat required to increase temperature depends on amount of material (m) and type of material (c). • Q = c m DT • Q = heat • c = specific heat • m = mass • DT = change in temperature
Specific Heat: Ideal Gases • Monatomic Gas (single atom): • All energy is translational kinetic energy. • At constant volume, work = 0. • Q = DKtr = 3/2 nRDT • CV = 3/2 R = 12.5 J/(K mole) • Diatomic Gas (two atoms): • Also have rotational energy. • CV = 5/2 R = 20.8 J/(K mole)
steam: temp rises water changesto steam(boils) water: temp rises T 100oC Latent Heat Q added to water Latent Heat • As you add heat to water, the temperature increases for a while, then it remains constant, despite the additional heat! • Q = m L • Latent Heat: L [J/kg] is heat which must be added (or removed) for material to change phase (solid-liquid or liquid-gas).
Summary • Heat is FLOW of energy • Heat will increase internal energy. • Specific Heat • Q = c m Dt • Monatomic IDEAL Gas: CV = 3/2 R • Diatomic IDEAL Gas: CV = 5/2 R • Latent Heat • Heat associated with change in phase • Q = m L
Example • How much heat is needed to change 1.8 grams of ice at -10ºC to steam at 100ºC? • cice = 2.100 J/g/ºC • cwater = 4.186 J/g/ºC • Lfusion = 333.7 J/g • Lvaporization = 2256 J/g We will need to use both equations for this problem: Q = c m Tto raise the temperature of the ice from -10ºC to 0ºC Q = m Lto melt the ice to water Q = c m Tto raise the temperature of the water from 0ºC to 100ºC Q = m Lto boil the water to steam
Example • How much heat is needed to change 1.8 grams of ice at -10ºC to steam at 100ºC? • cice = 2.100 J/g/ºC • cwater = 4.186 J/g/ºC • Lfusion = 333.7 J/g • Lvaporization = 2256 J/g Set up an expression for the total heat needed: Q = cice m Tice + m Lfusion + cwater m Twater + m Lvaporization Solve for the total heat needed: Q = 37.8 J + 600.66 J + 753.48 J + 4060.8 J = 5452.74 J