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EXAMPLE 5

Standardized Test Practice. EXAMPLE 5. SOLUTION. The lateral surface area of a cylinder is equal to the area of its curved surface. This surface becomes a rectangle in the net of the cylinder, with length equal to the circumference of the base. ANSWER.

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EXAMPLE 5

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  1. Standardized Test Practice EXAMPLE 5 SOLUTION The lateral surface area of a cylinder is equal to the area of its curved surface. This surface becomes a rectangle in the net of the cylinder, with length equal to the circumference of the base.

  2. ANSWER The lateral surface area of the container is about 955 cm2. The correct answer is C. Standardized Test Practice EXAMPLE 5 =2πrh Lateral surface area Multiply circumference and height. = 2π(8)(19) Substitute 8 for rand 19 for h. ≈ 955.04 Evaluate using a calculator.

  3. ANSWER The lateral surface area of the container is about 314 in.2 for Example 5 GUIDED PRACTICE 4. What If? Suppose the radius of the cylinder in Example 5 is 5 inches and the height is 10 inches. Approximate the lateral surface area.

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