Ncert Solutions For Class 10 Maths

1. If you are looking NCERT Solutions for Class 10 Maths error free and prepared by experienced mentors. Don’t WORRY!! Here we are providing Free PDF you can get easy with a single click. SUMMARY 1 1 tan? = cos? = sin? = We also observe that cot? ⇒ cot? = tan? 1 1 sec? ⇒ sec? = cos? 1 1 cosec? ⇒ cosec? = sin? tan? = ??? ? Trigonometric table: Trigonometric Identities: (i) sin2θ + cos2θ = 1 (ii) 1 + tan2θ = sec2θ (iii) 1 + cot2θ = cosec2θ Trigonometric ratios of complementary angles: Sin (900- θ) = cos θ cos (900- θ) = sin θ Tan (900- θ) = cot θ Cot (900- θ) = tan θ Sec (900- θ) = cosec θ Cosec (900- θ) = sec θ OBJECTIVE 1.If 5tan θ = 4, then value of 5sinθ−3 cosθ a)1 cot? = cos? cos? and sin? 5 ???θ+3 cosθ is : 6 ?)4 3 ?)1 5 ?)2 3 HURRY!! Visit our portal and get your NCERT Solutions UPDATED 2021-22. These all very essential for your exam preparation

2. If you are looking NCERT Solutions for Class 10 Maths error free and prepared by experienced mentors. Don’t WORRY!! Here we are providing Free PDF you can get easy with a single click. 2.Given 3sin β + 5cos β = 5, then the value of (3cos β- 5sin β)2 is equal to: a) 9 ?)9 5 ?)1 3 ?)1 9 tanθ 3. If tan θ= 4, then ( ????+????????) is equal to: ???3? 4. As x increases from 0 to ? a) Increases b) decreases c) remains constant d) increases, then decreases 5. Value of x from the equation xsin? ?????2? a) 4 b) 6 6. The area of a triangle is 12 sq. cm. Two sides are 6 cm and 12 cm. The included angle is : a) cos−1(1 b) cos−1(1 7. If α + β = 900and α = 2β, then cos2? + sin2β equals to: a) 1 b) 0 SUBJECTIVE 1. If A + B = 900, prove that: a) 0 ?)2√2 ?)√2 ?)1 2, the value of cos x : ???2? 6???? 4?????? 3???? 6cos2? 4 = 4 6 is : c) -2 d) 0 c) sin−1(1 d) sin−1(1 3) 6) 6) 3) 2 c) 1 d) 2 ???2? ???2? = tan? √????????+???????? ???????? − Prove the following (Q 2 to Q5) 2. 3. 4. (???8? − ???8?) = (???2? − ???2?)( 1 − ???2????2?) 5. 6. If x = r sin θ cos φ, y = r sin θ sin φ, z = r cos θ, then prove that: x2+y2+z2=r2. 7. Prove that: ????−????− 8. ???? 1−???? + ???? 1−???? = sec??????? + 1 ????+???? ????−???? + ????−???? 2 2 ????+???? = ???2?−???2? = 1−2???2? ????+????−1 ????−????+1 = 1+???? ???? 1 1 1 1 ????+???? ????= ????− Evaluate: tan 70 tan 230 tan 600 tan 670 tan 830 + cot540 tan 360 + sin 200 sec 700- 2 HURRY!! Visit our portal and get your NCERT Solutions UPDATED 2021-22. These all very essential for your exam preparation

3. If you are looking NCERT Solutions for Class 10 Maths error free and prepared by experienced mentors. Don’t WORRY!! Here we are providing Free PDF you can get easy with a single click. 9. 10. 11. 12. Answers: Objective: Subjective: 8)√3 Evaluate: 2 3cosec2580 - 2 3cot 580tan 320 - 5 3tan 130 tan 370 tan 450 tan 530 tan 770. If 5x = sec θ and 5 1 ?= tanθ, find the value of 5(?2− ?2). Find the value of sec 600 geometrically. Prove the following: sin A(1 + tan A) + cos A(1 + cot A) = sec A + cosec A. 1) b 2) a 3) d 4) b 5) b 6) d 7) a 10) 1 9)-1 5 11) 2 HURRY!! Visit our portal and get your NCERT Solutions UPDATED 2021-22. These all very essential for your exam preparation