Force Review

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# Force Review - PowerPoint PPT Presentation

Force Review. Four Fundamental Forces Nature. Gravity Electromagnetic Strong Nuclear Weak Nuclear. Common forces. Gravity – weight, attraction between masses. Friction - surfaces, air/wind resistance Elastic/Strain/Tension – deformation of shape.

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## PowerPoint Slideshow about 'Force Review' - jillian-bond

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Presentation Transcript
Four Fundamental Forces Nature
• Gravity
• Electromagnetic
• Strong Nuclear
• Weak Nuclear
Common forces
• Gravity – weight, attraction between masses.
• Friction - surfaces, air/wind resistance
• Elastic/Strain/Tension – deformation of shape.
• Electric – attraction / repulsion charges q.
• Magnetic - attraction / repulsion magnetic poles.
• Normal – reaction force perpendicular to surfaces.

Forces Review

Newton’s 1st Law (Inertia)

• Balanced F = Equilibrium: Fnet = 0 constant v, or v = 0.
• Translational Equilibrium – all F in all directions balanced.
• Vertical equilibrium - upward & downward forces are balanced.
• Horizontal equilibrium, left & right forces balanced.
• Inertia is a property of matter directly proportional to mass. Measure of resistance to acceleration.
Fnet ≠ 0 (Newton 2)
• Unbalanced forces cause acceleration in the direction of Fnet.
• a = Fnet/m
• accelerationrate change in velocity directly proportional to Fnet, inversely proportional to mass.
Newton 3: Action Reactions Pairs
• F a,b = - F b,a .
• IB - action/ reaction pairs.
• IB: Normal Force Fn = Reaction Force, R.
Know Newton’s 3 laws of motion
• Inertia
• Acceleration a =Fnet/m
• Action/Reaction –

Forces in pairs.

Fa,b = -F b,a.

Sketch Free Body Diagrams
• Show all forces, (relative or scaled) magnitudes, directions acting on a body. Identifies direction/mag of Fnet.
• No other arrows except forces.
Define
• Translational Equilibrium: linear forces balanced
• Balanced Forces – no linear acceleration.
Be able to:
• Identify action/reaction pairs.
• Solve problems in net force/ acceleration.
• RememberFnet = S Forces = ma.
• Can write & state

S Forces = ma = F1 + F2 + F3…

Force Vectors
• 1. The 25-kg sign (Joe’s) is suspended by two cables: A and B.
• Sketch a free body diagram.
• Find the tension in each cable.
30o.

Ta.

Tb.

• Tb = 144-N
• Ta = 289-N

Fg = 250 N

Using Fnet = S F = ma
• Inclined Plane.
• Elevator
• Horizontal Pulley
• Connected masses.
• Atwood’s machine.
Inclined Plane

2. The 5-kg box above is pushed up a 20o incline at constant speed.

• Sketch the free body diagram.
• Calculate the pushing force if m, the coefficient of friction is 0.49. Remember Ff = mFn.
• Sketch the free body diagram.
• Designate the downhill direction as positive.
• Write the equation of Fnet.
• Calculate m.

Sketch free body on man in elevator.

• Write the equation for Fnet.
• Fnet = SF = F1 + F2 …ma = F1 + F2 …
• What will the scale read when the elevator:
• Goes up at constant velocity.
• Accelerates up at 2 m/s2.
• Accelerates down at -3 m/s2.
• Accelerates down at -10 m/s2.

a) at constant velocity, a = 0 ma = 0

• SF = 0 so 0 = Fn – mg
• mg = Fn
• Fn ~ (100kg) (10 m/s2) 1000 N

He feels the same

b) ma = Fn - mg for a =2 m/s2.

(100 kg)(2m/s2) + (1000 N) = 1200 N

He feels heavier.

c) ma = Fn - mg

• (100kg)(-3m/s2) + (100)(10 m/s2) = 700 N
• He feels lighter.

d) ma = Fn - mg

• ma + mg = Fn
• 100 kg (-10 + 10) m/s2
• Fn = 0 He feels weightless!
• He is in freefall.
Read Hamper 2.2Problems in Force #1-4.
• Problem Sheet “Problems in Force 2” Sketch all free body diagrams with that.
• Do pg 29 #5, 6.
Linear Momentum
• Product mass x velocity
• Property of object moving in straight line
• p = mDv
• Vector quantity that is conserved.
• Don’t forget to include sign for velocity when calculating.
• S pbefore = S pafter.
• Impulse = Dp. Relates Force to momentum.

Momentum Change &Newton’s 2nd Law

• F = ma
• F = mDv
• Dt
• FDt =mDv m (vf - vi) for const mass.
• FDt = Dp
• Dp = Change in momentum

force - t graph:Dp Impulse is area under curve

For constant force = FDt.

Force N

Non-Constant ForceForce vs. time graph. The area under the curve = impulse or Dp change in momentum.

### Impulse involves timeWork involves distance!

Work = Fd cos q.

The force must be parallel to the distance moved (0o or 180o)

### Work: force x distance moved in direction of force. W = F cos q.

For varying force = area under curve on F vs. d graph.

Work is a scalar measured in Joules.
• Work done on an object causes changes in energy in by the amount of work done.
• Ex: if 300 Joules of work is done stopping a moving object, 300 J of KE was converted to thermal E, and sound.

A grenade is launched into the air and explodes into hundreds of pieces at the top of its arc. How does the total KE and total momentum compare just before and just after the explosion?

• KE more, less, the same.
• Momentum more, less, the same.

Positive & Negative Work

• Work can be pos, 0, neg depending on q:

If 0° ≤ q < 90° cosq= + W is positive .

If a = 90° cosq = 0 W is 0.

If 90° < q ≤ 180° cosq is neg W is neg.

Types of Energy

Non- Mechanical

Mechanical

• KE
• PEg
• PE elas
• Heat
• Light
• Sound
• Nuclear
• Chemical
• Electro-magnetic.
Conservation of Energy
• Holds true for all energy but – KE not conserved necessary…. E can be converted to other types.
• Momentum is a single quantity. It must be conserved!!
• To find final velocity don’t assume KE is conserved unless a collision is elastic.
We can relate KE to momentum
• See text for derivation.

Power = rate work gets done/E transformed.The kWh is a unit of energy equivalent to1 kW of power expended for 1 h of time.Use 1000 watts for 1 hour, that's a kilowatt-hour.

• kWh are units of energy.
• 1000 J/s (1 h) (3600 s/h) = 3.6 x 106 J
Efficiency is ratio of amount of work, Energy, power we get out compared to amount put in.

Often expressed as %.

Ex: A car engine has eff of 20% and produces 25 kJ of useful work/sec. How much energy is converted to heat per sec?