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Spanning Trees

Spanning Trees. Longin Jan Latecki Temple University based on slides by David Matuszek, UPenn, Rose Hoberman, CMU, Bing Liu, U. of Illinois, Boting Yang, U. of Regina. A connected, undirected graph. Four of the spanning trees of the graph. Spanning trees.

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Spanning Trees

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  1. Spanning Trees Longin Jan Latecki Temple University based on slides by David Matuszek, UPenn, Rose Hoberman, CMU, Bing Liu, U. of Illinois, Boting Yang, U. of Regina

  2. A connected,undirected graph Four of the spanning trees of the graph Spanning trees • Suppose you have a connected undirected graph • Connected: every node is reachable from every other node • Undirected: edges do not have an associated direction • ...then a spanning tree of the graph is a connected subgraph with the same nodes in which there are no cycles

  3. Theorem • A simple graph is connected iff it has a spanning tree. Proof. We assume that a graph G is connected. If G has a simple circuit, we remove one edge from it. We repeat this step, until there is no more circuits in G. Let T be the obtained subgraph. T has the same nodes as G, since we did not remove any node. T has no circuits, since we removed all circuits. T is connected, since in every circuit there was an alternative path. The proof in the opposite direction is very simple. Since the presented algorithm to construct a spanning tree is very inefficient, we need a better one.

  4. One possible result of a BFSstarting from top An undirected graph One possible result of a DFSstarting from top Finding a spanning tree • To find a spanning tree of a graph, • pick an initial node and call it part of the spanning tree • do a search from the initial node: • each time you find a node that is not in the spanning tree, add to the spanning tree both the new node and the edge you followed to get to it

  5. Graph Traversal Algorithm • To traverse a tree, we use tree traversal algorithms like pre-order, in-order, and post-order to visit all the nodes in a tree • Similarly, graph traversal algorithm tries to visit all the nodes it can reach. • If a graph is disconnected, a graph traversal that begins at a node v will visit only a subset of nodes, that is, the connected component containing v.

  6. Two basic traversal algorithms • Two basic graph traversal algorithms: • Depth-first-search (DFS), also called backtracking • After visiting node v, DFS proceeds along a path from v as deeply into the graph as possible before backing up • Breadth-first-search (BFS) • After visit node v, BFS visits every node adjacent to v before visiting any other nodes

  7. Depth-first search (DFS) • DFS strategy looks similar to pre-order. From a given node v, it first visits itself. Then, recursively visit its unvisited neighbors one by one. • DFS can be defined recursively as follows. procedure DSF(G: connected graph with vertices v1, v2, …, vn) T:=tree consisting only of the vertex v1 visit(v1) mark v1 as visited; procedure visit(v: vertex of G) for each node w adjacent to v not yet in T begin add vertex w and edge {v, w} to T visit(w); mark w as visited; end

  8. DFS example • Start from v3 1 v3 2 v2 v2 v3 v1 x x x 4 3 v1 x v4 x v5 v4 5 v5 G

  9. Breadth-first search (BFS) • BFS strategy looks similar to level-order. From a given node v, it first visits itself. Then, it visits every node adjacent to v before visiting any other nodes. • 1. Visit v • 2. Visit all v’s neighbors • 3. Visit all v’s neighbors’ neighbors • … • Similar to level-order, BFS is based on a queue.

  10. Algorithm for BFS procedure BFS(G: connected graph with vertices v1, v2, …, vn) T:= tree consisting only of vertex v1 L:= empty list put v1 in the list L of unprocessed vertices; while L is not empty begin remove the first vertex v from L for each neighbor w of v if w is not in L and not in T then begin add w to the end of the list L add w and edge {v, w} to T end end

  11. v2 v3 v1 x x 2 3 v3 x v4 x 4 5 v4 v2 v1 v5 G BFS example • Start from v5 1 v5 x

  12. Backtracking Applications • Use backtracking to find a subset of{31, 27, 15, 11, 7, 5}with sum equal to 39.

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