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Diffusion in 2 Energy Groups. B. Rouben McMaster University Course EP 6D03 – Nuclear Reactor Analysis (Reactor Physics) 2009 Jan.-Apr. Contents.
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Diffusion in 2 Energy Groups B. Rouben McMaster University Course EP 6D03 – Nuclear Reactor Analysis (Reactor Physics) 2009 Jan.-Apr.
Contents • We study the diffusion equation in two energy groups of neutrons, which is the methodology most often used for full-core diffusion calculations (but not for lattice calculations). • We treat first the infinite lattice, then move on to the finite reactor.
The Diffusion Equation in 2 Groups • In multigroup theory it is conventional to number groups from the highest energy range to the lowest energy range. • Following this convention, in the 2-group model: • Group 1 is the “fast” (or “slowing-down”) group • Group 2 is the “thermal” group • The energy boundary separating the 2 groups is typically taken as 0.625 eV. • Subscripts 1 and 2 refer to groups 1 and 2 respectively, e.g., we will have quantities 1, 2,a1, a2, D1, D2, etc. cont’d
The Diffusion Equation in 2 Groups • For now we will make the following simplifying assumptions: • All fission neutrons are born in the fast group • All fissions are lumped as if created by the thermal group, i.e. we have a quantity f2, but no f1 (i.e., f2 is assumed to be renormalized to account for the few percent of fast fissions) • We also have a “downscattering” or “moderation” (i.e., group-1-to-group-2) cross section, which we shall denote 12, but we make the assumption that “upscattering” is negligible, i.e. we take 21 0, and ignore it.
The Equation for the Infinite Lattice • As we did in the 1-group treatment, we will start the discussion with the infinite lattice, for which there are no leakage terms. • With the simplifying assumptions in the previous slide, then, the time-independent diffusion equation for the infinite lattice in 2 groups is: • Eq. (1) [a set of 2 equations] expresses the neutron balance: the absorption (loss) terms are balanced by the production terms, in each energy group. cont’d
Infinite-Lattice Equation (cont’d) • However, this is a set of 2 homogeneous linear equations in 2 unknowns. Just as in the 1-group case, there is not always a non-trivial solution! • In order that there be a non-trivial solution, the determinant of the equation set has to be 0, i.e. • However, we cannot expect this to be the case in general: physically speaking, we cannot throw together just any kind of material and expect it to constitute a static reactor (except one with 0 neutron flux everywhere)! cont’d
Infinite-Lattice Equation (cont’d) • Therefore, in order to ensure a solution, we divide f2 by an adjustable factor k, which will represent the infinite-lattice’s multiplication constant. • The equation set then becomes: • The criticality criterion then becomes: cont’d
Infinite-Lattice Equation (cont’d) • i.e., • Eq. (5) can be interpreted according to the neutron cycle (in the same way as we derived the 4-factor formula) as follows: • Suppose Nfast neutrons are born from thermal fissions • These neutrons can be absorbed or be moderated (downscattered to the thermal group). The number which succeed in being moderated is given by the ratio • These surviving neutrons will be absorbed according to cross section a2, but some of these absorptions (if in fuel) will result in fissions and new numbers of neutrons, according to the yield cross section f2. • The ratio of number of neutrons in successive generations is then seen to be exactly k, as given by Eq. (5).
Infinite-Lattice Equation (cont’d) • In summary: In the 2-group formalism, the infinite-lattice multiplication constant is given by • which is to be compared to the 1-group result • It is easy to see that the ratio is really the resonance escape probability p, since it is the fraction of fast neutrons which survive to moderation: cont’d
Infinite-Lattice Equation (cont’d) • Then, by comparing the rewritten Eq. (5) with the 4-factor formula: (7) we see that we must have (8) • This is actually easy to understand: If we move a2 to the right-hand side of Eq. (8), then we see that the total neutron production (f2) is equal to thermal absortions (a2) times the ratio of thermal absorptions which occur in the fuel(f) times thenumber of fission neutrons born per thermal absorptionin fuel () times the fas-fission factor () [Remember that in our casewe have from the start included fast fissions in f2.] • Therefore we have a consistent and understandable result!
Equation in Operator Form • Note that our original 2-group equation for the infinite lattice, Eq. (1), can be written in matrix form as: • This can be rewritten in operator form as:
Equation in Operator Form (cont’d) • With the introduction of keff to ensure a non-trivial solution, the final equation can be written in more conventional eigenvalue-problem form as • Note that if we integrate Eq. (14), we get as we had shown previously
Interactive Discussion/Exercise • If we remove the simplifications of assuming that: 1) fast fissions are included in thermal fissions, and 2) there is no upscattering, write the equation for the absorption and scattering operator M and for the fission-source operator F for the infinite lattice. • Note: The advantage of the operator notation is that the basic equation (14) will be the same no matter what exact model we use, i.e., M and F may include different things, but the equation remains the same.
Include Fast Fission & Upscattering The operators in the more general case:
The Finite Reactor • We now move to the case of the finite homogeneous reactor, and for now retain the simplifying assumptions we had assumed for the infinite lattice • For the finite lattice, we will have to change k to keff and add the leakage terms. • The leakage out of the reactor in each group is • (This must be a positive number for each group – why?) cont’d
Finite-Reactor Equation in 2 Groups • The equation for the finite homogeneous reactor, with leakage, is: • [Note: This has to be understood as applying at every point in the reactor.] • As we did in the one-energy-group formalism, let’s write the term as DB2 for each group, with the same buckling (B2) in the 2 groups. [This means that the flux has the same shape in the two groups.]
Criticality Criterion for Finite Reactor in 2 Groups • The criterion for having a non-trivial solution to this set of homogeneous equations is (as usual) that the determinant have a zero value: • This reduces to
Significance of keff • The significance of Eq. (19) is that the expression on the right-hand side of Eq. (19), which is an expression in the values of the material properties of the reactor, must have the value 1 if the reactor is to be critical (and allowed, therefore, to be a time-independent reactor). • If the right-hand side of Eq. (19) is not zero, then he properties of the reactor do not allow a time-independent solution. However, keff tells us how far off we are, and it also tells us that if we change the reactor to have a fission cross section f2/keff, then that reactor will be critical.
Criticality Criterion for Finite Reactor in 2 Groups • If we make use of the following definitions for the thermal diffusion area and the fast diffusion area [or neutron age ] we get for the criticality criterion
Relationship Between k and keff • If we compare this to the criticality criterion for the infinite lattice, which we obtained previously: • we see that we have the relationship • This is an important relationship, and can be interpreted as follows. • Since the physical difference between kand keff is the leakage, we can identify the factors linking them:
6-factor formula for keff • The factor represents the non-leakage probability of thermal neutrons from the reactor. • Similarly, the factor represents the non-leakage probability of “fast” (group-1) neutrons. • i.e., the relationship betweenkand keff becomes • Incidentally, if we substitute into Eq. (26) the 4-factor formula for k: • we get the 6-factor formula for keff : another important formula
Summary for 2-Group Model • The criticality criterion in 2 energy groups for a finite homogeneous reactor relates the buckling B2 to the material properties: • Regarding the flux shape in the reactor, this is given (for both groups) by the same eigenvalue equation as before: except that in 2 groups the value of the geometrical buckling B2 must be related to the material properties as per Eq. (21). (cont’d)
Interactive Discussion/Exercise • Derive the relative amplitudes of the fast and thermal fluxes.
Relative Amplitudes of Fluxes The operators in the more general case: Either Eq. (3b) or, just as easily, Eq. (3a), can be used to relate the fluxes as above.
Modified 1-Group Criticality Criterion • A modified, approximate criticality criterion is sometimes invoked, by starting from the 2-group criterion, Eq. (21), and neglecting the terms which would involve B2*B2 (since the leakage terms are usually small – a few % - in real reactors, this approximation is usually valid): where is called the migration area.
Another Exercise • For the finite homogeneous reactor in 3 groups: • write the equations for and the operators M and F,if: • all fission neutrons are born in the fast group, but from fissions in any group, and • there is scattering from any group to any other group.
Interactive Discussion/Exercise • The usual mathematical intervention (which has been used above) for ensuring that the reactor equation has a solution, is to include an eigenvalue, (= 1/keff), in front of the yield operator F. • Relate/contrast this intervention with the physical, concrete steps which are or can be used to ensure criticality of real reactors.