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Adsorption Characterization of porous materials Part 3 PowerPoint Presentation
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Adsorption Characterization of porous materials Part 3

Adsorption Characterization of porous materials Part 3

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Adsorption Characterization of porous materials Part 3

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  1. European Master Adsorption Characterization of porous materials Part 3 Bogdan Kuchta Laboratoire MADIREL Université Aix-Marseille

  2. m Basis of the specific surface measurements by adsorption = quantity required to cover 1 gram of adsorbent with one layer m = surface occupied by one molecule Specific surface For N2 at 77,35 K m = 0,162 nm2 Is the gas volume (STP) adsorbed required tobuildone layer on 1 gram of adsorbent where

  3. Structure of adsorbed molecules Hypothesis * molecules are modeled by spheres with radius r each of them occupies a surface m on a solid totally covered with 1 layer * the layer is supposed to be: - compact (hexagonal dense arrangement) - liquid (corresponding to density l at temperature of adsorption) Calculations NA is the Avogadro constant M is the molecular mass adsorbate Numerical applications :N2 at 77,35 K m = 0,162 nm2 H2O at 300 K m = 0,105 nm2

  4. Application of BET model:example : alumina NPL / N2 / 77 K

  5. Application of BET model:example : alumina NPL / N2 / 77 K

  6. Application of BET model:example : alumina NPL / N2 / 77 K Slope : Coordinate :

  7. Application of BET model:example : alumina NPL / N2 / 77 K

  8. + p/p° + Hypothesis  C >> 1  coordinate = 0 «Method of 1 point» for fast determination of the specific surface This method is recommended only for fast estimations.

  9. Application of BET model:example : alumina NPL / N2 / 77 K

  10. Comments on BET model applications • This method may be applied when the isotherm of adsorption of the type II is observed at 77 K when nitrogen is the adsorbed gaz. • 2. It is also possible to use it with isotherms of the type IV id the capillary condensation is not observed up to the relative pressure 0.35.