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Review of Chemistry 11

Review of Chemistry 11. Prior Knowledge Needed for Chemistry 12. Naming molecules and writing formulas Balancing Chemical Equations Counting Significant figures Calculating with significant figures Mole calculations Basic Stoichiometry. Naming Molecules and Writing Formulas.

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Review of Chemistry 11

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  1. Review of Chemistry 11

  2. Prior Knowledge Needed for Chemistry 12 • Naming molecules and writing formulas • Balancing Chemical Equations • Counting Significant figures • Calculating with significant figures • Mole calculations • Basic Stoichiometry

  3. Naming Molecules and Writing Formulas

  4. What do you remember? Categorize the following according to what elements are involved and the types of intramolecular bonds: HCl, NaCl, CO2, Cu(ClO) 2, CaO, HF, Ca(OH) 2, HIO3, Sr(NO3) 2, Pb(NO3) 2, AgNO3, KBr, NaOH, N2O3, FeO, CH3COOH,

  5. Analyze each pair (name = formula) and come up with some rules… Hyroiodic Acid = HI Nitrous Acid = HNO2 Nitric Acid = HNO3

  6. Copper(II) nitride = Cu(NO3)2 Sodium phosphate = Na2PO4 Gold(II) oxide = AuO

  7. Sulphur diflouride = SF2 Dinitrogen trioxide = N2O3

  8. Balancing Chemical Equations “BCE”

  9. Why?

  10. General Guidelines • Balance any polyatomic ions first • Balance metals • Balance nonmetals • Balance “O” and “H” last • Recount both sides to make sure!!

  11. Al + O2 Al2O3

  12. C2H6 + O2 CO2 + H2O

  13. Counting Significant figures

  14. Answers… 100 = 1 0.001 = 1 0.010 = 2 10.04 = 4 1.0 x 102 = 2 197 = 3 0.0000200910 = 6 100.20 = 5 10.0 = 3 1090 = 3

  15. What are the general rules for what zero’s are significant?

  16. Calculating with Significant Figures

  17. Answers… Adding and Subtracting… 10.00 + 2.0 = 12.0 36.98 – 0.0013= 36.98 General Rule?

  18. Answers… Multiplying and Dividing… 190 / 3 = 60 1403 / 7.0 = 2.0 x 102 0.09700 x 1.2 = 0.12 General Rule?

  19. Mole Calculations

  20. Answer… How many grams of NaCl are in 4.50 moles of NaCl? # g NaCl = 4.50 mol x 58.5 g = 263 g NaCl 1 mol What steps were used to answer this question?

  21. Answer… How many moles of NH4Br are in 15.87 g of NH4Br? # mol NH4Br= 15.87g x 1 mol =0.162 mol NH4Br 97.9 g What steps were used to answer this question?

  22. General Rules…

  23. Basic Stoichiometry

  24. Answers… Given the following balanced equation, answer the questions following it: 9Na + 4ZnI2 8NaI + NaZn4 a.) If 2.50 moles of Na are reacted, how many moles of ZnI2 will be consumed? # mol ZnI2 = 2.50 mol Na x 4 mol ZnI2 = 1.11 mol ZnI2 9 mol Na b.) If you completely react 526.68 g of ZnI2, what mass of NaZn4 will be produced? # g NaZn4 = 526.68g of ZnI2x 1 mol ZnI2 x 1 mol NaZn4 x 284.6g NaZn4 = 117.4g NaZn4 319.2 g ZnI2 4 mol ZnI2 1 mol NaZn4

  25. What steps were taken to answer these questions?

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