Review for Test 5. Gas Laws. Charles Law V 1 = V 2 P constant T 1 T 2 Boyles Law P 1 V 1 = P 2 V 2 T constant Gay-Lussac’s Law P 1 = P 2 V constant T 1 T 2 Combined P 1 V 1 = P 2 V 2
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Boyles Law P1V1 = P2V2 T constant
Gay-Lussac’s Law P1=P2 V constant
Ideal Gas Law PV = nRT
The sum of the individual gas pressures equals the overall pressure of the mixture of gases.
P1 + P2 + P3 . . . = Ptotal
What volume would it take up at 502K?
Volume should increase!
2.97L x 502K = 4.32 L
A gas-filled bottle is heated from 25°C to 89°C. If the original pressure was 760 torr, what would be the new pressure ?
T1 = 25+273=298K
T2 = 89+273=362K
760 = P2
P2 = 923 torr
A gas at 98.2 kPa has a volume of 39L. What is its volume at 120.5kPa and constant temperature?
P1V1 = P2V2
Volume should decrease.
39L x 98.2 kPa = 31.8L
At STP, the volume of a gas is 325 mL. What volume does it occupy at 20.0°C and 93.3kPa?
325 mL x 293K x 101.3 kPa = 379 mL
273K 93.3 kPa
What pressure is exerted by .00306 mole of gas in a 25.9 cm3 container at 9˚C?
= .00306mol x 8.31 L∙kPa x 282K
.0259 L mol∙K
A 35.0L tank contains 7.00 mol of compressed air. If the pressure inside the tank is 500.0 kPa, what is the temperature of the compressed gas?
T = PV
T = 500.0kPa x 35.0L
7.00mol x 8.31
= 301 K
A gaseous mixture containing argon, nitrogen, and oxygen is in a vessel. If the total pressure is 98.5 kPa, and the partial pressures of nitrogen and argon are 22.0 kPa and 50.0 kPa respectively, what is the partial pressure of oxygen?
Ptot = PAr + PN + PO
98.5 kPa = 22.0 + 50.0 + Po
PO = 26.5 kPa